/export/starexec/sandbox2/solver/bin/starexec_run_c /export/starexec/sandbox2/benchmark/theBenchmark.c /export/starexec/sandbox2/output/output_files


--------------------------------------------------------------------------------


NO
proof of /export/starexec/sandbox2/benchmark/theBenchmark.c
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


Termination of the given C Problem could be disproven:

(0) C Problem
(1) CToIRSProof [EQUIVALENT, 0 ms]
(2) IntTRS
(3) IRS2T2 [EQUIVALENT, 0 ms]
(4) T2IntSys
(5) T2 Underapproximation [COMPLETE, 1798 ms]
(6) T2IntSys
(7) T2 [COMPLETE, 953 ms]
(8) NO


----------------------------------------

(0)
Obligation:
c file /export/starexec/sandbox2/benchmark/theBenchmark.c
----------------------------------------

(1) CToIRSProof (EQUIVALENT)
Parsed C Integer Program as IRS.
----------------------------------------

(2)
Obligation:
Rules:
f1(x, y) -> f2(x_1, y) :|: TRUE
f2(x1, x2) -> f3(x1, x3) :|: TRUE
f7(x4, x5) -> f8(arith, x5) :|: TRUE && arith = x4 + x4 + x5
f8(x22, x23) -> f9(x22, x24) :|: TRUE && x24 = x23 + 1
f4(x8, x9) -> f7(x8, x9) :|: x8 > 0
f9(x10, x11) -> f4(x10, x11) :|: TRUE
f4(x12, x13) -> f10(x12, x13) :|: x12 <= 0
f3(x14, x15) -> f4(x14, x15) :|: x14 + x15 >= 0
f3(x16, x17) -> f5(x16, x17) :|: x16 + x17 < 0
f10(x18, x19) -> f6(x18, x19) :|: TRUE
f5(x20, x21) -> f6(x20, x21) :|: TRUE
Start term: f1(x, y)

----------------------------------------

(3) IRS2T2 (EQUIVALENT)
Transformed input IRS into an integer transition system.Used the following mapping from defined symbols to location IDs:

   (f1_2,1)
   (f2_2,2)
   (f3_2,3)
   (f7_2,4)
   (f8_2,5)
   (f9_2,6)
   (f4_2,7)
   (f10_2,8)
   (f5_2,9)
   (f6_2,10)

----------------------------------------

(4)
Obligation:
START: 1;

FROM: 1;
oldX0 := x0;
oldX1 := x1;
oldX2 := nondet();
assume(0 = 0);
x0 := oldX2;
x1 := oldX1;
TO: 2;

FROM: 2;
oldX0 := x0;
oldX1 := x1;
oldX2 := nondet();
assume(0 = 0);
x0 := oldX0;
x1 := oldX2;
TO: 3;

FROM: 4;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(-(oldX0 + oldX0 + oldX1));
assume(0 = 0 && oldX2 = oldX0 + oldX0 + oldX1);
x0 := -(-(oldX0 + oldX0 + oldX1));
x1 := oldX1;
TO: 5;

FROM: 5;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(-(oldX1 + 1));
assume(0 = 0 && oldX2 = oldX1 + 1);
x0 := oldX0;
x1 := -(-(oldX1 + 1));
TO: 6;

FROM: 7;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 > 0);
x0 := oldX0;
x1 := oldX1;
TO: 4;

FROM: 6;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 7;

FROM: 7;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 <= 0);
x0 := oldX0;
x1 := oldX1;
TO: 8;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 + oldX1 >= 0);
x0 := oldX0;
x1 := oldX1;
TO: 7;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 + oldX1 < 0);
x0 := oldX0;
x1 := oldX1;
TO: 9;

FROM: 8;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 10;

FROM: 9;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 10;


----------------------------------------

(5) T2 Underapproximation (COMPLETE)
Added the following guard statements:



Transition 5:
assume(x1 >= 0);



----------------------------------------

(6)
Obligation:
START: 1;

FROM: 1;
oldX0 := x0;
oldX1 := x1;
oldX2 := nondet();
assume(0 = 0);
x0 := oldX2;
x1 := x1;
TO: 2;

FROM: 2;
oldX0 := x0;
oldX1 := x1;
oldX2 := nondet();
assume(0 = 0);
x0 := x0;
x1 := oldX2;
TO: 3;

FROM: 4;
oldX0 := x0;
oldX1 := x1;
oldX2 := x0 + x0 + x1;
assume(0 = 0 && x0 + x0 + x1 = x0 + x0 + x1);
x0 := x0 + x0 + x1;
x1 := x1;
TO: 5;

FROM: 5;
oldX0 := x0;
oldX1 := x1;
oldX2 := x1 + 1;
assume(0 = 0 && x1 + 1 = x1 + 1);
x0 := x0;
assume(x1 >= 0);
x1 := x1 + 1;
TO: 6;

FROM: 7;
oldX0 := x0;
oldX1 := x1;
assume(x0 > 0);
x0 := x0;
x1 := x1;
TO: 4;

FROM: 6;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := x0;
x1 := x1;
TO: 7;

FROM: 7;
oldX0 := x0;
oldX1 := x1;
assume(x0 <= 0);
x0 := x0;
x1 := x1;
TO: 8;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(x0 + x1 >= 0);
x0 := x0;
x1 := x1;
TO: 7;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(x0 + x1 < 0);
x0 := x0;
x1 := x1;
TO: 9;

FROM: 8;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := x0;
x1 := x1;
TO: 10;

FROM: 9;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := x0;
x1 := x1;
TO: 10;


----------------------------------------

(7) T2 (COMPLETE)
Found this recurrent set for cutpoint 7: oldX2-x1 <= 0 and 0 <= x1+x0 and -x0+1 <= 0

----------------------------------------

(8)
NO