/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 
  f3#(I0, I1, I2) -> f2#(I0, I0 - 1, I1 + 1) [I1 = I2 /\ -1 <= I0 - 1]
  f2#(I3, I4, I5) -> f3#(I3, I5, I5) [I5 <= I4]
  f2#(I6, I7, I8) -> f3#(I6, I7, I8) [I7 <= I8 - 1]
  f1#(I9, I10, I11) -> f2#(I12, I13, I14) [I12 - 1 = I13 /\ 0 <= I9 - 1 /\ -1 <= I14 - 1 /\ -1 <= I10 - 1 /\ -1 <= I12 - 1]
R = 
  init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) 
  f3(I0, I1, I2) -> f2(I0, I0 - 1, I1 + 1) [I1 = I2 /\ -1 <= I0 - 1]
  f2(I3, I4, I5) -> f3(I3, I5, I5) [I5 <= I4]
  f2(I6, I7, I8) -> f3(I6, I7, I8) [I7 <= I8 - 1]
  f1(I9, I10, I11) -> f2(I12, I13, I14) [I12 - 1 = I13 /\ 0 <= I9 - 1 /\ -1 <= I14 - 1 /\ -1 <= I10 - 1 /\ -1 <= I12 - 1]

The dependency graph for this problem is:
  0 -> 4
  1 -> 2, 3
  2 -> 1
  3 -> 
  4 -> 2, 3
Where:
  0) init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 
  1) f3#(I0, I1, I2) -> f2#(I0, I0 - 1, I1 + 1) [I1 = I2 /\ -1 <= I0 - 1]
  2) f2#(I3, I4, I5) -> f3#(I3, I5, I5) [I5 <= I4]
  3) f2#(I6, I7, I8) -> f3#(I6, I7, I8) [I7 <= I8 - 1]
  4) f1#(I9, I10, I11) -> f2#(I12, I13, I14) [I12 - 1 = I13 /\ 0 <= I9 - 1 /\ -1 <= I14 - 1 /\ -1 <= I10 - 1 /\ -1 <= I12 - 1]

We have the following SCCs.
  { 1, 2 }

DP problem for innermost termination.
P =
  f3#(I0, I1, I2) -> f2#(I0, I0 - 1, I1 + 1) [I1 = I2 /\ -1 <= I0 - 1]
  f2#(I3, I4, I5) -> f3#(I3, I5, I5) [I5 <= I4]
R = 
  init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) 
  f3(I0, I1, I2) -> f2(I0, I0 - 1, I1 + 1) [I1 = I2 /\ -1 <= I0 - 1]
  f2(I3, I4, I5) -> f3(I3, I5, I5) [I5 <= I4]
  f2(I6, I7, I8) -> f3(I6, I7, I8) [I7 <= I8 - 1]
  f1(I9, I10, I11) -> f2(I12, I13, I14) [I12 - 1 = I13 /\ 0 <= I9 - 1 /\ -1 <= I14 - 1 /\ -1 <= I10 - 1 /\ -1 <= I12 - 1]