/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f14#(x1, x2, x3) -> f13#(x1, x2, x3) 
  f13#(I0, I1, I2) -> f4#(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1]
  f3#(I3, I4, I5) -> f5#(1 + I3, I4, I5) [I3 <= I4]
  f3#(I6, I7, I8) -> f5#(1 + I6, I7, I8) [1 + I7 <= I6]
  f2#(I9, I10, I11) -> f3#(I9, I10, I11) [1 + I11 <= 0]
  f2#(I12, I13, I14) -> f3#(I12, I13, I14) [1 <= I14]
  f2#(I15, I16, I17) -> f6#(I15, I16, I17) [0 <= I17 /\ I17 <= 0]
  f7#(I18, I19, I20) -> f6#(-1 + I18, I19, I20) [3 <= I18]
  f7#(I21, I22, I23) -> f4#(I21, I22, I23) [I21 <= 2]
  f12#(I24, I25, I26) -> f11#(I24, I25, I26) 
  f11#(I27, I28, I29) -> f12#(I27, I28, I29) 
  f10#(I30, I31, I32) -> f11#(I30, I31, I32) 
  f6#(I36, I37, I38) -> f7#(I36, I37, I38) 
  f5#(I39, I40, I41) -> f1#(I39, I40, I41) 
  f4#(I42, I43, I44) -> f5#(I42, I43, I44) 
  f1#(I45, I46, I47) -> f3#(I45, I46, I47) [I45 <= I46]
  f1#(I48, I49, I50) -> f2#(I48, I49, rnd3) [rnd3 = rnd3 /\ 1 + I49 <= I48]
R = 
  f14(x1, x2, x3) -> f13(x1, x2, x3) 
  f13(I0, I1, I2) -> f4(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1]
  f3(I3, I4, I5) -> f5(1 + I3, I4, I5) [I3 <= I4]
  f3(I6, I7, I8) -> f5(1 + I6, I7, I8) [1 + I7 <= I6]
  f2(I9, I10, I11) -> f3(I9, I10, I11) [1 + I11 <= 0]
  f2(I12, I13, I14) -> f3(I12, I13, I14) [1 <= I14]
  f2(I15, I16, I17) -> f6(I15, I16, I17) [0 <= I17 /\ I17 <= 0]
  f7(I18, I19, I20) -> f6(-1 + I18, I19, I20) [3 <= I18]
  f7(I21, I22, I23) -> f4(I21, I22, I23) [I21 <= 2]
  f12(I24, I25, I26) -> f11(I24, I25, I26) 
  f11(I27, I28, I29) -> f12(I27, I28, I29) 
  f10(I30, I31, I32) -> f11(I30, I31, I32) 
  f8(I33, I34, I35) -> f9(I33, I34, I35) 
  f6(I36, I37, I38) -> f7(I36, I37, I38) 
  f5(I39, I40, I41) -> f1(I39, I40, I41) 
  f4(I42, I43, I44) -> f5(I42, I43, I44) 
  f1(I45, I46, I47) -> f3(I45, I46, I47) [I45 <= I46]
  f1(I48, I49, I50) -> f2(I48, I49, rnd3) [rnd3 = rnd3 /\ 1 + I49 <= I48]

