/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f7#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) 
  f6#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) 
  f5#(I8, I9, I10, I11, I12, I13, I14, I15) -> f6#(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
  f4#(I16, I17, I18, I19, I20, I21, I22, I23) -> f5#(I16, I17, I18, I19, I20, I21, I22, I23) [1 + I21 <= I20]
  f4#(I24, I25, I26, I27, I28, I29, I30, I31) -> f5#(I24, I25, I26, I27, I28, I29, I30, I31) [1 + I28 <= I29]
  f2#(I32, I33, I34, I35, I36, I37, I38, I39) -> f4#(I32, I33, I34, I35, I33, I34, I38, I39) 
  f1#(I51, I52, I53, I54, I55, I56, I57, I58) -> f2#(I51, I52, I53, I54, I55, I56, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8]
R = 
  f7(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) 
  f6(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) 
  f5(I8, I9, I10, I11, I12, I13, I14, I15) -> f6(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
  f4(I16, I17, I18, I19, I20, I21, I22, I23) -> f5(I16, I17, I18, I19, I20, I21, I22, I23) [1 + I21 <= I20]
  f4(I24, I25, I26, I27, I28, I29, I30, I31) -> f5(I24, I25, I26, I27, I28, I29, I30, I31) [1 + I28 <= I29]
  f2(I32, I33, I34, I35, I36, I37, I38, I39) -> f4(I32, I33, I34, I35, I33, I34, I38, I39) 
  f2(I40, I41, I42, I43, I44, I45, I46, I47) -> f3(rnd1, I41, I42, I43, I48, I49, I46, I47) [I50 = I41 /\ y2 = I42 /\ I50 <= y2 /\ y2 <= I50 /\ I48 = I48 /\ I49 = I49 /\ rnd1 = rnd1]
  f1(I51, I52, I53, I54, I55, I56, I57, I58) -> f2(I51, I52, I53, I54, I55, I56, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8]

The dependency graph for this problem is:
  0 -> 6
  1 -> 5
  2 -> 1
  3 -> 2
  4 -> 2
  5 -> 3, 4
  6 -> 5
Where:
  0) f7#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) 
  1) f6#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) 
  2) f5#(I8, I9, I10, I11, I12, I13, I14, I15) -> f6#(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
  3) f4#(I16, I17, I18, I19, I20, I21, I22, I23) -> f5#(I16, I17, I18, I19, I20, I21, I22, I23) [1 + I21 <= I20]
  4) f4#(I24, I25, I26, I27, I28, I29, I30, I31) -> f5#(I24, I25, I26, I27, I28, I29, I30, I31) [1 + I28 <= I29]
  5) f2#(I32, I33, I34, I35, I36, I37, I38, I39) -> f4#(I32, I33, I34, I35, I33, I34, I38, I39) 
  6) f1#(I51, I52, I53, I54, I55, I56, I57, I58) -> f2#(I51, I52, I53, I54, I55, I56, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8]

We have the following SCCs.
  { 1, 2, 3, 4, 5 }

DP problem for innermost termination.
P =
  f6#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) 
  f5#(I8, I9, I10, I11, I12, I13, I14, I15) -> f6#(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
  f4#(I16, I17, I18, I19, I20, I21, I22, I23) -> f5#(I16, I17, I18, I19, I20, I21, I22, I23) [1 + I21 <= I20]
  f4#(I24, I25, I26, I27, I28, I29, I30, I31) -> f5#(I24, I25, I26, I27, I28, I29, I30, I31) [1 + I28 <= I29]
  f2#(I32, I33, I34, I35, I36, I37, I38, I39) -> f4#(I32, I33, I34, I35, I33, I34, I38, I39) 
R = 
  f7(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) 
  f6(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) 
  f5(I8, I9, I10, I11, I12, I13, I14, I15) -> f6(I8, I9, I10, rnd4, rnd5, rnd6, I14, I15) [rnd5 = rnd5 /\ rnd6 = rnd6 /\ y1 = I9 /\ rnd4 = rnd4]
  f4(I16, I17, I18, I19, I20, I21, I22, I23) -> f5(I16, I17, I18, I19, I20, I21, I22, I23) [1 + I21 <= I20]
  f4(I24, I25, I26, I27, I28, I29, I30, I31) -> f5(I24, I25, I26, I27, I28, I29, I30, I31) [1 + I28 <= I29]
  f2(I32, I33, I34, I35, I36, I37, I38, I39) -> f4(I32, I33, I34, I35, I33, I34, I38, I39) 
  f2(I40, I41, I42, I43, I44, I45, I46, I47) -> f3(rnd1, I41, I42, I43, I48, I49, I46, I47) [I50 = I41 /\ y2 = I42 /\ I50 <= y2 /\ y2 <= I50 /\ I48 = I48 /\ I49 = I49 /\ rnd1 = rnd1]
  f1(I51, I52, I53, I54, I55, I56, I57, I58) -> f2(I51, I52, I53, I54, I55, I56, rnd7, rnd8) [rnd7 = rnd7 /\ rnd8 = rnd8]