/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f11#(x1, x2, x3, x4, x5, x6) -> f10#(x1, x2, x3, x4, x5, x6) 
  f10#(I0, I1, I2, I3, I4, I5) -> f4#(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5]
  f5#(I6, I7, I8, I9, I10, I11) -> f9#(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9]
  f5#(I12, I13, I14, I15, I16, I17) -> f9#(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13]
  f5#(I18, I19, I20, I21, I22, I23) -> f8#(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21]
  f9#(I24, I25, I26, I27, I28, I29) -> f8#(I24, I25, I26, I27, I28, I29) 
  f9#(I30, I31, I32, I33, I34, I35) -> f2#(I30, 1 + I31, I32, I33, I34, I35) 
  f7#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) 
  f8#(I42, I43, I44, I45, I46, I47) -> f7#(I42, -1 + I43, 0, I45, I46, I47) 
  f6#(I48, I49, I50, I51, I52, I53) -> f7#(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49]
  f2#(I60, I61, I62, I63, I64, I65) -> f5#(I60, I61, I62, I63, I64, I65) 
  f4#(I72, I73, I74, I75, I76, I77) -> f1#(I72, I73, I74, I75, I76, I77) [1 <= I75]
  f1#(I84, I85, I86, I87, I88, I89) -> f2#(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84]
R = 
  f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) 
  f10(I0, I1, I2, I3, I4, I5) -> f4(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5]
  f5(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9]
  f5(I12, I13, I14, I15, I16, I17) -> f9(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13]
  f5(I18, I19, I20, I21, I22, I23) -> f8(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21]
  f9(I24, I25, I26, I27, I28, I29) -> f8(I24, I25, I26, I27, I28, I29) 
  f9(I30, I31, I32, I33, I34, I35) -> f2(I30, 1 + I31, I32, I33, I34, I35) 
  f7(I36, I37, I38, I39, I40, I41) -> f6(I36, I37, I38, I39, I40, I41) 
  f8(I42, I43, I44, I45, I46, I47) -> f7(I42, -1 + I43, 0, I45, I46, I47) 
  f6(I48, I49, I50, I51, I52, I53) -> f7(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49]
  f6(I54, I55, I56, I57, I58, I59) -> f3(I54, I55, I56, I57, I58, I59) [I55 <= I56]
  f2(I60, I61, I62, I63, I64, I65) -> f5(I60, I61, I62, I63, I64, I65) 
  f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, I68, I69, I70, I71) [I69 <= 0]
  f4(I72, I73, I74, I75, I76, I77) -> f1(I72, I73, I74, I75, I76, I77) [1 <= I75]
  f1(I78, I79, I80, I81, I82, I83) -> f3(I78, I79, I80, I81, I82, I83) [1 + I78 <= I81]
  f1(I84, I85, I86, I87, I88, I89) -> f2(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84]

The dependency graph for this problem is:
  0 -> 1
  1 -> 11
  2 -> 5, 6
  3 -> 5, 6
  4 -> 8
  5 -> 8
  6 -> 10
  7 -> 9
  8 -> 7
  9 -> 7
  10 -> 2, 3, 4
  11 -> 12
  12 -> 10
Where:
  0) f11#(x1, x2, x3, x4, x5, x6) -> f10#(x1, x2, x3, x4, x5, x6) 
  1) f10#(I0, I1, I2, I3, I4, I5) -> f4#(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5]
  2) f5#(I6, I7, I8, I9, I10, I11) -> f9#(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9]
  3) f5#(I12, I13, I14, I15, I16, I17) -> f9#(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13]
  4) f5#(I18, I19, I20, I21, I22, I23) -> f8#(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21]
  5) f9#(I24, I25, I26, I27, I28, I29) -> f8#(I24, I25, I26, I27, I28, I29) 
  6) f9#(I30, I31, I32, I33, I34, I35) -> f2#(I30, 1 + I31, I32, I33, I34, I35) 
  7) f7#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) 
  8) f8#(I42, I43, I44, I45, I46, I47) -> f7#(I42, -1 + I43, 0, I45, I46, I47) 
  9) f6#(I48, I49, I50, I51, I52, I53) -> f7#(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49]
  10) f2#(I60, I61, I62, I63, I64, I65) -> f5#(I60, I61, I62, I63, I64, I65) 
  11) f4#(I72, I73, I74, I75, I76, I77) -> f1#(I72, I73, I74, I75, I76, I77) [1 <= I75]
  12) f1#(I84, I85, I86, I87, I88, I89) -> f2#(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84]