The dependency graph for this problem is:
  0 -> 1
  1 -> 14
  2 -> 13
  3 -> 13
  4 -> 2, 3
  5 -> 2, 3
  6 -> 12
  7 -> 12
  8 -> 14
  9 -> 10
  10 -> 9
  11 -> 10
  12 -> 7, 8
  13 -> 15, 16
  14 -> 13
  15 -> 2
  16 -> 4, 5, 6
Where:
  0) f14#(x1, x2, x3) -> f13#(x1, x2, x3) 
  1) f13#(I0, I1, I2) -> f4#(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1]
  2) f3#(I3, I4, I5) -> f5#(1 + I3, I4, I5) [I3 <= I4]
  3) f3#(I6, I7, I8) -> f5#(1 + I6, I7, I8) [1 + I7 <= I6]
  4) f2#(I9, I10, I11) -> f3#(I9, I10, I11) [1 + I11 <= 0]
  5) f2#(I12, I13, I14) -> f3#(I12, I13, I14) [1 <= I14]
  6) f2#(I15, I16, I17) -> f6#(I15, I16, I17) [0 <= I17 /\ I17 <= 0]
  7) f7#(I18, I19, I20) -> f6#(-1 + I18, I19, I20) [3 <= I18]
  8) f7#(I21, I22, I23) -> f4#(I21, I22, I23) [I21 <= 2]
  9) f12#(I24, I25, I26) -> f11#(I24, I25, I26) 
  10) f11#(I27, I28, I29) -> f12#(I27, I28, I29) 
  11) f10#(I30, I31, I32) -> f11#(I30, I31, I32) 
  12) f6#(I36, I37, I38) -> f7#(I36, I37, I38) 
  13) f5#(I39, I40, I41) -> f1#(I39, I40, I41) 
  14) f4#(I42, I43, I44) -> f5#(I42, I43, I44) 
  15) f1#(I45, I46, I47) -> f3#(I45, I46, I47) [I45 <= I46]
  16) f1#(I48, I49, I50) -> f2#(I48, I49, rnd3) [rnd3 = rnd3 /\ 1 + I49 <= I48]

We have the following SCCs.
  { 9, 10 }
  { 2, 3, 4, 5, 6, 7, 8, 12, 13, 14, 15, 16 }

DP problem for innermost termination.
P =
  f3#(I3, I4, I5) -> f5#(1 + I3, I4, I5) [I3 <= I4]
  f3#(I6, I7, I8) -> f5#(1 + I6, I7, I8) [1 + I7 <= I6]
  f2#(I9, I10, I11) -> f3#(I9, I10, I11) [1 + I11 <= 0]
  f2#(I12, I13, I14) -> f3#(I12, I13, I14) [1 <= I14]
  f2#(I15, I16, I17) -> f6#(I15, I16, I17) [0 <= I17 /\ I17 <= 0]
  f7#(I18, I19, I20) -> f6#(-1 + I18, I19, I20) [3 <= I18]
  f7#(I21, I22, I23) -> f4#(I21, I22, I23) [I21 <= 2]
  f6#(I36, I37, I38) -> f7#(I36, I37, I38) 
  f5#(I39, I40, I41) -> f1#(I39, I40, I41) 
  f4#(I42, I43, I44) -> f5#(I42, I43, I44) 
  f1#(I45, I46, I47) -> f3#(I45, I46, I47) [I45 <= I46]
  f1#(I48, I49, I50) -> f2#(I48, I49, rnd3) [rnd3 = rnd3 /\ 1 + I49 <= I48]
R = 
  f14(x1, x2, x3) -> f13(x1, x2, x3) 
  f13(I0, I1, I2) -> f4(rnd1, I1, I2) [y1 = y1 /\ rnd1 = rnd1]
  f3(I3, I4, I5) -> f5(1 + I3, I4, I5) [I3 <= I4]
  f3(I6, I7, I8) -> f5(1 + I6, I7, I8) [1 + I7 <= I6]
  f2(I9, I10, I11) -> f3(I9, I10, I11) [1 + I11 <= 0]
  f2(I12, I13, I14) -> f3(I12, I13, I14) [1 <= I14]
  f2(I15, I16, I17) -> f6(I15, I16, I17) [0 <= I17 /\ I17 <= 0]
  f7(I18, I19, I20) -> f6(-1 + I18, I19, I20) [3 <= I18]
  f7(I21, I22, I23) -> f4(I21, I22, I23) [I21 <= 2]
  f12(I24, I25, I26) -> f11(I24, I25, I26) 
  f11(I27, I28, I29) -> f12(I27, I28, I29) 
  f10(I30, I31, I32) -> f11(I30, I31, I32) 
  f8(I33, I34, I35) -> f9(I33, I34, I35) 
  f6(I36, I37, I38) -> f7(I36, I37, I38) 
  f5(I39, I40, I41) -> f1(I39, I40, I41) 
  f4(I42, I43, I44) -> f5(I42, I43, I44) 
  f1(I45, I46, I47) -> f3(I45, I46, I47) [I45 <= I46]
  f1(I48, I49, I50) -> f2(I48, I49, rnd3) [rnd3 = rnd3 /\ 1 + I49 <= I48]