/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  init#(x1, x2, x3, x4, x5) -> f1#(rnd1, rnd2, rnd3, rnd4, rnd5) 
  f2#(I0, I1, I2, I3, I4) -> f2#(I5, I6, I7, I3, I4 + 1) [0 <= I2 - 1 /\ 1 <= I0 + 1 + y1 /\ -1 <= I3 - 1 /\ -1 <= I4 - 1 /\ I4 <= I3 - 1 /\ -1 <= I0 - 1 /\ -1 <= y1 - 1 /\ I0 = I1 /\ I0 + 1 + y1 = I5 /\ I0 + 1 + y1 = I6 /\ 10 - (I0 + 1 + y1) = I7]
  f2#(I8, I9, I10, I11, I12) -> f2#(I8 + 1, I8 + 1, 10 - (I8 + 1), I11, I12) [I8 = I9 /\ -1 <= I11 - 1 /\ I11 <= I12 /\ 0 <= I10 - 1 /\ -1 <= I8 - 1 /\ I8 <= I8 + 1 - 1]
  f1#(I13, I14, I15, I16, I17) -> f2#(I18, I19, I20, I14, 3) [-1 <= I18 - 1 /\ 2 <= I14 - 1 /\ -1 <= I21 - 1 /\ -1 <= I19 - 1 /\ 0 <= I13 - 1 /\ I21 - I19 = I20]
  f1#(I22, I23, I24, I25, I26) -> f2#(I27, 0, I28, 2, 2) [2 = I23 /\ 0 <= I22 - 1 /\ -1 <= I27 - 1 /\ -1 <= I28 - 1]
  f1#(I29, I30, I31, I32, I33) -> f2#(I34, 0, 0, 1, 1) [1 = I30 /\ -1 <= I34 - 1 /\ 0 <= I29 - 1]
  f1#(I35, I36, I37, I38, I39) -> f2#(0, 0, 0, 0, 0) [0 = I36 /\ 0 <= I35 - 1]
R = 
  init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) 
  f2(I0, I1, I2, I3, I4) -> f2(I5, I6, I7, I3, I4 + 1) [0 <= I2 - 1 /\ 1 <= I0 + 1 + y1 /\ -1 <= I3 - 1 /\ -1 <= I4 - 1 /\ I4 <= I3 - 1 /\ -1 <= I0 - 1 /\ -1 <= y1 - 1 /\ I0 = I1 /\ I0 + 1 + y1 = I5 /\ I0 + 1 + y1 = I6 /\ 10 - (I0 + 1 + y1) = I7]
  f2(I8, I9, I10, I11, I12) -> f2(I8 + 1, I8 + 1, 10 - (I8 + 1), I11, I12) [I8 = I9 /\ -1 <= I11 - 1 /\ I11 <= I12 /\ 0 <= I10 - 1 /\ -1 <= I8 - 1 /\ I8 <= I8 + 1 - 1]
  f1(I13, I14, I15, I16, I17) -> f2(I18, I19, I20, I14, 3) [-1 <= I18 - 1 /\ 2 <= I14 - 1 /\ -1 <= I21 - 1 /\ -1 <= I19 - 1 /\ 0 <= I13 - 1 /\ I21 - I19 = I20]
  f1(I22, I23, I24, I25, I26) -> f2(I27, 0, I28, 2, 2) [2 = I23 /\ 0 <= I22 - 1 /\ -1 <= I27 - 1 /\ -1 <= I28 - 1]
  f1(I29, I30, I31, I32, I33) -> f2(I34, 0, 0, 1, 1) [1 = I30 /\ -1 <= I34 - 1 /\ 0 <= I29 - 1]
  f1(I35, I36, I37, I38, I39) -> f2(0, 0, 0, 0, 0) [0 = I36 /\ 0 <= I35 - 1]

