/export/starexec/sandbox2/solver/bin/starexec_run_c /export/starexec/sandbox2/benchmark/theBenchmark.c /export/starexec/sandbox2/output/output_files


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NO
proof of /export/starexec/sandbox2/benchmark/theBenchmark.c
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


Termination of the given C Problem could be disproven:

(0) C Problem
(1) CToIRSProof [EQUIVALENT, 0 ms]
(2) IntTRS
(3) IRS2T2 [EQUIVALENT, 0 ms]
(4) T2IntSys
(5) T2 [COMPLETE, 993 ms]
(6) NO


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(0)
Obligation:
c file /export/starexec/sandbox2/benchmark/theBenchmark.c
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(1) CToIRSProof (EQUIVALENT)
Parsed C Integer Program as IRS.
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(2)
Obligation:
Rules:
f1(x, c) -> f2(x_1, c) :|: TRUE
f2(x1, x2) -> f3(x1, x3) :|: TRUE
f7(x4, x5) -> f8(arith, x5) :|: TRUE && arith = x4 - x5
f8(x22, x23) -> f9(x22, x24) :|: TRUE && x24 = x23 - 1
f4(x8, x9) -> f7(x8, x9) :|: x8 + x9 >= 0
f9(x10, x11) -> f4(x10, x11) :|: TRUE
f4(x12, x13) -> f10(x12, x13) :|: x12 + x13 < 0
f3(x14, x15) -> f4(x14, x15) :|: x15 < 0
f3(x16, x17) -> f5(x16, x17) :|: x17 >= 0
f10(x18, x19) -> f6(x18, x19) :|: TRUE
f5(x20, x21) -> f6(x20, x21) :|: TRUE
Start term: f1(x, c)

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(3) IRS2T2 (EQUIVALENT)
Transformed input IRS into an integer transition system.Used the following mapping from defined symbols to location IDs:

   (f1_2,1)
   (f2_2,2)
   (f3_2,3)
   (f7_2,4)
   (f8_2,5)
   (f9_2,6)
   (f4_2,7)
   (f10_2,8)
   (f5_2,9)
   (f6_2,10)

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(4)
Obligation:
START: 1;

FROM: 1;
oldX0 := x0;
oldX1 := x1;
oldX2 := nondet();
assume(0 = 0);
x0 := oldX2;
x1 := oldX1;
TO: 2;

FROM: 2;
oldX0 := x0;
oldX1 := x1;
oldX2 := nondet();
assume(0 = 0);
x0 := oldX0;
x1 := oldX2;
TO: 3;

FROM: 4;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(oldX1 - oldX0);
assume(0 = 0 && oldX2 = oldX0 - oldX1);
x0 := -(oldX1 - oldX0);
x1 := oldX1;
TO: 5;

FROM: 5;
oldX0 := x0;
oldX1 := x1;
oldX2 := -(1 - oldX1);
assume(0 = 0 && oldX2 = oldX1 - 1);
x0 := oldX0;
x1 := -(1 - oldX1);
TO: 6;

FROM: 7;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 + oldX1 >= 0);
x0 := oldX0;
x1 := oldX1;
TO: 4;

FROM: 6;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 7;

FROM: 7;
oldX0 := x0;
oldX1 := x1;
assume(oldX0 + oldX1 < 0);
x0 := oldX0;
x1 := oldX1;
TO: 8;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(oldX1 < 0);
x0 := oldX0;
x1 := oldX1;
TO: 7;

FROM: 3;
oldX0 := x0;
oldX1 := x1;
assume(oldX1 >= 0);
x0 := oldX0;
x1 := oldX1;
TO: 9;

FROM: 8;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 10;

FROM: 9;
oldX0 := x0;
oldX1 := x1;
assume(0 = 0);
x0 := oldX0;
x1 := oldX1;
TO: 10;


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(5) T2 (COMPLETE)
Found this recurrent set for cutpoint 7: oldX1 <= -1 and oldX2 <= -1 and x1 <= -1 and oldX1-oldX2 <= 0 and oldX1+oldX2 <= -2 and x1-oldX1 <= 0 and oldX1-x1 <= 0 and x1+oldX1 <= -2 and x1-oldX2 <= 0 and x1+oldX2 <= -2 and 0 <= 0

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(6)
NO