/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f7#(x1, x2) -> f6#(x1, x2) f6#(I0, I1) -> f5#(1, I1) f5#(I2, I3) -> f3#(I2, 1) f5#(I4, I5) -> f1#(I4, I5) [1 + I4 <= 1] f1#(I8, I9) -> f3#(I8, 0) f2#(I10, I11) -> f1#(I10, I11) f1#(I12, I13) -> f2#(I12, I13) [1 <= 0] R = f7(x1, x2) -> f6(x1, x2) f6(I0, I1) -> f5(1, I1) f5(I2, I3) -> f3(I2, 1) f5(I4, I5) -> f1(I4, I5) [1 + I4 <= 1] f3(I6, I7) -> f4(I6, I7) [1 + I7 <= 1] f1(I8, I9) -> f3(I8, 0) f2(I10, I11) -> f1(I10, I11) f1(I12, I13) -> f2(I12, I13) [1 <= 0] The dependency graph for this problem is: 0 -> 1 1 -> 2 2 -> 3 -> 4 4 -> 5 -> 4 6 -> Where: 0) f7#(x1, x2) -> f6#(x1, x2) 1) f6#(I0, I1) -> f5#(1, I1) 2) f5#(I2, I3) -> f3#(I2, 1) 3) f5#(I4, I5) -> f1#(I4, I5) [1 + I4 <= 1] 4) f1#(I8, I9) -> f3#(I8, 0) 5) f2#(I10, I11) -> f1#(I10, I11) 6) f1#(I12, I13) -> f2#(I12, I13) [1 <= 0] We have the following SCCs.