/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f4#(x1, x2) -> f3#(x1, x2) f3#(I0, I1) -> f1#(I0, I1) f2#(I2, I3) -> f1#(I2, I3) f1#(I4, I5) -> f2#(I4, 1 + I5) [1 + I4 <= 1 + I5] R = f4(x1, x2) -> f3(x1, x2) f3(I0, I1) -> f1(I0, I1) f2(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f2(I4, 1 + I5) [1 + I4 <= 1 + I5] The dependency graph for this problem is: 0 -> 1 1 -> 3 2 -> 3 3 -> 2 Where: 0) f4#(x1, x2) -> f3#(x1, x2) 1) f3#(I0, I1) -> f1#(I0, I1) 2) f2#(I2, I3) -> f1#(I2, I3) 3) f1#(I4, I5) -> f2#(I4, 1 + I5) [1 + I4 <= 1 + I5] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f2#(I2, I3) -> f1#(I2, I3) f1#(I4, I5) -> f2#(I4, 1 + I5) [1 + I4 <= 1 + I5] R = f4(x1, x2) -> f3(x1, x2) f3(I0, I1) -> f1(I0, I1) f2(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f2(I4, 1 + I5) [1 + I4 <= 1 + I5]