/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f6#(x1, x2) -> f5#(x1, x2) 
  f5#(I0, I1) -> f1#(I0, I1) [I0 <= I1 /\ I1 <= I0]
  f3#(I4, I5) -> f1#(I4, I5) 
  f1#(I6, I7) -> f3#(1 + I6, 1 + I7) 
R = 
  f6(x1, x2) -> f5(x1, x2) 
  f5(I0, I1) -> f1(I0, I1) [I0 <= I1 /\ I1 <= I0]
  f1(I2, I3) -> f4(I2, I3) 
  f3(I4, I5) -> f1(I4, I5) 
  f1(I6, I7) -> f3(1 + I6, 1 + I7) 
  f1(I8, I9) -> f2(I8, I9) [1 + I9 <= I8]

The dependency graph for this problem is:
  0 -> 1
  1 -> 3
  2 -> 3
  3 -> 2
Where:
  0) f6#(x1, x2) -> f5#(x1, x2) 
  1) f5#(I0, I1) -> f1#(I0, I1) [I0 <= I1 /\ I1 <= I0]
  2) f3#(I4, I5) -> f1#(I4, I5) 
  3) f1#(I6, I7) -> f3#(1 + I6, 1 + I7) 

We have the following SCCs.
  { 2, 3 }

DP problem for innermost termination.
P =
  f3#(I4, I5) -> f1#(I4, I5) 
  f1#(I6, I7) -> f3#(1 + I6, 1 + I7) 
R = 
  f6(x1, x2) -> f5(x1, x2) 
  f5(I0, I1) -> f1(I0, I1) [I0 <= I1 /\ I1 <= I0]
  f1(I2, I3) -> f4(I2, I3) 
  f3(I4, I5) -> f1(I4, I5) 
  f1(I6, I7) -> f3(1 + I6, 1 + I7) 
  f1(I8, I9) -> f2(I8, I9) [1 + I9 <= I8]