/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f6#(x1, x2, x3) -> f5#(x1, x2, x3) 
  f5#(I0, I1, I2) -> f4#(I0, 0, I2) 
  f4#(I3, I4, I5) -> f3#(rnd1, I4, I5) [rnd1 = rnd1 /\ 1 <= I5]
  f4#(I6, I7, I8) -> f2#(I6, I7, I8) [I8 <= 0]
  f3#(I9, I10, I11) -> f4#(I9, I10, -1 + I11) [1 <= I9]
  f3#(I12, I13, I14) -> f4#(I12, I13, -2 + I14) [I12 <= 0]
  f2#(I15, I16, I17) -> f1#(I18, I16, I17) [I18 = I18]
  f1#(I19, I20, I21) -> f2#(I19, 1, I21) [1 <= I19]
  f1#(I22, I23, I24) -> f2#(I22, 2, I24) [I22 <= 0]
R = 
  f6(x1, x2, x3) -> f5(x1, x2, x3) 
  f5(I0, I1, I2) -> f4(I0, 0, I2) 
  f4(I3, I4, I5) -> f3(rnd1, I4, I5) [rnd1 = rnd1 /\ 1 <= I5]
  f4(I6, I7, I8) -> f2(I6, I7, I8) [I8 <= 0]
  f3(I9, I10, I11) -> f4(I9, I10, -1 + I11) [1 <= I9]
  f3(I12, I13, I14) -> f4(I12, I13, -2 + I14) [I12 <= 0]
  f2(I15, I16, I17) -> f1(I18, I16, I17) [I18 = I18]
  f1(I19, I20, I21) -> f2(I19, 1, I21) [1 <= I19]
  f1(I22, I23, I24) -> f2(I22, 2, I24) [I22 <= 0]

The dependency graph for this problem is:
  0 -> 1
  1 -> 2, 3
  2 -> 4, 5
  3 -> 6
  4 -> 2, 3
  5 -> 2, 3
  6 -> 7, 8
  7 -> 6
  8 -> 6
Where:
  0) f6#(x1, x2, x3) -> f5#(x1, x2, x3) 
  1) f5#(I0, I1, I2) -> f4#(I0, 0, I2) 
  2) f4#(I3, I4, I5) -> f3#(rnd1, I4, I5) [rnd1 = rnd1 /\ 1 <= I5]
  3) f4#(I6, I7, I8) -> f2#(I6, I7, I8) [I8 <= 0]
  4) f3#(I9, I10, I11) -> f4#(I9, I10, -1 + I11) [1 <= I9]
  5) f3#(I12, I13, I14) -> f4#(I12, I13, -2 + I14) [I12 <= 0]
  6) f2#(I15, I16, I17) -> f1#(I18, I16, I17) [I18 = I18]
  7) f1#(I19, I20, I21) -> f2#(I19, 1, I21) [1 <= I19]
  8) f1#(I22, I23, I24) -> f2#(I22, 2, I24) [I22 <= 0]

We have the following SCCs.
  { 2, 4, 5 }
  { 6, 7, 8 }

DP problem for innermost termination.
P =
  f2#(I15, I16, I17) -> f1#(I18, I16, I17) [I18 = I18]
  f1#(I19, I20, I21) -> f2#(I19, 1, I21) [1 <= I19]
  f1#(I22, I23, I24) -> f2#(I22, 2, I24) [I22 <= 0]
R = 
  f6(x1, x2, x3) -> f5(x1, x2, x3) 
  f5(I0, I1, I2) -> f4(I0, 0, I2) 
  f4(I3, I4, I5) -> f3(rnd1, I4, I5) [rnd1 = rnd1 /\ 1 <= I5]
  f4(I6, I7, I8) -> f2(I6, I7, I8) [I8 <= 0]
  f3(I9, I10, I11) -> f4(I9, I10, -1 + I11) [1 <= I9]
  f3(I12, I13, I14) -> f4(I12, I13, -2 + I14) [I12 <= 0]
  f2(I15, I16, I17) -> f1(I18, I16, I17) [I18 = I18]
  f1(I19, I20, I21) -> f2(I19, 1, I21) [1 <= I19]
  f1(I22, I23, I24) -> f2(I22, 2, I24) [I22 <= 0]