/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


--------------------------------------------------------------------------------


MAYBE

DP problem for innermost termination.
P =
  f4#(x1, x2, x3, x4) -> f3#(x1, x2, x3, x4) 
  f3#(I0, I1, I2, I3) -> f1#(I0, I1, I2, I3) 
  f2#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) 
  f1#(I8, I9, I10, I11) -> f2#(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0]
R = 
  f4(x1, x2, x3, x4) -> f3(x1, x2, x3, x4) 
  f3(I0, I1, I2, I3) -> f1(I0, I1, I2, I3) 
  f2(I4, I5, I6, I7) -> f1(I4, I5, I6, I7) 
  f1(I8, I9, I10, I11) -> f2(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0]

The dependency graph for this problem is:
  0 -> 1
  1 -> 3
  2 -> 3
  3 -> 2
Where:
  0) f4#(x1, x2, x3, x4) -> f3#(x1, x2, x3, x4) 
  1) f3#(I0, I1, I2, I3) -> f1#(I0, I1, I2, I3) 
  2) f2#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) 
  3) f1#(I8, I9, I10, I11) -> f2#(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0]

We have the following SCCs.
  { 2, 3 }

DP problem for innermost termination.
P =
  f2#(I4, I5, I6, I7) -> f1#(I4, I5, I6, I7) 
  f1#(I8, I9, I10, I11) -> f2#(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0]
R = 
  f4(x1, x2, x3, x4) -> f3(x1, x2, x3, x4) 
  f3(I0, I1, I2, I3) -> f1(I0, I1, I2, I3) 
  f2(I4, I5, I6, I7) -> f1(I4, I5, I6, I7) 
  f1(I8, I9, I10, I11) -> f2(I9, I11, rnd3, I11) [1 <= 1 + I10 /\ 1 <= I10 /\ y1 = y1 /\ 1 <= 1 + y1 /\ 1 <= y1 /\ rnd3 = rnd3 /\ 0 <= -1 * I9 /\ -1 * I9 <= 0]