/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Outermost Termination of the given OTRS could be disproven: (0) OTRS (1) OutermostNonTerminationProof [COMPLETE, 0 ms] (2) NO ---------------------------------------- (0) Obligation: Term rewrite system R: The TRS R consists of the following rules: uTake2(tt) -> cons(N) uLength(tt) -> s(length(L)) and(tt, T) -> T isNatIList -> isNatList isNat -> tt isNat -> isNat isNat -> isNatList isNatIList -> tt isNatIList -> and(isNat, isNatIList) isNatList -> tt isNatList -> and(isNat, isNatList) isNatList -> and(isNat, isNatIList) zeros -> cons(0) take(0, IL) -> uTake1(isNatIList) uTake1(tt) -> nil take(s(M), cons(N)) -> uTake2(and(isNat, and(isNat, isNatIList))) length(cons(N)) -> uLength(and(isNat, isNatList)) Outermost Strategy. ---------------------------------------- (1) OutermostNonTerminationProof (COMPLETE) Term rewrite system R: The TRS R consists of the following rules: uTake2(tt) -> cons(N) uLength(tt) -> s(length(L)) and(tt, T) -> T isNatIList -> isNatList isNat -> tt isNat -> isNat isNat -> isNatList isNatIList -> tt isNatIList -> and(isNat, isNatIList) isNatList -> tt isNatList -> and(isNat, isNatList) isNatList -> and(isNat, isNatIList) zeros -> cons(0) take(0, IL) -> uTake1(isNatIList) uTake1(tt) -> nil take(s(M), cons(N)) -> uTake2(and(isNat, and(isNat, isNatIList))) length(cons(N)) -> uLength(and(isNat, isNatList)) Outermost Strategy. ---------- Loop: ---------- uTake2(tt) -> cons(uTake2(tt)) with rule uTake2(tt) -> cons(N) at position [] and matcher [N / uTake2(tt)] Now an instance of the first term with Matcher [ ] occurs in the last term at position [0]. Context: cons([]) We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. ---------------------------------------- (2) NO