/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  init#(x1, x2) -> f1#(rnd1, rnd2) 
  f4#(I0, I1) -> f3#(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
  f3#(I3, I4) -> f4#(I3, I4) [0 <= I4 - 1]
  f2#(I5, I6) -> f3#(I7, I8) [-1 <= I6 - 1 /\ -1 <= I7 - 1 /\ 0 <= I5 - 1 /\ I7 - 3 * I9 <= 2 /\ 0 <= I7 - 3 * I9 /\ I7 - 3 * I9 = I8]
  f1#(I10, I11) -> f2#(I10, I11) [-1 <= I11 - 1 /\ -1 <= I12 - 1 /\ 0 <= I10 - 1]
R = 
  init(x1, x2) -> f1(rnd1, rnd2) 
  f4(I0, I1) -> f3(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
  f3(I3, I4) -> f4(I3, I4) [0 <= I4 - 1]
  f2(I5, I6) -> f3(I7, I8) [-1 <= I6 - 1 /\ -1 <= I7 - 1 /\ 0 <= I5 - 1 /\ I7 - 3 * I9 <= 2 /\ 0 <= I7 - 3 * I9 /\ I7 - 3 * I9 = I8]
  f1(I10, I11) -> f2(I10, I11) [-1 <= I11 - 1 /\ -1 <= I12 - 1 /\ 0 <= I10 - 1]

The dependency graph for this problem is:
  0 -> 4
  1 -> 2
  2 -> 1
  3 -> 2
  4 -> 3
Where:
  0) init#(x1, x2) -> f1#(rnd1, rnd2) 
  1) f4#(I0, I1) -> f3#(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
  2) f3#(I3, I4) -> f4#(I3, I4) [0 <= I4 - 1]
  3) f2#(I5, I6) -> f3#(I7, I8) [-1 <= I6 - 1 /\ -1 <= I7 - 1 /\ 0 <= I5 - 1 /\ I7 - 3 * I9 <= 2 /\ 0 <= I7 - 3 * I9 /\ I7 - 3 * I9 = I8]
  4) f1#(I10, I11) -> f2#(I10, I11) [-1 <= I11 - 1 /\ -1 <= I12 - 1 /\ 0 <= I10 - 1]

We have the following SCCs.
  { 1, 2 }

DP problem for innermost termination.
P =
  f4#(I0, I1) -> f3#(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
  f3#(I3, I4) -> f4#(I3, I4) [0 <= I4 - 1]
R = 
  init(x1, x2) -> f1(rnd1, rnd2) 
  f4(I0, I1) -> f3(I0 + 1, I2) [0 <= I1 - 1 /\ I0 + 1 - 3 * y1 <= 2 /\ 0 <= I0 + 1 - 3 * y1 /\ I0 + 1 - 3 * y1 = I2]
  f3(I3, I4) -> f4(I3, I4) [0 <= I4 - 1]
  f2(I5, I6) -> f3(I7, I8) [-1 <= I6 - 1 /\ -1 <= I7 - 1 /\ 0 <= I5 - 1 /\ I7 - 3 * I9 <= 2 /\ 0 <= I7 - 3 * I9 /\ I7 - 3 * I9 = I8]
  f1(I10, I11) -> f2(I10, I11) [-1 <= I11 - 1 /\ -1 <= I12 - 1 /\ 0 <= I10 - 1]