/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files


--------------------------------------------------------------------------------


YES

DP problem for innermost termination.
P =
  f11#(x1, x2, x3, x4, x5, x6) -> f10#(x1, x2, x3, x4, x5, x6) 
  f10#(I0, I1, I2, I3, I4, I5) -> f6#(I0, I1, I2, I3, I4, rnd6) [rnd6 = rnd6]
  f2#(I6, I7, I8, I9, I10, I11) -> f9#(I6, I7, I8, I9, I10, I11) [0 <= I7]
  f2#(I12, I13, I14, I15, I16, I17) -> f7#(I12, I13, I14, I15, I16, I17) [1 + I13 <= 0]
  f9#(I18, I19, I20, I21, I22, I23) -> f7#(I18, I19, I20, I21, I22, I23) [1 + I19 <= I18]
  f9#(I24, I25, I26, I27, I28, I29) -> f7#(I24, I25, I26, I27, I28, I29) [I24 <= I25]
  f3#(I36, I37, I38, I39, I40, I41) -> f1#(I36, I37, I38, I39, I40, I41) 
  f6#(I42, I43, I44, I45, I46, I47) -> f5#(I42, I43, I44, I45, I46, I47) [1 + I47 <= 0]
  f6#(I48, I49, I50, I51, I52, I53) -> f5#(I48, I49, I50, I51, I52, I53) [1 <= I53]
  f6#(I54, I55, I56, I57, I58, I59) -> f4#(I54, I55, I56, I57, I54, I59) [0 <= I59 /\ I59 <= 0]
  f5#(I60, I61, I62, I63, I64, I65) -> f4#(I60, I61, I62, I63, 0, I65) 
  f4#(I66, I67, I68, I69, I70, I71) -> f3#(I66, I67, 0, I69, I70, I71) 
  f1#(I72, I73, I74, I75, I76, I77) -> f3#(I72, I73, 1 + I74, 2 + I75, I76, I77) [I74 <= I76]
  f1#(I78, I79, I80, I81, I82, I83) -> f2#(I78, I79, I80, I81, I82, I83) [1 + I82 <= I80]
R = 
  f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) 
  f10(I0, I1, I2, I3, I4, I5) -> f6(I0, I1, I2, I3, I4, rnd6) [rnd6 = rnd6]
  f2(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [0 <= I7]
  f2(I12, I13, I14, I15, I16, I17) -> f7(I12, I13, I14, I15, I16, I17) [1 + I13 <= 0]
  f9(I18, I19, I20, I21, I22, I23) -> f7(I18, I19, I20, I21, I22, I23) [1 + I19 <= I18]
  f9(I24, I25, I26, I27, I28, I29) -> f7(I24, I25, I26, I27, I28, I29) [I24 <= I25]
  f7(I30, I31, I32, I33, I34, I35) -> f8(I30, I31, I32, I33, I34, I35) 
  f3(I36, I37, I38, I39, I40, I41) -> f1(I36, I37, I38, I39, I40, I41) 
  f6(I42, I43, I44, I45, I46, I47) -> f5(I42, I43, I44, I45, I46, I47) [1 + I47 <= 0]
  f6(I48, I49, I50, I51, I52, I53) -> f5(I48, I49, I50, I51, I52, I53) [1 <= I53]
  f6(I54, I55, I56, I57, I58, I59) -> f4(I54, I55, I56, I57, I54, I59) [0 <= I59 /\ I59 <= 0]
  f5(I60, I61, I62, I63, I64, I65) -> f4(I60, I61, I62, I63, 0, I65) 
  f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, 0, I69, I70, I71) 
  f1(I72, I73, I74, I75, I76, I77) -> f3(I72, I73, 1 + I74, 2 + I75, I76, I77) [I74 <= I76]
  f1(I78, I79, I80, I81, I82, I83) -> f2(I78, I79, I80, I81, I82, I83) [1 + I82 <= I80]

The dependency graph for this problem is:
  0 -> 1
  1 -> 7, 8, 9
  2 -> 4, 5
  3 -> 
  4 -> 
  5 -> 
  6 -> 12, 13
  7 -> 10
  8 -> 10
  9 -> 11
  10 -> 11
  11 -> 6
  12 -> 6
  13 -> 2, 3
Where:
  0) f11#(x1, x2, x3, x4, x5, x6) -> f10#(x1, x2, x3, x4, x5, x6) 
  1) f10#(I0, I1, I2, I3, I4, I5) -> f6#(I0, I1, I2, I3, I4, rnd6) [rnd6 = rnd6]
  2) f2#(I6, I7, I8, I9, I10, I11) -> f9#(I6, I7, I8, I9, I10, I11) [0 <= I7]
  3) f2#(I12, I13, I14, I15, I16, I17) -> f7#(I12, I13, I14, I15, I16, I17) [1 + I13 <= 0]
  4) f9#(I18, I19, I20, I21, I22, I23) -> f7#(I18, I19, I20, I21, I22, I23) [1 + I19 <= I18]
  5) f9#(I24, I25, I26, I27, I28, I29) -> f7#(I24, I25, I26, I27, I28, I29) [I24 <= I25]
  6) f3#(I36, I37, I38, I39, I40, I41) -> f1#(I36, I37, I38, I39, I40, I41) 
  7) f6#(I42, I43, I44, I45, I46, I47) -> f5#(I42, I43, I44, I45, I46, I47) [1 + I47 <= 0]
  8) f6#(I48, I49, I50, I51, I52, I53) -> f5#(I48, I49, I50, I51, I52, I53) [1 <= I53]
  9) f6#(I54, I55, I56, I57, I58, I59) -> f4#(I54, I55, I56, I57, I54, I59) [0 <= I59 /\ I59 <= 0]
  10) f5#(I60, I61, I62, I63, I64, I65) -> f4#(I60, I61, I62, I63, 0, I65) 
  11) f4#(I66, I67, I68, I69, I70, I71) -> f3#(I66, I67, 0, I69, I70, I71) 
  12) f1#(I72, I73, I74, I75, I76, I77) -> f3#(I72, I73, 1 + I74, 2 + I75, I76, I77) [I74 <= I76]
  13) f1#(I78, I79, I80, I81, I82, I83) -> f2#(I78, I79, I80, I81, I82, I83) [1 + I82 <= I80]