We have the following SCCs.
  { 2, 3, 6, 10 }
  { 7, 9 }

DP problem for innermost termination.
P =
  f7#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) 
  f6#(I48, I49, I50, I51, I52, I53) -> f7#(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49]
R = 
  f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) 
  f10(I0, I1, I2, I3, I4, I5) -> f4(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5]
  f5(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9]
  f5(I12, I13, I14, I15, I16, I17) -> f9(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13]
  f5(I18, I19, I20, I21, I22, I23) -> f8(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21]
  f9(I24, I25, I26, I27, I28, I29) -> f8(I24, I25, I26, I27, I28, I29) 
  f9(I30, I31, I32, I33, I34, I35) -> f2(I30, 1 + I31, I32, I33, I34, I35) 
  f7(I36, I37, I38, I39, I40, I41) -> f6(I36, I37, I38, I39, I40, I41) 
  f8(I42, I43, I44, I45, I46, I47) -> f7(I42, -1 + I43, 0, I45, I46, I47) 
  f6(I48, I49, I50, I51, I52, I53) -> f7(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49]
  f6(I54, I55, I56, I57, I58, I59) -> f3(I54, I55, I56, I57, I58, I59) [I55 <= I56]
  f2(I60, I61, I62, I63, I64, I65) -> f5(I60, I61, I62, I63, I64, I65) 
  f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, I68, I69, I70, I71) [I69 <= 0]
  f4(I72, I73, I74, I75, I76, I77) -> f1(I72, I73, I74, I75, I76, I77) [1 <= I75]
  f1(I78, I79, I80, I81, I82, I83) -> f3(I78, I79, I80, I81, I82, I83) [1 + I78 <= I81]
  f1(I84, I85, I86, I87, I88, I89) -> f2(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84]

We use the reverse value criterion with the projection function NU:
  NU[f6#(z1,z2,z3,z4,z5,z6)] = z2 + -1 * (1 + z3)
  NU[f7#(z1,z2,z3,z4,z5,z6)] = z2 + -1 * (1 + z3)

This gives the following inequalities:
    ==>  I37 + -1 * (1 + I38) >= I37 + -1 * (1 + I38)
  1 + I50 <= I49  ==>  I49 + -1 * (1 + I50) > I49 + -1 * (1 + (1 + I50))  with  I49 + -1 * (1 + I50) >= 0

We remove all the strictly oriented dependency pairs.

DP problem for innermost termination.
P =
  f7#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) 
R = 
  f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) 
  f10(I0, I1, I2, I3, I4, I5) -> f4(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5]
  f5(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9]
  f5(I12, I13, I14, I15, I16, I17) -> f9(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13]
  f5(I18, I19, I20, I21, I22, I23) -> f8(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21]
  f9(I24, I25, I26, I27, I28, I29) -> f8(I24, I25, I26, I27, I28, I29) 
  f9(I30, I31, I32, I33, I34, I35) -> f2(I30, 1 + I31, I32, I33, I34, I35) 
  f7(I36, I37, I38, I39, I40, I41) -> f6(I36, I37, I38, I39, I40, I41) 
  f8(I42, I43, I44, I45, I46, I47) -> f7(I42, -1 + I43, 0, I45, I46, I47) 
  f6(I48, I49, I50, I51, I52, I53) -> f7(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49]
  f6(I54, I55, I56, I57, I58, I59) -> f3(I54, I55, I56, I57, I58, I59) [I55 <= I56]
  f2(I60, I61, I62, I63, I64, I65) -> f5(I60, I61, I62, I63, I64, I65) 
  f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, I68, I69, I70, I71) [I69 <= 0]
  f4(I72, I73, I74, I75, I76, I77) -> f1(I72, I73, I74, I75, I76, I77) [1 <= I75]
  f1(I78, I79, I80, I81, I82, I83) -> f3(I78, I79, I80, I81, I82, I83) [1 + I78 <= I81]
  f1(I84, I85, I86, I87, I88, I89) -> f2(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84]

The dependency graph for this problem is:
  7 -> 
Where:
  7) f7#(I36, I37, I38, I39, I40, I41) -> f6#(I36, I37, I38, I39, I40, I41) 

We have the following SCCs.
  

