/export/starexec/sandbox/solver/bin/starexec_run_complexity /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- WORST_CASE(Omega(n^1), O(n^1)) proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, n^1). (0) CpxTRS (1) NestedDefinedSymbolProof [UPPER BOUND(ID), 0 ms] (2) CpxTRS (3) RcToIrcProof [BOTH BOUNDS(ID, ID), 0 ms] (4) CpxTRS (5) CpxTrsToCdtProof [UPPER BOUND(ID), 3 ms] (6) CdtProblem (7) CdtLeafRemovalProof [BOTH BOUNDS(ID, ID), 0 ms] (8) CdtProblem (9) CdtUsableRulesProof [BOTH BOUNDS(ID, ID), 0 ms] (10) CdtProblem (11) CdtRuleRemovalProof [UPPER BOUND(ADD(n^1)), 40 ms] (12) CdtProblem (13) SIsEmptyProof [BOTH BOUNDS(ID, ID), 0 ms] (14) BOUNDS(1, 1) (15) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] (16) TRS for Loop Detection (17) DecreasingLoopProof [LOWER BOUND(ID), 0 ms] (18) BEST (19) proven lower bound (20) LowerBoundPropagationProof [FINISHED, 0 ms] (21) BOUNDS(n^1, INF) (22) TRS for Loop Detection ---------------------------------------- (0) Obligation: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, n^1). The TRS R consists of the following rules: :(:(x, y), z) -> :(x, :(y, z)) :(+(x, y), z) -> +(:(x, z), :(y, z)) :(z, +(x, f(y))) -> :(g(z, y), +(x, a)) S is empty. Rewrite Strategy: FULL ---------------------------------------- (1) NestedDefinedSymbolProof (UPPER BOUND(ID)) The TRS does not nest defined symbols. Hence, the left-hand sides of the following rules are not basic-reachable and can be removed: :(:(x, y), z) -> :(x, :(y, z)) ---------------------------------------- (2) Obligation: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(1, n^1). The TRS R consists of the following rules: :(+(x, y), z) -> +(:(x, z), :(y, z)) :(z, +(x, f(y))) -> :(g(z, y), +(x, a)) S is empty. Rewrite Strategy: FULL ---------------------------------------- (3) RcToIrcProof (BOTH BOUNDS(ID, ID)) Converted rc-obligation to irc-obligation. As the TRS does not nest defined symbols, we have rc = irc. ---------------------------------------- (4) Obligation: The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(1, n^1). The TRS R consists of the following rules: :(+(x, y), z) -> +(:(x, z), :(y, z)) :(z, +(x, f(y))) -> :(g(z, y), +(x, a)) S is empty. Rewrite Strategy: INNERMOST ---------------------------------------- (5) CpxTrsToCdtProof (UPPER BOUND(ID)) Converted Cpx (relative) TRS to CDT ---------------------------------------- (6) Obligation: Complexity Dependency Tuples Problem Rules: :(+(z0, z1), z2) -> +(:(z0, z2), :(z1, z2)) :(z0, +(z1, f(z2))) -> :(g(z0, z2), +(z1, a)) Tuples: :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) :'(z0, +(z1, f(z2))) -> c1(:'(g(z0, z2), +(z1, a))) S tuples: :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) :'(z0, +(z1, f(z2))) -> c1(:'(g(z0, z2), +(z1, a))) K tuples:none Defined Rule Symbols: :_2 Defined Pair Symbols: :'_2 Compound Symbols: c_2, c1_1 ---------------------------------------- (7) CdtLeafRemovalProof (BOTH BOUNDS(ID, ID)) Removed 1 trailing nodes: :'(z0, +(z1, f(z2))) -> c1(:'(g(z0, z2), +(z1, a))) ---------------------------------------- (8) Obligation: Complexity Dependency Tuples Problem Rules: :(+(z0, z1), z2) -> +(:(z0, z2), :(z1, z2)) :(z0, +(z1, f(z2))) -> :(g(z0, z2), +(z1, a)) Tuples: :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) S tuples: :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) K tuples:none Defined Rule Symbols: :_2 Defined Pair Symbols: :'_2 Compound Symbols: c_2 ---------------------------------------- (9) CdtUsableRulesProof (BOTH BOUNDS(ID, ID)) The following rules are not usable and were removed: :(+(z0, z1), z2) -> +(:(z0, z2), :(z1, z2)) :(z0, +(z1, f(z2))) -> :(g(z0, z2), +(z1, a)) ---------------------------------------- (10) Obligation: Complexity Dependency Tuples Problem Rules:none Tuples: :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) S tuples: :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) K tuples:none Defined Rule Symbols:none Defined Pair Symbols: :'_2 Compound Symbols: c_2 ---------------------------------------- (11) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1))) Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S. :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) We considered the (Usable) Rules:none And the Tuples: :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) The order we found is given by the following interpretation: Polynomial interpretation : POL(+(x_1, x_2)) = [1] + x_1 + x_2 POL(:'(x_1, x_2)) = x_1 POL(c(x_1, x_2)) = x_1 + x_2 ---------------------------------------- (12) Obligation: Complexity Dependency Tuples Problem Rules:none Tuples: :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) S tuples:none K tuples: :'(+(z0, z1), z2) -> c(:'(z0, z2), :'(z1, z2)) Defined Rule Symbols:none Defined Pair Symbols: :'_2 Compound Symbols: c_2 ---------------------------------------- (13) SIsEmptyProof (BOTH BOUNDS(ID, ID)) The set S is empty ---------------------------------------- (14) BOUNDS(1, 1) ---------------------------------------- (15) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) Transformed a relative TRS into a decreasing-loop problem. ---------------------------------------- (16) Obligation: Analyzing the following TRS for decreasing loops: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, n^1). The TRS R consists of the following rules: :(:(x, y), z) -> :(x, :(y, z)) :(+(x, y), z) -> +(:(x, z), :(y, z)) :(z, +(x, f(y))) -> :(g(z, y), +(x, a)) S is empty. Rewrite Strategy: FULL ---------------------------------------- (17) DecreasingLoopProof (LOWER BOUND(ID)) The following loop(s) give(s) rise to the lower bound Omega(n^1): The rewrite sequence :(+(x, y), z) ->^+ +(:(x, z), :(y, z)) gives rise to a decreasing loop by considering the right hand sides subterm at position [0]. The pumping substitution is [x / +(x, y)]. The result substitution is [ ]. ---------------------------------------- (18) Complex Obligation (BEST) ---------------------------------------- (19) Obligation: Proved the lower bound n^1 for the following obligation: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, n^1). The TRS R consists of the following rules: :(:(x, y), z) -> :(x, :(y, z)) :(+(x, y), z) -> +(:(x, z), :(y, z)) :(z, +(x, f(y))) -> :(g(z, y), +(x, a)) S is empty. Rewrite Strategy: FULL ---------------------------------------- (20) LowerBoundPropagationProof (FINISHED) Propagated lower bound. ---------------------------------------- (21) BOUNDS(n^1, INF) ---------------------------------------- (22) Obligation: Analyzing the following TRS for decreasing loops: The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, n^1). The TRS R consists of the following rules: :(:(x, y), z) -> :(x, :(y, z)) :(+(x, y), z) -> +(:(x, z), :(y, z)) :(z, +(x, f(y))) -> :(g(z, y), +(x, a)) S is empty. Rewrite Strategy: FULL