/export/starexec/sandbox/solver/bin/starexec_run_c /export/starexec/sandbox/benchmark/theBenchmark.c /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.c # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 52 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 30 ms] (6) IntTRS (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (8) IntTRS (9) PolynomialOrderProcessor [EQUIVALENT, 7 ms] (10) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(x, y, z) -> f2(x_1, y, z) :|: TRUE f2(x1, x2, x3) -> f3(x1, x4, x3) :|: TRUE f3(x5, x6, x7) -> f4(x5, x6, x8) :|: TRUE f6(x9, x10, x11) -> f7(arith, x10, x11) :|: TRUE && arith = x9 - 1 f7(x33, x34, x35) -> f8(x33, x36, x35) :|: TRUE && x36 = x34 - 1 f5(x15, x16, x17) -> f6(x15, x16, x17) :|: x16 > x17 f8(x18, x19, x20) -> f5(x18, x19, x20) :|: TRUE f5(x21, x22, x23) -> f9(x21, x22, x23) :|: x22 <= x23 f4(x24, x25, x26) -> f5(x24, x25, x26) :|: x24 = x25 && x24 > x26 f9(x27, x28, x29) -> f4(x27, x28, x29) :|: TRUE f4(x30, x31, x32) -> f10(x30, x31, x32) :|: x30 <= x32 f4(x37, x38, x39) -> f10(x37, x38, x39) :|: x37 < x38 f4(x40, x41, x42) -> f10(x40, x41, x42) :|: x40 > x41 Start term: f1(x, y, z) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f4(x24, x25, x26) -> f5(x24, x25, x26) :|: x24 = x25 && x24 > x26 f9(x27, x28, x29) -> f4(x27, x28, x29) :|: TRUE f5(x21, x22, x23) -> f9(x21, x22, x23) :|: x22 <= x23 f8(x18, x19, x20) -> f5(x18, x19, x20) :|: TRUE f7(x33, x34, x35) -> f8(x33, x36, x35) :|: TRUE && x36 = x34 - 1 f6(x9, x10, x11) -> f7(arith, x10, x11) :|: TRUE && arith = x9 - 1 f5(x15, x16, x17) -> f6(x15, x16, x17) :|: x16 > x17 ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f5(x15:0, x16:0, x17:0) -> f5(x15:0 - 1, x16:0 - 1, x17:0) :|: x17:0 < x16:0 ---------------------------------------- (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: f5(x1, x2, x3) -> f5(x2, x3) ---------------------------------------- (8) Obligation: Rules: f5(x16:0, x17:0) -> f5(x16:0 - 1, x17:0) :|: x17:0 < x16:0 ---------------------------------------- (9) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation: [f5(x, x1)] = x - x1 The following rules are decreasing: f5(x16:0, x17:0) -> f5(x16:0 - 1, x17:0) :|: x17:0 < x16:0 The following rules are bounded: f5(x16:0, x17:0) -> f5(x16:0 - 1, x17:0) :|: x17:0 < x16:0 ---------------------------------------- (10) YES