/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f5#(x1, x2, x3, x4, x5) -> f4#(x1, x2, x3, x4, x5) 
  f4#(I0, I1, I2, I3, I4) -> f1#(I0, I1, I2, 1, rnd5) [rnd5 = rnd5]
  f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 
  f1#(I10, I11, I12, I13, I14) -> f3#(I10, I11, I12, -1 + I13, -1 * I11 + I14) [1 + I10 <= I14 /\ 1 <= I13]
  f2#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I18, I19) 
  f1#(I20, I21, I22, I23, I24) -> f2#(I20, I21, I22, 1 + I23, I22 + I24) [I24 <= I20 /\ 1 <= I23]
R = 
  f5(x1, x2, x3, x4, x5) -> f4(x1, x2, x3, x4, x5) 
  f4(I0, I1, I2, I3, I4) -> f1(I0, I1, I2, 1, rnd5) [rnd5 = rnd5]
  f3(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I9) 
  f1(I10, I11, I12, I13, I14) -> f3(I10, I11, I12, -1 + I13, -1 * I11 + I14) [1 + I10 <= I14 /\ 1 <= I13]
  f2(I15, I16, I17, I18, I19) -> f1(I15, I16, I17, I18, I19) 
  f1(I20, I21, I22, I23, I24) -> f2(I20, I21, I22, 1 + I23, I22 + I24) [I24 <= I20 /\ 1 <= I23]

The dependency graph for this problem is:
  0 -> 1
  1 -> 3, 5
  2 -> 3, 5
  3 -> 2
  4 -> 3, 5
  5 -> 4
Where:
  0) f5#(x1, x2, x3, x4, x5) -> f4#(x1, x2, x3, x4, x5) 
  1) f4#(I0, I1, I2, I3, I4) -> f1#(I0, I1, I2, 1, rnd5) [rnd5 = rnd5]
  2) f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 
  3) f1#(I10, I11, I12, I13, I14) -> f3#(I10, I11, I12, -1 + I13, -1 * I11 + I14) [1 + I10 <= I14 /\ 1 <= I13]
  4) f2#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I18, I19) 
  5) f1#(I20, I21, I22, I23, I24) -> f2#(I20, I21, I22, 1 + I23, I22 + I24) [I24 <= I20 /\ 1 <= I23]

We have the following SCCs.
  { 2, 3, 4, 5 }

DP problem for innermost termination.
P =
  f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 
  f1#(I10, I11, I12, I13, I14) -> f3#(I10, I11, I12, -1 + I13, -1 * I11 + I14) [1 + I10 <= I14 /\ 1 <= I13]
  f2#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I18, I19) 
  f1#(I20, I21, I22, I23, I24) -> f2#(I20, I21, I22, 1 + I23, I22 + I24) [I24 <= I20 /\ 1 <= I23]
R = 
  f5(x1, x2, x3, x4, x5) -> f4(x1, x2, x3, x4, x5) 
  f4(I0, I1, I2, I3, I4) -> f1(I0, I1, I2, 1, rnd5) [rnd5 = rnd5]
  f3(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I9) 
  f1(I10, I11, I12, I13, I14) -> f3(I10, I11, I12, -1 + I13, -1 * I11 + I14) [1 + I10 <= I14 /\ 1 <= I13]
  f2(I15, I16, I17, I18, I19) -> f1(I15, I16, I17, I18, I19) 
  f1(I20, I21, I22, I23, I24) -> f2(I20, I21, I22, 1 + I23, I22 + I24) [I24 <= I20 /\ 1 <= I23]