/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Outermost Termination of the given OTRS could be disproven: (0) OTRS (1) OutermostNonTerminationProof [COMPLETE, 763 ms] (2) NO ---------------------------------------- (0) Obligation: Term rewrite system R: The TRS R consists of the following rules: f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) f(f(b, x), y) -> x f(c, y) -> y Outermost Strategy. ---------------------------------------- (1) OutermostNonTerminationProof (COMPLETE) Term rewrite system R: The TRS R consists of the following rules: f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) f(f(b, x), y) -> x f(c, y) -> y Outermost Strategy. ---------- Loop: ---------- f(f(f(f(b, f(f(a, a), b)), y'), f(f(b, f(a, f(f(b, f(f(a, a), b)), y'''))), y'')), y'''') -> f(f(f(f(b, f(f(a, a), b)), y'), f(a, f(f(b, f(f(a, a), b)), y'''))), y'''') with rule f(f(b, x'), y''1) -> x' at position [0,1] and matcher [x' / f(a, f(f(b, f(f(a, a), b)), y''')), y''1 / y''] f(f(f(f(b, f(f(a, a), b)), y'), f(a, f(f(b, f(f(a, a), b)), y'''))), y'''') -> f(f(f(f(a, a), b), f(a, f(f(b, f(f(a, a), b)), y'''))), y'''') with rule f(f(b, x'), y'') -> x' at position [0,0] and matcher [x' / f(f(a, a), b), y'' / y'] f(f(f(f(a, a), b), f(a, f(f(b, f(f(a, a), b)), y'''))), y'''') -> f(f(f(a, f(a, f(f(b, f(f(a, a), b)), y'''))), f(b, f(a, f(f(b, f(f(a, a), b)), y''')))), y'''') with rule f(f(f(a, x'), y), z) -> f(f(x', z), f(y, z)) at position [0] and matcher [x' / a, y / b, z / f(a, f(f(b, f(f(a, a), b)), y'''))] f(f(f(a, f(a, f(f(b, f(f(a, a), b)), y'''))), f(b, f(a, f(f(b, f(f(a, a), b)), y''')))), y'''') -> f(f(f(a, f(f(b, f(f(a, a), b)), y''')), y''''), f(f(b, f(a, f(f(b, f(f(a, a), b)), y'''))), y'''')) with rule f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) at position [] and matcher [x / f(a, f(f(b, f(f(a, a), b)), y''')), y / f(b, f(a, f(f(b, f(f(a, a), b)), y'''))), z / y''''] f(f(f(a, f(f(b, f(f(a, a), b)), y''')), y''''), f(f(b, f(a, f(f(b, f(f(a, a), b)), y'''))), y'''')) -> f(f(f(f(b, f(f(a, a), b)), y'''), f(f(b, f(a, f(f(b, f(f(a, a), b)), y'''))), y'''')), f(y'''', f(f(b, f(a, f(f(b, f(f(a, a), b)), y'''))), y''''))) with rule f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) at position [] and matcher [x / f(f(b, f(f(a, a), b)), y'''), y / y'''', z / f(f(b, f(a, f(f(b, f(f(a, a), b)), y'''))), y'''')] Now an instance of the first term with Matcher [y' / y''', y'' / y'''', y'''' / f(y'''', f(f(b, f(a, f(f(b, f(f(a, a), b)), y'''))), y''''))] occurs in the last term at position []. Context: [] We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. ---------------------------------------- (2) NO