/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  init#(x1, x2) -> f1#(rnd1, rnd2) 
  f2#(I0, I1) -> f2#(-1 * I0 - 1, I2) [5 <= I0 - 1]
  f2#(I3, I4) -> f2#(0, I5) [0 <= I3 - 1 /\ I3 <= 5]
  f2#(I6, I7) -> f2#(0, I8) [I6 <= -1 /\ -6 <= I6 - 1 /\ I6 <= 5]
  f2#(I9, I10) -> f2#(-1 * I9 + 1, I11) [0 <= I9 - 1 /\ I9 <= -5 - 1 /\ I9 <= 1]
  f2#(I12, I13) -> f2#(-1 * I12 + 1, I14) [I12 <= -1 /\ I12 <= -5 - 1 /\ I12 <= 1]
  f1#(I15, I16) -> f2#(I16, I17) [-1 <= I16 - 1 /\ 0 <= I15 - 1]
R = 
  init(x1, x2) -> f1(rnd1, rnd2) 
  f2(I0, I1) -> f2(-1 * I0 - 1, I2) [5 <= I0 - 1]
  f2(I3, I4) -> f2(0, I5) [0 <= I3 - 1 /\ I3 <= 5]
  f2(I6, I7) -> f2(0, I8) [I6 <= -1 /\ -6 <= I6 - 1 /\ I6 <= 5]
  f2(I9, I10) -> f2(-1 * I9 + 1, I11) [0 <= I9 - 1 /\ I9 <= -5 - 1 /\ I9 <= 1]
  f2(I12, I13) -> f2(-1 * I12 + 1, I14) [I12 <= -1 /\ I12 <= -5 - 1 /\ I12 <= 1]
  f1(I15, I16) -> f2(I16, I17) [-1 <= I16 - 1 /\ 0 <= I15 - 1]

The dependency graph for this problem is:
  0 -> 6
  1 -> 5
  2 -> 
  3 -> 
  4 -> 
  5 -> 1
  6 -> 1, 2
Where:
  0) init#(x1, x2) -> f1#(rnd1, rnd2) 
  1) f2#(I0, I1) -> f2#(-1 * I0 - 1, I2) [5 <= I0 - 1]
  2) f2#(I3, I4) -> f2#(0, I5) [0 <= I3 - 1 /\ I3 <= 5]
  3) f2#(I6, I7) -> f2#(0, I8) [I6 <= -1 /\ -6 <= I6 - 1 /\ I6 <= 5]
  4) f2#(I9, I10) -> f2#(-1 * I9 + 1, I11) [0 <= I9 - 1 /\ I9 <= -5 - 1 /\ I9 <= 1]
  5) f2#(I12, I13) -> f2#(-1 * I12 + 1, I14) [I12 <= -1 /\ I12 <= -5 - 1 /\ I12 <= 1]
  6) f1#(I15, I16) -> f2#(I16, I17) [-1 <= I16 - 1 /\ 0 <= I15 - 1]

We have the following SCCs.
  { 1, 5 }

DP problem for innermost termination.
P =
  f2#(I0, I1) -> f2#(-1 * I0 - 1, I2) [5 <= I0 - 1]
  f2#(I12, I13) -> f2#(-1 * I12 + 1, I14) [I12 <= -1 /\ I12 <= -5 - 1 /\ I12 <= 1]
R = 
  init(x1, x2) -> f1(rnd1, rnd2) 
  f2(I0, I1) -> f2(-1 * I0 - 1, I2) [5 <= I0 - 1]
  f2(I3, I4) -> f2(0, I5) [0 <= I3 - 1 /\ I3 <= 5]
  f2(I6, I7) -> f2(0, I8) [I6 <= -1 /\ -6 <= I6 - 1 /\ I6 <= 5]
  f2(I9, I10) -> f2(-1 * I9 + 1, I11) [0 <= I9 - 1 /\ I9 <= -5 - 1 /\ I9 <= 1]
  f2(I12, I13) -> f2(-1 * I12 + 1, I14) [I12 <= -1 /\ I12 <= -5 - 1 /\ I12 <= 1]
  f1(I15, I16) -> f2(I16, I17) [-1 <= I16 - 1 /\ 0 <= I15 - 1]