/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f9#(x1, x2) -> f8#(x1, x2) 
  f8#(I0, I1) -> f2#(I0, 1) 
  f5#(I4, I5) -> f4#(I4, I5) 
  f4#(I6, I7) -> f5#(I6, I7) 
  f2#(I8, I9) -> f3#(rnd1, I9) [rnd1 = rnd1]
  f3#(I10, I11) -> f1#(I10, I11) [1 + I10 <= 0]
  f3#(I12, I13) -> f1#(I12, I13) [1 <= I12]
  f3#(I14, I15) -> f4#(I14, 1) [I14 <= 0 /\ 0 <= I14 /\ y1 = 0]
  f1#(I16, I17) -> f2#(I16, I17) 
R = 
  f9(x1, x2) -> f8(x1, x2) 
  f8(I0, I1) -> f2(I0, 1) 
  f6(I2, I3) -> f7(I2, I3) 
  f5(I4, I5) -> f4(I4, I5) 
  f4(I6, I7) -> f5(I6, I7) 
  f2(I8, I9) -> f3(rnd1, I9) [rnd1 = rnd1]
  f3(I10, I11) -> f1(I10, I11) [1 + I10 <= 0]
  f3(I12, I13) -> f1(I12, I13) [1 <= I12]
  f3(I14, I15) -> f4(I14, 1) [I14 <= 0 /\ 0 <= I14 /\ y1 = 0]
  f1(I16, I17) -> f2(I16, I17) 

The dependency graph for this problem is:
  0 -> 1
  1 -> 4
  2 -> 3
  3 -> 2
  4 -> 5, 6, 7
  5 -> 8
  6 -> 8
  7 -> 3
  8 -> 4
Where:
  0) f9#(x1, x2) -> f8#(x1, x2) 
  1) f8#(I0, I1) -> f2#(I0, 1) 
  2) f5#(I4, I5) -> f4#(I4, I5) 
  3) f4#(I6, I7) -> f5#(I6, I7) 
  4) f2#(I8, I9) -> f3#(rnd1, I9) [rnd1 = rnd1]
  5) f3#(I10, I11) -> f1#(I10, I11) [1 + I10 <= 0]
  6) f3#(I12, I13) -> f1#(I12, I13) [1 <= I12]
  7) f3#(I14, I15) -> f4#(I14, 1) [I14 <= 0 /\ 0 <= I14 /\ y1 = 0]
  8) f1#(I16, I17) -> f2#(I16, I17) 

We have the following SCCs.
  { 4, 5, 6, 8 }
  { 2, 3 }

DP problem for innermost termination.
P =
  f5#(I4, I5) -> f4#(I4, I5) 
  f4#(I6, I7) -> f5#(I6, I7) 
R = 
  f9(x1, x2) -> f8(x1, x2) 
  f8(I0, I1) -> f2(I0, 1) 
  f6(I2, I3) -> f7(I2, I3) 
  f5(I4, I5) -> f4(I4, I5) 
  f4(I6, I7) -> f5(I6, I7) 
  f2(I8, I9) -> f3(rnd1, I9) [rnd1 = rnd1]
  f3(I10, I11) -> f1(I10, I11) [1 + I10 <= 0]
  f3(I12, I13) -> f1(I12, I13) [1 <= I12]
  f3(I14, I15) -> f4(I14, 1) [I14 <= 0 /\ 0 <= I14 /\ y1 = 0]
  f1(I16, I17) -> f2(I16, I17)