/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.koat /export/starexec/sandbox/output/output_files


--------------------------------------------------------------------------------


WORST_CASE(NON_POLY, ?)
proof of /export/starexec/sandbox/benchmark/theBenchmark.koat
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(INF, INF).

(0) CpxIntTrs
(1) Loat Proof [FINISHED, 125 ms]
(2) BOUNDS(INF, INF)


----------------------------------------

(0)
Obligation:
Complexity Int TRS consisting of the following rules:
f3(A, B) -> Com_1(f0(2, B)) :|: TRUE
f0(A, B) -> Com_1(f0(A + 1, C)) :|: C >= 1
f0(A, B) -> Com_1(f0(A - 1, C)) :|: 0 >= C

The start-symbols are:[f3_2]


----------------------------------------

(1) Loat Proof (FINISHED)


### Pre-processing the ITS problem ###



Initial linear ITS problem

   Start location: f3

      0: f3 -> f0 : A'=2, [], cost: 1

      1: f0 -> f0 : A'=1+A, B'=free, [ free>=1 ], cost: 1

      2: f0 -> f0 : A'=-1+A, B'=free_1, [ 0>=free_1 ], cost: 1



### Simplification by acceleration and chaining ###



Accelerating simple loops of location 1.

   Accelerating the following rules:

      1: f0 -> f0 : A'=1+A, B'=free, [ free>=1 ], cost: 1

      2: f0 -> f0 : A'=-1+A, B'=free_1, [ 0>=free_1 ], cost: 1



   Accelerated rule 1 with NONTERM, yielding the new rule 3.

   Accelerated rule 2 with NONTERM, yielding the new rule 4.

   Removing the simple loops: 1 2.



Accelerated all simple loops using metering functions (where possible):

   Start location: f3

      0: f3 -> f0 : A'=2, [], cost: 1

      3: f0 -> [2] : [ free>=1 ], cost: INF

      4: f0 -> [2] : [ 0>=free_1 ], cost: INF



Chained accelerated rules (with incoming rules):

   Start location: f3

      0: f3 -> f0 : A'=2, [], cost: 1

      5: f3 -> [2] : A'=2, [], cost: INF

      6: f3 -> [2] : A'=2, [], cost: INF



Removed unreachable locations (and leaf rules with constant cost):

   Start location: f3

      5: f3 -> [2] : A'=2, [], cost: INF

      6: f3 -> [2] : A'=2, [], cost: INF



### Computing asymptotic complexity ###



Fully simplified ITS problem

   Start location: f3

      6: f3 -> [2] : A'=2, [], cost: INF



Computing asymptotic complexity for rule 6

   Resulting cost INF has complexity: Nonterm



Found new complexity Nonterm.



Obtained the following overall complexity (w.r.t. the length of the input n):

   Complexity:  Nonterm

   Cpx degree:  Nonterm

   Solved cost: INF

   Rule cost:   INF

   Rule guard:  []



NO


----------------------------------------

(2)
BOUNDS(INF, INF)