/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f7#(x1, x2) -> f6#(x1, x2) 
  f6#(I0, I1) -> f2#(0, I1) 
  f2#(I2, I3) -> f4#(I2, rnd2) [rnd2 = rnd2]
  f4#(I4, I5) -> f3#(I4, I5) [1 + I5 <= 0]
  f4#(I6, I7) -> f3#(I6, I7) [1 <= I7]
  f3#(I10, I11) -> f1#(0, I11) [4 <= I10 /\ I10 <= 4]
  f3#(I12, I13) -> f1#(I12, I13) [1 + I12 <= 4]
  f3#(I14, I15) -> f1#(I14, I15) [5 <= I14]
  f1#(I16, I17) -> f2#(1 + I16, I17) 
R = 
  f7(x1, x2) -> f6(x1, x2) 
  f6(I0, I1) -> f2(0, I1) 
  f2(I2, I3) -> f4(I2, rnd2) [rnd2 = rnd2]
  f4(I4, I5) -> f3(I4, I5) [1 + I5 <= 0]
  f4(I6, I7) -> f3(I6, I7) [1 <= I7]
  f4(I8, I9) -> f5(I8, I9) [0 <= I9 /\ I9 <= 0]
  f3(I10, I11) -> f1(0, I11) [4 <= I10 /\ I10 <= 4]
  f3(I12, I13) -> f1(I12, I13) [1 + I12 <= 4]
  f3(I14, I15) -> f1(I14, I15) [5 <= I14]
  f1(I16, I17) -> f2(1 + I16, I17) 

The dependency graph for this problem is:
  0 -> 1
  1 -> 2
  2 -> 3, 4
  3 -> 5, 6, 7
  4 -> 5, 6, 7
  5 -> 8
  6 -> 8
  7 -> 8
  8 -> 2
Where:
  0) f7#(x1, x2) -> f6#(x1, x2) 
  1) f6#(I0, I1) -> f2#(0, I1) 
  2) f2#(I2, I3) -> f4#(I2, rnd2) [rnd2 = rnd2]
  3) f4#(I4, I5) -> f3#(I4, I5) [1 + I5 <= 0]
  4) f4#(I6, I7) -> f3#(I6, I7) [1 <= I7]
  5) f3#(I10, I11) -> f1#(0, I11) [4 <= I10 /\ I10 <= 4]
  6) f3#(I12, I13) -> f1#(I12, I13) [1 + I12 <= 4]
  7) f3#(I14, I15) -> f1#(I14, I15) [5 <= I14]
  8) f1#(I16, I17) -> f2#(1 + I16, I17) 

We have the following SCCs.
  { 2, 3, 4, 5, 6, 7, 8 }

DP problem for innermost termination.
P =
  f2#(I2, I3) -> f4#(I2, rnd2) [rnd2 = rnd2]
  f4#(I4, I5) -> f3#(I4, I5) [1 + I5 <= 0]
  f4#(I6, I7) -> f3#(I6, I7) [1 <= I7]
  f3#(I10, I11) -> f1#(0, I11) [4 <= I10 /\ I10 <= 4]
  f3#(I12, I13) -> f1#(I12, I13) [1 + I12 <= 4]
  f3#(I14, I15) -> f1#(I14, I15) [5 <= I14]
  f1#(I16, I17) -> f2#(1 + I16, I17) 
R = 
  f7(x1, x2) -> f6(x1, x2) 
  f6(I0, I1) -> f2(0, I1) 
  f2(I2, I3) -> f4(I2, rnd2) [rnd2 = rnd2]
  f4(I4, I5) -> f3(I4, I5) [1 + I5 <= 0]
  f4(I6, I7) -> f3(I6, I7) [1 <= I7]
  f4(I8, I9) -> f5(I8, I9) [0 <= I9 /\ I9 <= 0]
  f3(I10, I11) -> f1(0, I11) [4 <= I10 /\ I10 <= 4]
  f3(I12, I13) -> f1(I12, I13) [1 + I12 <= 4]
  f3(I14, I15) -> f1(I14, I15) [5 <= I14]
  f1(I16, I17) -> f2(1 + I16, I17)