/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f5#(x1, x2) -> f3#(x1, x2) f3#(I2, I3) -> f1#(I2, I3) f1#(I4, I5) -> f2#(I4, I5) [0 <= -1 - I5] f1#(I6, I7) -> f2#(I6, 1 + I7) [-1 * I7 <= 0] R = f5(x1, x2) -> f3(x1, x2) f2(I0, I1) -> f4(rnd1, I1) [rnd1 = rnd1] f3(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f2(I4, I5) [0 <= -1 - I5] f1(I6, I7) -> f2(I6, 1 + I7) [-1 * I7 <= 0] The dependency graph for this problem is: 0 -> 1 1 -> 2, 3 2 -> 3 -> Where: 0) f5#(x1, x2) -> f3#(x1, x2) 1) f3#(I2, I3) -> f1#(I2, I3) 2) f1#(I4, I5) -> f2#(I4, I5) [0 <= -1 - I5] 3) f1#(I6, I7) -> f2#(I6, 1 + I7) [-1 * I7 <= 0] We have the following SCCs.