/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Outermost Termination of the given OTRS could be disproven: (0) OTRS (1) OutermostNonTerminationProof [COMPLETE, 0 ms] (2) NO ---------------------------------------- (0) Obligation: Term rewrite system R: The TRS R consists of the following rules: and(tt) -> X length(cons(N)) -> s(length(L)) zeros -> cons(0) length(nil) -> 0 take(0, IL) -> nil take(s(M), cons(N)) -> cons(N) Outermost Strategy. ---------------------------------------- (1) OutermostNonTerminationProof (COMPLETE) Term rewrite system R: The TRS R consists of the following rules: and(tt) -> X length(cons(N)) -> s(length(L)) zeros -> cons(0) length(nil) -> 0 take(0, IL) -> nil take(s(M), cons(N)) -> cons(N) Outermost Strategy. ---------- Loop: ---------- and(tt) -> and(tt) with rule and(tt) -> X at position [] and matcher [X / and(tt)] Now an instance of the first term with Matcher [ ] occurs in the last term at position []. Context: [] We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. ---------------------------------------- (2) NO