/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files


--------------------------------------------------------------------------------


MAYBE

DP problem for innermost termination.
P =
  f8#(x1, x2, x3, x4, x5) -> f7#(x1, x2, x3, x4, x5) 
  f7#(I0, I1, I2, I3, I4) -> f1#(I0, I1, I2, I3, I4) 
  f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 
  f5#(I10, I11, I12, I13, I14) -> f6#(I10, I11, I12, -1 + I13, -1 + I13) 
  f4#(I15, I16, I17, I18, I19) -> f5#(I15, I16, I17, I18, I19) [I16 = I16]
  f1#(I20, I21, I22, I23, I24) -> f4#(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 + I23 + I24 /\ 0 <= -1 + I24 /\ 0 <= -1 + I23]
  f3#(I25, I26, I27, I28, I29) -> f1#(I25, I26, I27, I28, I29) 
  f1#(I30, I31, I32, I33, I34) -> f3#(I30, I31, I35, -2 + I34, 1 + -2 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 + I33 + I34 /\ 0 <= -1 + I34 /\ 0 <= -1 + I33]
R = 
  f8(x1, x2, x3, x4, x5) -> f7(x1, x2, x3, x4, x5) 
  f7(I0, I1, I2, I3, I4) -> f1(I0, I1, I2, I3, I4) 
  f6(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I9) 
  f5(I10, I11, I12, I13, I14) -> f6(I10, I11, I12, -1 + I13, -1 + I13) 
  f4(I15, I16, I17, I18, I19) -> f5(I15, I16, I17, I18, I19) [I16 = I16]
  f1(I20, I21, I22, I23, I24) -> f4(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 + I23 + I24 /\ 0 <= -1 + I24 /\ 0 <= -1 + I23]
  f3(I25, I26, I27, I28, I29) -> f1(I25, I26, I27, I28, I29) 
  f1(I30, I31, I32, I33, I34) -> f3(I30, I31, I35, -2 + I34, 1 + -2 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 + I33 + I34 /\ 0 <= -1 + I34 /\ 0 <= -1 + I33]
  f1(I36, I37, I38, I39, I40) -> f2(rnd1, I37, I38, I39, I40) [rnd1 = rnd1 /\ I39 + I40 <= 0 /\ 0 <= -1 + I40 /\ 0 <= -1 + I39]
  f1(I41, I42, I43, I44, I45) -> f2(I46, I42, I43, I44, I45) [I46 = I46 /\ I45 <= 0 /\ 0 <= -1 + I44]
  f1(I47, I48, I49, I50, I51) -> f2(I52, I48, I49, I50, I51) [I52 = I52 /\ I50 <= 0]

The dependency graph for this problem is:
  0 -> 1
  1 -> 5, 7
  2 -> 5, 7
  3 -> 2
  4 -> 3
  5 -> 4
  6 -> 5, 7
  7 -> 6
Where:
  0) f8#(x1, x2, x3, x4, x5) -> f7#(x1, x2, x3, x4, x5) 
  1) f7#(I0, I1, I2, I3, I4) -> f1#(I0, I1, I2, I3, I4) 
  2) f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 
  3) f5#(I10, I11, I12, I13, I14) -> f6#(I10, I11, I12, -1 + I13, -1 + I13) 
  4) f4#(I15, I16, I17, I18, I19) -> f5#(I15, I16, I17, I18, I19) [I16 = I16]
  5) f1#(I20, I21, I22, I23, I24) -> f4#(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 + I23 + I24 /\ 0 <= -1 + I24 /\ 0 <= -1 + I23]
  6) f3#(I25, I26, I27, I28, I29) -> f1#(I25, I26, I27, I28, I29) 
  7) f1#(I30, I31, I32, I33, I34) -> f3#(I30, I31, I35, -2 + I34, 1 + -2 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 + I33 + I34 /\ 0 <= -1 + I34 /\ 0 <= -1 + I33]

We have the following SCCs.
  { 2, 3, 4, 5, 6, 7 }

DP problem for innermost termination.
P =
  f6#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, I8, I9) 
  f5#(I10, I11, I12, I13, I14) -> f6#(I10, I11, I12, -1 + I13, -1 + I13) 
  f4#(I15, I16, I17, I18, I19) -> f5#(I15, I16, I17, I18, I19) [I16 = I16]
  f1#(I20, I21, I22, I23, I24) -> f4#(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 + I23 + I24 /\ 0 <= -1 + I24 /\ 0 <= -1 + I23]
  f3#(I25, I26, I27, I28, I29) -> f1#(I25, I26, I27, I28, I29) 
  f1#(I30, I31, I32, I33, I34) -> f3#(I30, I31, I35, -2 + I34, 1 + -2 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 + I33 + I34 /\ 0 <= -1 + I34 /\ 0 <= -1 + I33]
R = 
  f8(x1, x2, x3, x4, x5) -> f7(x1, x2, x3, x4, x5) 
  f7(I0, I1, I2, I3, I4) -> f1(I0, I1, I2, I3, I4) 
  f6(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, I8, I9) 
  f5(I10, I11, I12, I13, I14) -> f6(I10, I11, I12, -1 + I13, -1 + I13) 
  f4(I15, I16, I17, I18, I19) -> f5(I15, I16, I17, I18, I19) [I16 = I16]
  f1(I20, I21, I22, I23, I24) -> f4(I20, I21, rnd3, I23, I24) [rnd3 = rnd3 /\ 0 <= -1 + I23 + I24 /\ 0 <= -1 + I24 /\ 0 <= -1 + I23]
  f3(I25, I26, I27, I28, I29) -> f1(I25, I26, I27, I28, I29) 
  f1(I30, I31, I32, I33, I34) -> f3(I30, I31, I35, -2 + I34, 1 + -2 + I34) [0 <= I35 /\ I35 <= 0 /\ I35 = I35 /\ 0 <= -1 + I33 + I34 /\ 0 <= -1 + I34 /\ 0 <= -1 + I33]
  f1(I36, I37, I38, I39, I40) -> f2(rnd1, I37, I38, I39, I40) [rnd1 = rnd1 /\ I39 + I40 <= 0 /\ 0 <= -1 + I40 /\ 0 <= -1 + I39]
  f1(I41, I42, I43, I44, I45) -> f2(I46, I42, I43, I44, I45) [I46 = I46 /\ I45 <= 0 /\ 0 <= -1 + I44]
  f1(I47, I48, I49, I50, I51) -> f2(I52, I48, I49, I50, I51) [I52 = I52 /\ I50 <= 0]