/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files


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MAYBE

DP problem for innermost termination.
P =
  f9#(x1, x2, x3) -> f8#(x1, x2, x3) 
  f8#(I0, I1, I2) -> f7#(0, I1, I2) 
  f7#(I3, I4, I5) -> f5#(I3, I4, I5) [1 <= I4]
  f7#(I6, I7, I8) -> f3#(I6, I7, I8) [I7 <= 0]
  f6#(I9, I10, I11) -> f5#(I9, I10, I11) 
  f5#(I12, I13, I14) -> f6#(1 + I12, I13, I14) 
  f5#(I15, I16, I17) -> f1#(I15, I16, I17) [2 <= 0]
  f4#(I18, I19, I20) -> f3#(I18, I19, I20) 
  f3#(I21, I22, I23) -> f4#(I21, I22, -1 + I23) [1 <= I23]
  f3#(I24, I25, I26) -> f1#(0, I25, I26) [I26 <= 0]
  f2#(I27, I28, I29) -> f1#(I27, I28, I29) 
  f1#(I30, I31, I32) -> f2#(I30, 1, I32) 
R = 
  f9(x1, x2, x3) -> f8(x1, x2, x3) 
  f8(I0, I1, I2) -> f7(0, I1, I2) 
  f7(I3, I4, I5) -> f5(I3, I4, I5) [1 <= I4]
  f7(I6, I7, I8) -> f3(I6, I7, I8) [I7 <= 0]
  f6(I9, I10, I11) -> f5(I9, I10, I11) 
  f5(I12, I13, I14) -> f6(1 + I12, I13, I14) 
  f5(I15, I16, I17) -> f1(I15, I16, I17) [2 <= 0]
  f4(I18, I19, I20) -> f3(I18, I19, I20) 
  f3(I21, I22, I23) -> f4(I21, I22, -1 + I23) [1 <= I23]
  f3(I24, I25, I26) -> f1(0, I25, I26) [I26 <= 0]
  f2(I27, I28, I29) -> f1(I27, I28, I29) 
  f1(I30, I31, I32) -> f2(I30, 1, I32) 

The dependency graph for this problem is:
  0 -> 1
  1 -> 2, 3
  2 -> 5
  3 -> 8, 9
  4 -> 5
  5 -> 4
  6 -> 
  7 -> 8, 9
  8 -> 7
  9 -> 11
  10 -> 11
  11 -> 10
Where:
  0) f9#(x1, x2, x3) -> f8#(x1, x2, x3) 
  1) f8#(I0, I1, I2) -> f7#(0, I1, I2) 
  2) f7#(I3, I4, I5) -> f5#(I3, I4, I5) [1 <= I4]
  3) f7#(I6, I7, I8) -> f3#(I6, I7, I8) [I7 <= 0]
  4) f6#(I9, I10, I11) -> f5#(I9, I10, I11) 
  5) f5#(I12, I13, I14) -> f6#(1 + I12, I13, I14) 
  6) f5#(I15, I16, I17) -> f1#(I15, I16, I17) [2 <= 0]
  7) f4#(I18, I19, I20) -> f3#(I18, I19, I20) 
  8) f3#(I21, I22, I23) -> f4#(I21, I22, -1 + I23) [1 <= I23]
  9) f3#(I24, I25, I26) -> f1#(0, I25, I26) [I26 <= 0]
  10) f2#(I27, I28, I29) -> f1#(I27, I28, I29) 
  11) f1#(I30, I31, I32) -> f2#(I30, 1, I32) 

We have the following SCCs.
  { 4, 5 }
  { 7, 8 }
  { 10, 11 }

DP problem for innermost termination.
P =
  f2#(I27, I28, I29) -> f1#(I27, I28, I29) 
  f1#(I30, I31, I32) -> f2#(I30, 1, I32) 
R = 
  f9(x1, x2, x3) -> f8(x1, x2, x3) 
  f8(I0, I1, I2) -> f7(0, I1, I2) 
  f7(I3, I4, I5) -> f5(I3, I4, I5) [1 <= I4]
  f7(I6, I7, I8) -> f3(I6, I7, I8) [I7 <= 0]
  f6(I9, I10, I11) -> f5(I9, I10, I11) 
  f5(I12, I13, I14) -> f6(1 + I12, I13, I14) 
  f5(I15, I16, I17) -> f1(I15, I16, I17) [2 <= 0]
  f4(I18, I19, I20) -> f3(I18, I19, I20) 
  f3(I21, I22, I23) -> f4(I21, I22, -1 + I23) [1 <= I23]
  f3(I24, I25, I26) -> f1(0, I25, I26) [I26 <= 0]
  f2(I27, I28, I29) -> f1(I27, I28, I29) 
  f1(I30, I31, I32) -> f2(I30, 1, I32)