/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f3#(I0, I1) -> f2#(I2, I3) [I0 <= 14 /\ I0 + 1 - 10 * y1 <= 9 /\ 0 <= I0 + 1 - 10 * y1 /\ I0 + 1 - 10 * y1 = I2] f2#(I4, I5) -> f3#(I4, I6) [I4 <= 14] f1#(I7, I8) -> f2#(I8, I9) [-1 <= I8 - 1 /\ 0 <= I7 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f3(I0, I1) -> f2(I2, I3) [I0 <= 14 /\ I0 + 1 - 10 * y1 <= 9 /\ 0 <= I0 + 1 - 10 * y1 /\ I0 + 1 - 10 * y1 = I2] f2(I4, I5) -> f3(I4, I6) [I4 <= 14] f1(I7, I8) -> f2(I8, I9) [-1 <= I8 - 1 /\ 0 <= I7 - 1] The dependency graph for this problem is: 0 -> 3 1 -> 2 2 -> 1 3 -> 2 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f3#(I0, I1) -> f2#(I2, I3) [I0 <= 14 /\ I0 + 1 - 10 * y1 <= 9 /\ 0 <= I0 + 1 - 10 * y1 /\ I0 + 1 - 10 * y1 = I2] 2) f2#(I4, I5) -> f3#(I4, I6) [I4 <= 14] 3) f1#(I7, I8) -> f2#(I8, I9) [-1 <= I8 - 1 /\ 0 <= I7 - 1] We have the following SCCs. { 1, 2 } DP problem for innermost termination. P = f3#(I0, I1) -> f2#(I2, I3) [I0 <= 14 /\ I0 + 1 - 10 * y1 <= 9 /\ 0 <= I0 + 1 - 10 * y1 /\ I0 + 1 - 10 * y1 = I2] f2#(I4, I5) -> f3#(I4, I6) [I4 <= 14] R = init(x1, x2) -> f1(rnd1, rnd2) f3(I0, I1) -> f2(I2, I3) [I0 <= 14 /\ I0 + 1 - 10 * y1 <= 9 /\ 0 <= I0 + 1 - 10 * y1 /\ I0 + 1 - 10 * y1 = I2] f2(I4, I5) -> f3(I4, I6) [I4 <= 14] f1(I7, I8) -> f2(I8, I9) [-1 <= I8 - 1 /\ 0 <= I7 - 1]