/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO We split firstr-order part and higher-order part, and do modular checking by a general modularity. ******** FO SN check ******** Check non-SN using NTI (Non-Termination Inference by Payet) ******** Computation rules ******** (1) f(X,c(X),c(Y)) => f(Y,Y,f(Y,X,Y)) (2) f(s(U),V,W) => f(U,s(c(V)),c(W)) (3) f(c(P),P,X1) => c(X1) (4) g(Y1,U1) => Y1 (5) g(V1,W1) => W1 backward process killed -- 548 rule(s) generated forward+backward process killed -- 425 rule(s) generated NO let R be the TRS under consideration f(_1,c(_1),c(_2)) -> f(_2,_2,f(_2,_1,_2)) is in elim_R(R) let r0 be the right-hand side of this rule p0 = 0 is a position in r0 we have r0|p0 = _2 g(_3,_4) -> _3 is in R let l'0 be the left-hand side of this rule theta0 = {_2/g(_3,_4)} is a mgu of r0|p0 and l'0 ==> f(_1,c(_1),c(g(_2,_3))) -> f(_2,g(_2,_3),f(g(_2,_3),_1,g(_2,_3))) is in EU_R^1 let r1 be the right-hand side of this rule p1 = 1 is a position in r1 we have r1|p1 = g(_2,_3) g(_4,_5) -> _5 is in R let l'1 be the left-hand side of this rule theta1 = {_2/_4, _3/_5} is a mgu of r1|p1 and l'1 ==> f(_1,c(_1),c(g(_2,_3))) -> f(_2,_3,f(g(_2,_3),_1,g(_2,_3))) is in EU_R^2 let r2 be the right-hand side of this rule p2 = 2.0 is a position in r2 we have r2|p2 = g(_2,_3) g(_4,_5) -> _5 is in R let l'2 be the left-hand side of this rule theta2 = {_2/_4, _3/_5} is a mgu of r2|p2 and l'2 ==> f(_1,c(_1),c(g(_2,_3))) -> f(_2,_3,f(_3,_1,g(_2,_3))) is in EU_R^3 let r3 be the right-hand side of this rule p3 = 2 is a position in r3 we have r3|p3 = f(_3,_1,g(_2,_3)) f(c(_4),_4,_5) -> c(_5) is in R let l'3 be the left-hand side of this rule theta3 = {_1/_4, _3/c(_4), _5/g(_2,c(_4))} is a mgu of r3|p3 and l'3 ==> f(_1,c(_1),c(g(_2,c(_1)))) -> f(_2,c(_1),c(g(_2,c(_1)))) is in EU_R^4 let l be the left-hand side and r be the right-hand side of this rule let p = epsilon let theta = {_1/_2} let theta' = {} we have r|p = f(_2,c(_1),c(g(_2,c(_1)))) and theta'(theta(l)) = theta(r|p) so, theta(l) = f(_2,c(_2),c(g(_2,c(_2)))) is non-terminating w.r.t. R Termination disproved by the forward process proof stopped at iteration i=4, depth k=3 241 rule(s) generated >>NO ******** Signature ******** c : a -> a cons : (d,e) -> e f : (a,a,a) -> a false : c filter : ((d -> c),e) -> e filter2 : (c,(d -> c),d,e) -> e g : (b,b) -> b map : ((d -> d),e) -> e nil : e s : a -> a true : c ******** Computation Rules ******** (1) f(X,c(X),c(Y)) => f(Y,Y,f(Y,X,Y)) (2) f(s(U),V,W) => f(U,s(c(V)),c(W)) (3) f(c(P),P,X1) => c(X1) (4) g(Y1,U1) => Y1 (5) g(V1,W1) => W1 (6) map(J1,nil) => nil (7) map(F2,cons(Y2,U2)) => cons(F2[Y2],map(F2,U2)) (8) filter(H2,nil) => nil (9) filter(I2,cons(P2,X3)) => filter2(I2[P2],I2,P2,X3) (10) filter2(true,Z3,U3,V3) => cons(U3,filter(Z3,V3)) (11) filter2(false,I3,P3,X4) => filter(I3,X4) NO