/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files


--------------------------------------------------------------------------------


YES

DP problem for innermost termination.
P =
  init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 
  f2#(I0, I1, I2) -> f2#(I3, I2 + 1, I2) [0 <= I3 - 1 /\ 0 <= I0 - 1 /\ I3 <= I0 /\ -1 <= I2 - 1 /\ I1 <= I2 - 1]
  f1#(I4, I5, I6) -> f2#(I7, I5 + 1, I5) [0 <= I7 - 1 /\ 0 <= I4 - 1 /\ -1 <= I5 - 1 /\ I7 <= I4]
R = 
  init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) 
  f2(I0, I1, I2) -> f2(I3, I2 + 1, I2) [0 <= I3 - 1 /\ 0 <= I0 - 1 /\ I3 <= I0 /\ -1 <= I2 - 1 /\ I1 <= I2 - 1]
  f1(I4, I5, I6) -> f2(I7, I5 + 1, I5) [0 <= I7 - 1 /\ 0 <= I4 - 1 /\ -1 <= I5 - 1 /\ I7 <= I4]

The dependency graph for this problem is:
  0 -> 2
  1 -> 
  2 -> 
Where:
  0) init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 
  1) f2#(I0, I1, I2) -> f2#(I3, I2 + 1, I2) [0 <= I3 - 1 /\ 0 <= I0 - 1 /\ I3 <= I0 /\ -1 <= I2 - 1 /\ I1 <= I2 - 1]
  2) f1#(I4, I5, I6) -> f2#(I7, I5 + 1, I5) [0 <= I7 - 1 /\ 0 <= I4 - 1 /\ -1 <= I5 - 1 /\ I7 <= I4]

We have the following SCCs.