/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.koat /export/starexec/sandbox2/output/output_files


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WORST_CASE(NON_POLY, ?)
proof of /export/starexec/sandbox2/benchmark/theBenchmark.koat
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(INF, INF).

(0) CpxIntTrs
(1) Loat Proof [FINISHED, 6 ms]
(2) BOUNDS(INF, INF)


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(0)
Obligation:
Complexity Int TRS consisting of the following rules:
f0(A, B, C, D) -> Com_1(f3(A, E, C, D)) :|: A >= 10
f0(A, B, C, D) -> Com_1(f0(-(1) + A, B, A, D)) :|: 9 >= A
f1(A, B, C, D) -> Com_1(f0(-(1), B, C, -(1))) :|: 9 >= A
f2(A, B, C, D) -> Com_1(f0(0, B, C, D)) :|: TRUE

The start-symbols are:[f2_4]


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(1) Loat Proof (FINISHED)


### Pre-processing the ITS problem ###



Initial linear ITS problem

   Start location: f2

      0: f0 -> f3 : B'=free, [ A>=10 ], cost: 1

      1: f0 -> f0 : A'=-1+A, C'=A, [ 9>=A ], cost: 1

      2: f1 -> f0 : A'=-1, D'=-1, [ 9>=A ], cost: 1

      3: f2 -> f0 : A'=0, [], cost: 1



Removed unreachable and leaf rules:

   Start location: f2

      1: f0 -> f0 : A'=-1+A, C'=A, [ 9>=A ], cost: 1

      3: f2 -> f0 : A'=0, [], cost: 1



### Simplification by acceleration and chaining ###



Accelerating simple loops of location 0.

   Accelerating the following rules:

      1: f0 -> f0 : A'=-1+A, C'=A, [ 9>=A ], cost: 1



   Accelerated rule 1 with NONTERM, yielding the new rule 4.

   Removing the simple loops: 1.



Accelerated all simple loops using metering functions (where possible):

   Start location: f2

      4: f0 -> [4] : [ 9>=A ], cost: INF

      3: f2 -> f0 : A'=0, [], cost: 1



Chained accelerated rules (with incoming rules):

   Start location: f2

      3: f2 -> f0 : A'=0, [], cost: 1

      5: f2 -> [4] : A'=0, [], cost: INF



Removed unreachable locations (and leaf rules with constant cost):

   Start location: f2

      5: f2 -> [4] : A'=0, [], cost: INF



### Computing asymptotic complexity ###



Fully simplified ITS problem

   Start location: f2

      5: f2 -> [4] : A'=0, [], cost: INF



Computing asymptotic complexity for rule 5

   Resulting cost INF has complexity: Nonterm



Found new complexity Nonterm.



Obtained the following overall complexity (w.r.t. the length of the input n):

   Complexity:  Nonterm

   Cpx degree:  Nonterm

   Solved cost: INF

   Rule cost:   INF

   Rule guard:  []



NO


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(2)
BOUNDS(INF, INF)