/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f5#(x1, x2, x3, x4, x5) -> f4#(x1, x2, x3, x4, x5) 
  f4#(I0, I1, I2, I3, I4) -> f3#(I0, 2, I2, I3, I4) [I2 <= 3 /\ 0 <= I2 /\ I4 <= 3 /\ 0 <= I4]
  f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9]
  f3#(I10, I11, I12, I13, I14) -> f1#(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12]
  f3#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19]
  f2#(I20, I21, I22, I23, I24) -> f3#(I20, I21, I23, I23, I24) 
  f1#(I25, I26, I27, I28, I29) -> f2#(I25, I26, I27, I28, I29) [I25 = I25]
R = 
  f5(x1, x2, x3, x4, x5) -> f4(x1, x2, x3, x4, x5) 
  f4(I0, I1, I2, I3, I4) -> f3(I0, 2, I2, I3, I4) [I2 <= 3 /\ 0 <= I2 /\ I4 <= 3 /\ 0 <= I4]
  f3(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9]
  f3(I10, I11, I12, I13, I14) -> f1(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12]
  f3(I15, I16, I17, I18, I19) -> f1(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19]
  f2(I20, I21, I22, I23, I24) -> f3(I20, I21, I23, I23, I24) 
  f1(I25, I26, I27, I28, I29) -> f2(I25, I26, I27, I28, I29) [I25 = I25]

The dependency graph for this problem is:
  0 -> 1
  1 -> 2, 3, 4
  2 -> 6
  3 -> 6
  4 -> 6
  5 -> 2, 3, 4
  6 -> 5
Where:
  0) f5#(x1, x2, x3, x4, x5) -> f4#(x1, x2, x3, x4, x5) 
  1) f4#(I0, I1, I2, I3, I4) -> f3#(I0, 2, I2, I3, I4) [I2 <= 3 /\ 0 <= I2 /\ I4 <= 3 /\ 0 <= I4]
  2) f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9]
  3) f3#(I10, I11, I12, I13, I14) -> f1#(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12]
  4) f3#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19]
  5) f2#(I20, I21, I22, I23, I24) -> f3#(I20, I21, I23, I23, I24) 
  6) f1#(I25, I26, I27, I28, I29) -> f2#(I25, I26, I27, I28, I29) [I25 = I25]

We have the following SCCs.
  { 2, 3, 4, 5, 6 }

DP problem for innermost termination.
P =
  f3#(I5, I6, I7, I8, I9) -> f1#(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9]
  f3#(I10, I11, I12, I13, I14) -> f1#(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12]
  f3#(I15, I16, I17, I18, I19) -> f1#(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19]
  f2#(I20, I21, I22, I23, I24) -> f3#(I20, I21, I23, I23, I24) 
  f1#(I25, I26, I27, I28, I29) -> f2#(I25, I26, I27, I28, I29) [I25 = I25]
R = 
  f5(x1, x2, x3, x4, x5) -> f4(x1, x2, x3, x4, x5) 
  f4(I0, I1, I2, I3, I4) -> f3(I0, 2, I2, I3, I4) [I2 <= 3 /\ 0 <= I2 /\ I4 <= 3 /\ 0 <= I4]
  f3(I5, I6, I7, I8, I9) -> f1(I5, I6, I7, 1 + I7, I9) [1 + 2 * I7 <= I6 + I9]
  f3(I10, I11, I12, I13, I14) -> f1(I10, I11, I12, -1 + I12, I14) [1 + I11 + I14 <= -1 + 2 * I12]
  f3(I15, I16, I17, I18, I19) -> f1(I15, I16, I17, I17, I19) [I16 + I19 <= 2 * I17 /\ -1 + 2 * I17 <= I16 + I19]
  f2(I20, I21, I22, I23, I24) -> f3(I20, I21, I23, I23, I24) 
  f1(I25, I26, I27, I28, I29) -> f2(I25, I26, I27, I28, I29) [I25 = I25]