We have the following SCCs.
  { 6, 12 }

DP problem for innermost termination.
P =
  f3#(I36, I37, I38, I39, I40, I41) -> f1#(I36, I37, I38, I39, I40, I41) 
  f1#(I72, I73, I74, I75, I76, I77) -> f3#(I72, I73, 1 + I74, 2 + I75, I76, I77) [I74 <= I76]
R = 
  f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) 
  f10(I0, I1, I2, I3, I4, I5) -> f6(I0, I1, I2, I3, I4, rnd6) [rnd6 = rnd6]
  f2(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [0 <= I7]
  f2(I12, I13, I14, I15, I16, I17) -> f7(I12, I13, I14, I15, I16, I17) [1 + I13 <= 0]
  f9(I18, I19, I20, I21, I22, I23) -> f7(I18, I19, I20, I21, I22, I23) [1 + I19 <= I18]
  f9(I24, I25, I26, I27, I28, I29) -> f7(I24, I25, I26, I27, I28, I29) [I24 <= I25]
  f7(I30, I31, I32, I33, I34, I35) -> f8(I30, I31, I32, I33, I34, I35) 
  f3(I36, I37, I38, I39, I40, I41) -> f1(I36, I37, I38, I39, I40, I41) 
  f6(I42, I43, I44, I45, I46, I47) -> f5(I42, I43, I44, I45, I46, I47) [1 + I47 <= 0]
  f6(I48, I49, I50, I51, I52, I53) -> f5(I48, I49, I50, I51, I52, I53) [1 <= I53]
  f6(I54, I55, I56, I57, I58, I59) -> f4(I54, I55, I56, I57, I54, I59) [0 <= I59 /\ I59 <= 0]
  f5(I60, I61, I62, I63, I64, I65) -> f4(I60, I61, I62, I63, 0, I65) 
  f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, 0, I69, I70, I71) 
  f1(I72, I73, I74, I75, I76, I77) -> f3(I72, I73, 1 + I74, 2 + I75, I76, I77) [I74 <= I76]
  f1(I78, I79, I80, I81, I82, I83) -> f2(I78, I79, I80, I81, I82, I83) [1 + I82 <= I80]

We use the reverse value criterion with the projection function NU:
  NU[f1#(z1,z2,z3,z4,z5,z6)] = z5 + -1 * z3
  NU[f3#(z1,z2,z3,z4,z5,z6)] = z5 + -1 * z3

This gives the following inequalities:
    ==>  I40 + -1 * I38 >= I40 + -1 * I38
  I74 <= I76  ==>  I76 + -1 * I74 > I76 + -1 * (1 + I74)  with  I76 + -1 * I74 >= 0

We remove all the strictly oriented dependency pairs.

DP problem for innermost termination.
P =
  f3#(I36, I37, I38, I39, I40, I41) -> f1#(I36, I37, I38, I39, I40, I41) 
R = 
  f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) 
  f10(I0, I1, I2, I3, I4, I5) -> f6(I0, I1, I2, I3, I4, rnd6) [rnd6 = rnd6]
  f2(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [0 <= I7]
  f2(I12, I13, I14, I15, I16, I17) -> f7(I12, I13, I14, I15, I16, I17) [1 + I13 <= 0]
  f9(I18, I19, I20, I21, I22, I23) -> f7(I18, I19, I20, I21, I22, I23) [1 + I19 <= I18]
  f9(I24, I25, I26, I27, I28, I29) -> f7(I24, I25, I26, I27, I28, I29) [I24 <= I25]
  f7(I30, I31, I32, I33, I34, I35) -> f8(I30, I31, I32, I33, I34, I35) 
  f3(I36, I37, I38, I39, I40, I41) -> f1(I36, I37, I38, I39, I40, I41) 
  f6(I42, I43, I44, I45, I46, I47) -> f5(I42, I43, I44, I45, I46, I47) [1 + I47 <= 0]
  f6(I48, I49, I50, I51, I52, I53) -> f5(I48, I49, I50, I51, I52, I53) [1 <= I53]
  f6(I54, I55, I56, I57, I58, I59) -> f4(I54, I55, I56, I57, I54, I59) [0 <= I59 /\ I59 <= 0]
  f5(I60, I61, I62, I63, I64, I65) -> f4(I60, I61, I62, I63, 0, I65) 
  f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, 0, I69, I70, I71) 
  f1(I72, I73, I74, I75, I76, I77) -> f3(I72, I73, 1 + I74, 2 + I75, I76, I77) [I74 <= I76]
  f1(I78, I79, I80, I81, I82, I83) -> f2(I78, I79, I80, I81, I82, I83) [1 + I82 <= I80]

The dependency graph for this problem is:
  6 -> 
Where:
  6) f3#(I36, I37, I38, I39, I40, I41) -> f1#(I36, I37, I38, I39, I40, I41) 

We have the following SCCs.