/export/starexec/sandbox/solver/bin/starexec_run_c /export/starexec/sandbox/benchmark/theBenchmark.c /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.c # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 40 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 0 ms] (6) IntTRS (7) TerminationGraphProcessor [EQUIVALENT, 6 ms] (8) IntTRS (9) TerminationGraphProcessor [EQUIVALENT, 6 ms] (10) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(x) -> f2(x_1) :|: TRUE f3(x1) -> f4(arith) :|: TRUE && arith = 0 - 2 * x1 + 10 f2(x2) -> f3(x2) :|: x2 >= 0 f4(x3) -> f2(x3) :|: TRUE f2(x4) -> f5(x4) :|: x4 < 0 Start term: f1(x) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f2(x2) -> f3(x2) :|: x2 >= 0 f4(x3) -> f2(x3) :|: TRUE f3(x1) -> f4(arith) :|: TRUE && arith = 0 - 2 * x1 + 10 ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f4(x3:0) -> f4(0 - 2 * x3:0 + 10) :|: x3:0 > -1 ---------------------------------------- (7) TerminationGraphProcessor (EQUIVALENT) Constructed the termination graph and obtained one non-trivial SCC. f4(x3:0) -> f4(0 - 2 * x3:0 + 10) :|: x3:0 > -1 has been transformed into f4(x3:0) -> f4(0 - 2 * x3:0 + 10) :|: x3:0 = 0 - 2 * x2 + 10 && x3:0 > -1 && x2 > -1. f4(x3:0) -> f4(0 - 2 * x3:0 + 10) :|: x3:0 = 0 - 2 * x2 + 10 && x3:0 > -1 && x2 > -1 and f4(x3:0) -> f4(0 - 2 * x3:0 + 10) :|: x3:0 = 0 - 2 * x2 + 10 && x3:0 > -1 && x2 > -1 have been merged into the new rule f4(x7) -> f4(0 - 2 * (0 - 2 * x7 + 10) + 10) :|: x7 = 0 - 2 * x8 + 10 && x7 > -1 && x8 > -1 && (0 - 2 * x7 + 10 = 0 - 2 * x9 + 10 && 0 - 2 * x7 + 10 > -1 && x9 > -1) ---------------------------------------- (8) Obligation: Rules: f4(x10) -> f4(4 * x10 + -10) :|: TRUE && x10 + 2 * x11 = 10 && x10 >= 0 && x11 >= 0 && -1 * x10 + x12 = 0 && -1 * x10 >= -5 && x12 >= 0 ---------------------------------------- (9) TerminationGraphProcessor (EQUIVALENT) Constructed the termination graph and obtained no non-trivial SCC(s). ---------------------------------------- (10) YES