The dependency graph for this problem is:
  0 -> 3, 4, 5, 6
  1 -> 1, 2
  2 -> 2
  3 -> 1, 2
  4 -> 2
  5 -> 
  6 -> 
Where:
  0) init#(x1, x2, x3, x4, x5) -> f1#(rnd1, rnd2, rnd3, rnd4, rnd5) 
  1) f2#(I0, I1, I2, I3, I4) -> f2#(I5, I6, I7, I3, I4 + 1) [0 <= I2 - 1 /\ 1 <= I0 + 1 + y1 /\ -1 <= I3 - 1 /\ -1 <= I4 - 1 /\ I4 <= I3 - 1 /\ -1 <= I0 - 1 /\ -1 <= y1 - 1 /\ I0 = I1 /\ I0 + 1 + y1 = I5 /\ I0 + 1 + y1 = I6 /\ 10 - (I0 + 1 + y1) = I7]
  2) f2#(I8, I9, I10, I11, I12) -> f2#(I8 + 1, I8 + 1, 10 - (I8 + 1), I11, I12) [I8 = I9 /\ -1 <= I11 - 1 /\ I11 <= I12 /\ 0 <= I10 - 1 /\ -1 <= I8 - 1 /\ I8 <= I8 + 1 - 1]
  3) f1#(I13, I14, I15, I16, I17) -> f2#(I18, I19, I20, I14, 3) [-1 <= I18 - 1 /\ 2 <= I14 - 1 /\ -1 <= I21 - 1 /\ -1 <= I19 - 1 /\ 0 <= I13 - 1 /\ I21 - I19 = I20]
  4) f1#(I22, I23, I24, I25, I26) -> f2#(I27, 0, I28, 2, 2) [2 = I23 /\ 0 <= I22 - 1 /\ -1 <= I27 - 1 /\ -1 <= I28 - 1]
  5) f1#(I29, I30, I31, I32, I33) -> f2#(I34, 0, 0, 1, 1) [1 = I30 /\ -1 <= I34 - 1 /\ 0 <= I29 - 1]
  6) f1#(I35, I36, I37, I38, I39) -> f2#(0, 0, 0, 0, 0) [0 = I36 /\ 0 <= I35 - 1]

We have the following SCCs.
  { 1 }
  { 2 }

DP problem for innermost termination.
P =
  f2#(I8, I9, I10, I11, I12) -> f2#(I8 + 1, I8 + 1, 10 - (I8 + 1), I11, I12) [I8 = I9 /\ -1 <= I11 - 1 /\ I11 <= I12 /\ 0 <= I10 - 1 /\ -1 <= I8 - 1 /\ I8 <= I8 + 1 - 1]
R = 
  init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) 
  f2(I0, I1, I2, I3, I4) -> f2(I5, I6, I7, I3, I4 + 1) [0 <= I2 - 1 /\ 1 <= I0 + 1 + y1 /\ -1 <= I3 - 1 /\ -1 <= I4 - 1 /\ I4 <= I3 - 1 /\ -1 <= I0 - 1 /\ -1 <= y1 - 1 /\ I0 = I1 /\ I0 + 1 + y1 = I5 /\ I0 + 1 + y1 = I6 /\ 10 - (I0 + 1 + y1) = I7]
  f2(I8, I9, I10, I11, I12) -> f2(I8 + 1, I8 + 1, 10 - (I8 + 1), I11, I12) [I8 = I9 /\ -1 <= I11 - 1 /\ I11 <= I12 /\ 0 <= I10 - 1 /\ -1 <= I8 - 1 /\ I8 <= I8 + 1 - 1]
  f1(I13, I14, I15, I16, I17) -> f2(I18, I19, I20, I14, 3) [-1 <= I18 - 1 /\ 2 <= I14 - 1 /\ -1 <= I21 - 1 /\ -1 <= I19 - 1 /\ 0 <= I13 - 1 /\ I21 - I19 = I20]
  f1(I22, I23, I24, I25, I26) -> f2(I27, 0, I28, 2, 2) [2 = I23 /\ 0 <= I22 - 1 /\ -1 <= I27 - 1 /\ -1 <= I28 - 1]
  f1(I29, I30, I31, I32, I33) -> f2(I34, 0, 0, 1, 1) [1 = I30 /\ -1 <= I34 - 1 /\ 0 <= I29 - 1]
  f1(I35, I36, I37, I38, I39) -> f2(0, 0, 0, 0, 0) [0 = I36 /\ 0 <= I35 - 1]