/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f5#(x1, x2, x3) -> f1#(x1, x2, x3) 
  f3#(I3, I4, I5) -> f2#(I3, I4, I5) 
  f2#(I6, I7, I8) -> f3#(I6, I7 + I8, I8) [-1 * (I7 + I8) <= 0]
  f1#(I9, I10, I11) -> f2#(I9, I10, I11) 
R = 
  f5(x1, x2, x3) -> f1(x1, x2, x3) 
  f2(I0, I1, I2) -> f4(rnd1, I1 + I2, I2) [rnd1 = rnd1 /\ 0 <= -1 - (I1 + I2)]
  f3(I3, I4, I5) -> f2(I3, I4, I5) 
  f2(I6, I7, I8) -> f3(I6, I7 + I8, I8) [-1 * (I7 + I8) <= 0]
  f1(I9, I10, I11) -> f2(I9, I10, I11) 

The dependency graph for this problem is:
  0 -> 3
  1 -> 2
  2 -> 1
  3 -> 2
Where:
  0) f5#(x1, x2, x3) -> f1#(x1, x2, x3) 
  1) f3#(I3, I4, I5) -> f2#(I3, I4, I5) 
  2) f2#(I6, I7, I8) -> f3#(I6, I7 + I8, I8) [-1 * (I7 + I8) <= 0]
  3) f1#(I9, I10, I11) -> f2#(I9, I10, I11) 

We have the following SCCs.
  { 1, 2 }

DP problem for innermost termination.
P =
  f3#(I3, I4, I5) -> f2#(I3, I4, I5) 
  f2#(I6, I7, I8) -> f3#(I6, I7 + I8, I8) [-1 * (I7 + I8) <= 0]
R = 
  f5(x1, x2, x3) -> f1(x1, x2, x3) 
  f2(I0, I1, I2) -> f4(rnd1, I1 + I2, I2) [rnd1 = rnd1 /\ 0 <= -1 - (I1 + I2)]
  f3(I3, I4, I5) -> f2(I3, I4, I5) 
  f2(I6, I7, I8) -> f3(I6, I7 + I8, I8) [-1 * (I7 + I8) <= 0]
  f1(I9, I10, I11) -> f2(I9, I10, I11)