/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f7#(x1, x2, x3, x4, x5, x6, x7) -> f6#(x1, x2, x3, x4, x5, x6, x7) 
  f6#(I0, I1, I2, I3, I4, I5, I6) -> f3#(-1, 0, I2, I3, I4, 14, 8) 
  f2#(I7, I8, I9, I10, I11, I12, I13) -> f3#(I7, I8, I9, I10, I11, -1 + I9, I13) 
  f2#(I14, I15, I16, I17, I18, I19, I20) -> f3#(I14, 1 + I16, I16, I17, I18, I19, I20) 
  f3#(I21, I22, I23, I24, I25, I26, I27) -> f4#(I21, I22, I23, I24, I25, I26, I27) 
  f4#(I28, I29, I30, I31, I32, I33, I34) -> f1#(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
  f1#(I42, I43, I44, I45, I46, I47, I48) -> f2#(I42, I43, I44, I45, I46, I47, I48) 
  f1#(I49, I50, I51, I52, I53, I54, I55) -> f3#(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
  f1#(I56, I57, I58, I59, I60, I61, I62) -> f2#(I56, I57, I58, I59, I60, I61, I62) 
R = 
  f7(x1, x2, x3, x4, x5, x6, x7) -> f6(x1, x2, x3, x4, x5, x6, x7) 
  f6(I0, I1, I2, I3, I4, I5, I6) -> f3(-1, 0, I2, I3, I4, 14, 8) 
  f2(I7, I8, I9, I10, I11, I12, I13) -> f3(I7, I8, I9, I10, I11, -1 + I9, I13) 
  f2(I14, I15, I16, I17, I18, I19, I20) -> f3(I14, 1 + I16, I16, I17, I18, I19, I20) 
  f3(I21, I22, I23, I24, I25, I26, I27) -> f4(I21, I22, I23, I24, I25, I26, I27) 
  f4(I28, I29, I30, I31, I32, I33, I34) -> f1(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
  f4(I35, I36, I37, I38, I39, I40, I41) -> f5(I35, I36, I37, I35, I35, I40, I41) [1 + I40 <= I36]
  f1(I42, I43, I44, I45, I46, I47, I48) -> f2(I42, I43, I44, I45, I46, I47, I48) 
  f1(I49, I50, I51, I52, I53, I54, I55) -> f3(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
  f1(I56, I57, I58, I59, I60, I61, I62) -> f2(I56, I57, I58, I59, I60, I61, I62) 

The dependency graph for this problem is:
  0 -> 1
  1 -> 4
  2 -> 4
  3 -> 4
  4 -> 5
  5 -> 6, 7, 8
  6 -> 2, 3
  7 -> 4
  8 -> 2, 3
Where:
  0) f7#(x1, x2, x3, x4, x5, x6, x7) -> f6#(x1, x2, x3, x4, x5, x6, x7) 
  1) f6#(I0, I1, I2, I3, I4, I5, I6) -> f3#(-1, 0, I2, I3, I4, 14, 8) 
  2) f2#(I7, I8, I9, I10, I11, I12, I13) -> f3#(I7, I8, I9, I10, I11, -1 + I9, I13) 
  3) f2#(I14, I15, I16, I17, I18, I19, I20) -> f3#(I14, 1 + I16, I16, I17, I18, I19, I20) 
  4) f3#(I21, I22, I23, I24, I25, I26, I27) -> f4#(I21, I22, I23, I24, I25, I26, I27) 
  5) f4#(I28, I29, I30, I31, I32, I33, I34) -> f1#(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
  6) f1#(I42, I43, I44, I45, I46, I47, I48) -> f2#(I42, I43, I44, I45, I46, I47, I48) 
  7) f1#(I49, I50, I51, I52, I53, I54, I55) -> f3#(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
  8) f1#(I56, I57, I58, I59, I60, I61, I62) -> f2#(I56, I57, I58, I59, I60, I61, I62) 

We have the following SCCs.
  { 2, 3, 4, 5, 6, 7, 8 }

DP problem for innermost termination.
P =
  f2#(I7, I8, I9, I10, I11, I12, I13) -> f3#(I7, I8, I9, I10, I11, -1 + I9, I13) 
  f2#(I14, I15, I16, I17, I18, I19, I20) -> f3#(I14, 1 + I16, I16, I17, I18, I19, I20) 
  f3#(I21, I22, I23, I24, I25, I26, I27) -> f4#(I21, I22, I23, I24, I25, I26, I27) 
  f4#(I28, I29, I30, I31, I32, I33, I34) -> f1#(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
  f1#(I42, I43, I44, I45, I46, I47, I48) -> f2#(I42, I43, I44, I45, I46, I47, I48) 
  f1#(I49, I50, I51, I52, I53, I54, I55) -> f3#(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
  f1#(I56, I57, I58, I59, I60, I61, I62) -> f2#(I56, I57, I58, I59, I60, I61, I62) 
R = 
  f7(x1, x2, x3, x4, x5, x6, x7) -> f6(x1, x2, x3, x4, x5, x6, x7) 
  f6(I0, I1, I2, I3, I4, I5, I6) -> f3(-1, 0, I2, I3, I4, 14, 8) 
  f2(I7, I8, I9, I10, I11, I12, I13) -> f3(I7, I8, I9, I10, I11, -1 + I9, I13) 
  f2(I14, I15, I16, I17, I18, I19, I20) -> f3(I14, 1 + I16, I16, I17, I18, I19, I20) 
  f3(I21, I22, I23, I24, I25, I26, I27) -> f4(I21, I22, I23, I24, I25, I26, I27) 
  f4(I28, I29, I30, I31, I32, I33, I34) -> f1(I28, I29, rnd3, I31, I32, I33, I34) [rnd3 = rnd3 /\ I29 <= I33]
  f4(I35, I36, I37, I38, I39, I40, I41) -> f5(I35, I36, I37, I35, I35, I40, I41) [1 + I40 <= I36]
  f1(I42, I43, I44, I45, I46, I47, I48) -> f2(I42, I43, I44, I45, I46, I47, I48) 
  f1(I49, I50, I51, I52, I53, I54, I55) -> f3(rnd1, I50, I51, I52, I53, -1 + I50, I55) [rnd1 = rnd1]
  f1(I56, I57, I58, I59, I60, I61, I62) -> f2(I56, I57, I58, I59, I60, I61, I62)