/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f2#(I0, I1) -> f2#(I0 - 2, I2) [I0 <= -1 /\ I0 - 2 <= I0 - 1 /\ I0 <= 0 /\ I0 <= 2] f1#(I3, I4) -> f2#(-1 * I4, I5) [0 <= I3 - 1 /\ -1 <= I4 - 1 /\ -1 * I4 <= 0] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(I0 - 2, I2) [I0 <= -1 /\ I0 - 2 <= I0 - 1 /\ I0 <= 0 /\ I0 <= 2] f1(I3, I4) -> f2(-1 * I4, I5) [0 <= I3 - 1 /\ -1 <= I4 - 1 /\ -1 * I4 <= 0] The dependency graph for this problem is: 0 -> 2 1 -> 1 2 -> 1 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f2#(I0, I1) -> f2#(I0 - 2, I2) [I0 <= -1 /\ I0 - 2 <= I0 - 1 /\ I0 <= 0 /\ I0 <= 2] 2) f1#(I3, I4) -> f2#(-1 * I4, I5) [0 <= I3 - 1 /\ -1 <= I4 - 1 /\ -1 * I4 <= 0] We have the following SCCs. { 1 } DP problem for innermost termination. P = f2#(I0, I1) -> f2#(I0 - 2, I2) [I0 <= -1 /\ I0 - 2 <= I0 - 1 /\ I0 <= 0 /\ I0 <= 2] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(I0 - 2, I2) [I0 <= -1 /\ I0 - 2 <= I0 - 1 /\ I0 <= 0 /\ I0 <= 2] f1(I3, I4) -> f2(-1 * I4, I5) [0 <= I3 - 1 /\ -1 <= I4 - 1 /\ -1 * I4 <= 0]