/export/starexec/sandbox2/solver/bin/starexec_run_complexity /export/starexec/sandbox2/benchmark/theBenchmark.koat /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- WORST_CASE(NON_POLY, ?) proof of /export/starexec/sandbox2/benchmark/theBenchmark.koat # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(INF, INF). (0) CpxIntTrs (1) Loat Proof [FINISHED, 220 ms] (2) BOUNDS(INF, INF) ---------------------------------------- (0) Obligation: Complexity Int TRS consisting of the following rules: f0(A) -> Com_1(f3(A)) :|: TRUE f3(A) -> Com_1(f3(A - 1)) :|: A >= 2 f3(A) -> Com_1(f3(A - 1)) :|: TRUE The start-symbols are:[f0_1] ---------------------------------------- (1) Loat Proof (FINISHED) ### Pre-processing the ITS problem ### Initial linear ITS problem Start location: f0 0: f0 -> f3 : [], cost: 1 1: f3 -> f3 : A'=-1+A, [ A>=2 ], cost: 1 2: f3 -> f3 : A'=-1+A, [], cost: 1 ### Simplification by acceleration and chaining ### Accelerating simple loops of location 1. Accelerating the following rules: 1: f3 -> f3 : A'=-1+A, [ A>=2 ], cost: 1 2: f3 -> f3 : A'=-1+A, [], cost: 1 Accelerated rule 1 with metering function -1+A, yielding the new rule 3. Accelerated rule 2 with NONTERM, yielding the new rule 4. Removing the simple loops: 1 2. Accelerated all simple loops using metering functions (where possible): Start location: f0 0: f0 -> f3 : [], cost: 1 3: f3 -> f3 : A'=1, [ A>=2 ], cost: -1+A 4: f3 -> [2] : [], cost: INF Chained accelerated rules (with incoming rules): Start location: f0 0: f0 -> f3 : [], cost: 1 5: f0 -> f3 : A'=1, [ A>=2 ], cost: A 6: f0 -> [2] : [], cost: INF Removed unreachable locations (and leaf rules with constant cost): Start location: f0 5: f0 -> f3 : A'=1, [ A>=2 ], cost: A 6: f0 -> [2] : [], cost: INF ### Computing asymptotic complexity ### Fully simplified ITS problem Start location: f0 5: f0 -> f3 : A'=1, [ A>=2 ], cost: A 6: f0 -> [2] : [], cost: INF Computing asymptotic complexity for rule 5 Solved the limit problem by the following transformations: Created initial limit problem: -1+A (+/+!), A (+) [not solved] removing all constraints (solved by SMT) resulting limit problem: [solved] applying transformation rule (C) using substitution {A==n} resulting limit problem: [solved] Solution: A / n Resulting cost n has complexity: Poly(n^1) Found new complexity Poly(n^1). Computing asymptotic complexity for rule 6 Resulting cost INF has complexity: Nonterm Found new complexity Nonterm. Obtained the following overall complexity (w.r.t. the length of the input n): Complexity: Nonterm Cpx degree: Nonterm Solved cost: INF Rule cost: INF Rule guard: [] NO ---------------------------------------- (2) BOUNDS(INF, INF)