DP problem for innermost termination.
P =
  f5#(I6, I7, I8, I9, I10, I11) -> f9#(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9]
  f5#(I12, I13, I14, I15, I16, I17) -> f9#(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13]
  f9#(I30, I31, I32, I33, I34, I35) -> f2#(I30, 1 + I31, I32, I33, I34, I35) 
  f2#(I60, I61, I62, I63, I64, I65) -> f5#(I60, I61, I62, I63, I64, I65) 
R = 
  f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) 
  f10(I0, I1, I2, I3, I4, I5) -> f4(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5]
  f5(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9]
  f5(I12, I13, I14, I15, I16, I17) -> f9(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13]
  f5(I18, I19, I20, I21, I22, I23) -> f8(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21]
  f9(I24, I25, I26, I27, I28, I29) -> f8(I24, I25, I26, I27, I28, I29) 
  f9(I30, I31, I32, I33, I34, I35) -> f2(I30, 1 + I31, I32, I33, I34, I35) 
  f7(I36, I37, I38, I39, I40, I41) -> f6(I36, I37, I38, I39, I40, I41) 
  f8(I42, I43, I44, I45, I46, I47) -> f7(I42, -1 + I43, 0, I45, I46, I47) 
  f6(I48, I49, I50, I51, I52, I53) -> f7(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49]
  f6(I54, I55, I56, I57, I58, I59) -> f3(I54, I55, I56, I57, I58, I59) [I55 <= I56]
  f2(I60, I61, I62, I63, I64, I65) -> f5(I60, I61, I62, I63, I64, I65) 
  f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, I68, I69, I70, I71) [I69 <= 0]
  f4(I72, I73, I74, I75, I76, I77) -> f1(I72, I73, I74, I75, I76, I77) [1 <= I75]
  f1(I78, I79, I80, I81, I82, I83) -> f3(I78, I79, I80, I81, I82, I83) [1 + I78 <= I81]
  f1(I84, I85, I86, I87, I88, I89) -> f2(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84]

We use the extended value criterion with the projection function NU:
  NU[f2#(x0,x1,x2,x3,x4,x5)] = -x1 + x3 - 1
  NU[f9#(x0,x1,x2,x3,x4,x5)] = -x1 + x3 - 2
  NU[f5#(x0,x1,x2,x3,x4,x5)] = -x1 + x3 - 1

This gives the following inequalities:
  1 + I7 <= I9  ==>  -I7 + I9 - 1 > -I7 + I9 - 2  with  -I7 + I9 - 1 >= 0
  1 + I15 <= I13  ==>  -I13 + I15 - 1 >= -I13 + I15 - 2
    ==>  -I31 + I33 - 2 >= -(1 + I31) + I33 - 1
    ==>  -I61 + I63 - 1 >= -I61 + I63 - 1

We remove all the strictly oriented dependency pairs.

DP problem for innermost termination.
P =
  f5#(I12, I13, I14, I15, I16, I17) -> f9#(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13]
  f9#(I30, I31, I32, I33, I34, I35) -> f2#(I30, 1 + I31, I32, I33, I34, I35) 
  f2#(I60, I61, I62, I63, I64, I65) -> f5#(I60, I61, I62, I63, I64, I65) 
R = 
  f11(x1, x2, x3, x4, x5, x6) -> f10(x1, x2, x3, x4, x5, x6) 
  f10(I0, I1, I2, I3, I4, I5) -> f4(I0, I1, I2, rnd4, rnd5, I5) [rnd4 = rnd5 /\ rnd5 = rnd5]
  f5(I6, I7, I8, I9, I10, I11) -> f9(I6, I7, I8, I9, I10, I11) [1 + I7 <= I9]
  f5(I12, I13, I14, I15, I16, I17) -> f9(I12, I13, I14, I15, I16, I17) [1 + I15 <= I13]
  f5(I18, I19, I20, I21, I22, I23) -> f8(I18, I19, I20, I21, I22, I23) [I21 <= I19 /\ I19 <= I21]
  f9(I24, I25, I26, I27, I28, I29) -> f8(I24, I25, I26, I27, I28, I29) 
  f9(I30, I31, I32, I33, I34, I35) -> f2(I30, 1 + I31, I32, I33, I34, I35) 
  f7(I36, I37, I38, I39, I40, I41) -> f6(I36, I37, I38, I39, I40, I41) 
  f8(I42, I43, I44, I45, I46, I47) -> f7(I42, -1 + I43, 0, I45, I46, I47) 
  f6(I48, I49, I50, I51, I52, I53) -> f7(I48, I49, 1 + I50, I51, I52, I53) [1 + I50 <= I49]
  f6(I54, I55, I56, I57, I58, I59) -> f3(I54, I55, I56, I57, I58, I59) [I55 <= I56]
  f2(I60, I61, I62, I63, I64, I65) -> f5(I60, I61, I62, I63, I64, I65) 
  f4(I66, I67, I68, I69, I70, I71) -> f3(I66, I67, I68, I69, I70, I71) [I69 <= 0]
  f4(I72, I73, I74, I75, I76, I77) -> f1(I72, I73, I74, I75, I76, I77) [1 <= I75]
  f1(I78, I79, I80, I81, I82, I83) -> f3(I78, I79, I80, I81, I82, I83) [1 + I78 <= I81]
  f1(I84, I85, I86, I87, I88, I89) -> f2(I84, 0, I86, I87, I88, rnd6) [rnd6 = rnd6 /\ I87 <= I84]