/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f10#(x1, x2) -> f1#(x1, x2) 
  f9#(I2, I3) -> f2#(I2, I3) 
  f2#(I4, I5) -> f9#(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
  f6#(I11, I12) -> f7#(I11, I12) [14 <= I12]
  f6#(I13, I14) -> f7#(I13, I14) [1 + I14 <= 13]
  f2#(I15, I16) -> f6#(I15, -1 + I16) 
  f5#(I17, I18) -> f2#(I17, I18) 
  f4#(I19, I20) -> f5#(I19, I20) [-1 * I20 <= 0]
  f3#(I21, I22) -> f4#(I21, I22) [14 <= I22]
  f3#(I23, I24) -> f4#(I23, I24) [1 + I24 <= 13]
  f2#(I25, I26) -> f3#(I25, -1 + I26) 
  f1#(I27, I28) -> f2#(I27, I28) 
R = 
  f10(x1, x2) -> f1(x1, x2) 
  f2(I0, I1) -> f8(rnd1, rnd2) [y1 = -1 + I1 /\ y1 <= 13 /\ 13 <= y1 /\ rnd2 = rnd2 /\ 0 <= -1 - rnd2 /\ rnd1 = rnd1]
  f9(I2, I3) -> f2(I2, I3) 
  f2(I4, I5) -> f9(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
  f7(I8, I9) -> f8(I10, I9) [I10 = I10 /\ 0 <= -1 - I9]
  f6(I11, I12) -> f7(I11, I12) [14 <= I12]
  f6(I13, I14) -> f7(I13, I14) [1 + I14 <= 13]
  f2(I15, I16) -> f6(I15, -1 + I16) 
  f5(I17, I18) -> f2(I17, I18) 
  f4(I19, I20) -> f5(I19, I20) [-1 * I20 <= 0]
  f3(I21, I22) -> f4(I21, I22) [14 <= I22]
  f3(I23, I24) -> f4(I23, I24) [1 + I24 <= 13]
  f2(I25, I26) -> f3(I25, -1 + I26) 
  f1(I27, I28) -> f2(I27, I28) 

The dependency graph for this problem is:
  0 -> 11
  1 -> 2, 5, 10
  2 -> 1
  3 -> 
  4 -> 
  5 -> 3, 4
  6 -> 2, 5, 10
  7 -> 6
  8 -> 7
  9 -> 7
  10 -> 8, 9
  11 -> 2, 5, 10
Where:
  0) f10#(x1, x2) -> f1#(x1, x2) 
  1) f9#(I2, I3) -> f2#(I2, I3) 
  2) f2#(I4, I5) -> f9#(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
  3) f6#(I11, I12) -> f7#(I11, I12) [14 <= I12]
  4) f6#(I13, I14) -> f7#(I13, I14) [1 + I14 <= 13]
  5) f2#(I15, I16) -> f6#(I15, -1 + I16) 
  6) f5#(I17, I18) -> f2#(I17, I18) 
  7) f4#(I19, I20) -> f5#(I19, I20) [-1 * I20 <= 0]
  8) f3#(I21, I22) -> f4#(I21, I22) [14 <= I22]
  9) f3#(I23, I24) -> f4#(I23, I24) [1 + I24 <= 13]
  10) f2#(I25, I26) -> f3#(I25, -1 + I26) 
  11) f1#(I27, I28) -> f2#(I27, I28) 

We have the following SCCs.
  { 1, 2, 6, 7, 8, 9, 10 }

DP problem for innermost termination.
P =
  f9#(I2, I3) -> f2#(I2, I3) 
  f2#(I4, I5) -> f9#(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
  f5#(I17, I18) -> f2#(I17, I18) 
  f4#(I19, I20) -> f5#(I19, I20) [-1 * I20 <= 0]
  f3#(I21, I22) -> f4#(I21, I22) [14 <= I22]
  f3#(I23, I24) -> f4#(I23, I24) [1 + I24 <= 13]
  f2#(I25, I26) -> f3#(I25, -1 + I26) 
R = 
  f10(x1, x2) -> f1(x1, x2) 
  f2(I0, I1) -> f8(rnd1, rnd2) [y1 = -1 + I1 /\ y1 <= 13 /\ 13 <= y1 /\ rnd2 = rnd2 /\ 0 <= -1 - rnd2 /\ rnd1 = rnd1]
  f9(I2, I3) -> f2(I2, I3) 
  f2(I4, I5) -> f9(I4, I6) [I7 = -1 + I5 /\ I7 <= 13 /\ 13 <= I7 /\ I6 = I6 /\ -1 * I6 <= 0]
  f7(I8, I9) -> f8(I10, I9) [I10 = I10 /\ 0 <= -1 - I9]
  f6(I11, I12) -> f7(I11, I12) [14 <= I12]
  f6(I13, I14) -> f7(I13, I14) [1 + I14 <= 13]
  f2(I15, I16) -> f6(I15, -1 + I16) 
  f5(I17, I18) -> f2(I17, I18) 
  f4(I19, I20) -> f5(I19, I20) [-1 * I20 <= 0]
  f3(I21, I22) -> f4(I21, I22) [14 <= I22]
  f3(I23, I24) -> f4(I23, I24) [1 + I24 <= 13]
  f2(I25, I26) -> f3(I25, -1 + I26) 
  f1(I27, I28) -> f2(I27, I28)