/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.pl /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.pl # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Left Termination of the query pattern balance(g,a) w.r.t. the given Prolog program could successfully be proven: (0) Prolog (1) PrologToPiTRSProof [SOUND, 0 ms] (2) PiTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) PiDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) PiDP (8) UsableRulesProof [EQUIVALENT, 0 ms] (9) PiDP (10) PiDPToQDPProof [SOUND, 0 ms] (11) QDP (12) QDPSizeChangeProof [EQUIVALENT, 0 ms] (13) YES (14) PiDP (15) UsableRulesProof [EQUIVALENT, 0 ms] (16) PiDP (17) PiDPToQDPProof [SOUND, 0 ms] (18) QDP (19) QDPSizeChangeProof [EQUIVALENT, 0 ms] (20) YES ---------------------------------------- (0) Obligation: Clauses: balance(T, TB) :- balance55(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []). balance55(nil, C, T, T, A, B, A, B, X, X). balance55(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) :- ','(balance55(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)), balance55(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)). balance5(nil, C, T, T, A, B, A, B, X, X) :- balance55(nil, C, T, T, A, B, A, B, X, X). balance5(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) :- balance55(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT). balance(nil, -(X, X), -(A, B), -(A, B), -(.(','(nil, -(C, C)), T), T)) :- balance5(nil, C, T, T, A, B, A, B, X, X). balance(tree(L, V, R), -(IH, IT), -(.(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T))), -(HR, TR), -(.(','(nil, -(XX0, XX0)), XX1), NT)) :- balance5(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT). Query: balance(g,a) ---------------------------------------- (1) PrologToPiTRSProof (SOUND) We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes: balance_in_2: (b,f) balance55_in_10: (b,f,f,b,f,b,f,f,f,b) (b,f,f,f,f,f,f,f,f,f) Transforming Prolog into the following Term Rewriting System: Pi-finite rewrite system: The TRS R consists of the following rules: balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB) The argument filtering Pi contains the following mapping: balance_in_ga(x1, x2) = balance_in_ga(x1) U1_ga(x1, x2, x3) = U1_ga(x3) balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaagagaaag(x1, x4, x6, x10) nil = nil balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaagagaaag tree(x1, x2, x3) = tree(x1, x2, x3) U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaagagaaag(x3, x6, x8, x18, x19) balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaaaaaaaaa(x1) balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaaaaaaaaa U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaaaaaaaaa(x3, x19) U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaaaaaaaaa(x19) U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaagagaaag(x19) [] = [] balance_out_ga(x1, x2) = balance_out_ga Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog ---------------------------------------- (2) Obligation: Pi-finite rewrite system: The TRS R consists of the following rules: balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB) The argument filtering Pi contains the following mapping: balance_in_ga(x1, x2) = balance_in_ga(x1) U1_ga(x1, x2, x3) = U1_ga(x3) balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaagagaaag(x1, x4, x6, x10) nil = nil balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaagagaaag tree(x1, x2, x3) = tree(x1, x2, x3) U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaagagaaag(x3, x6, x8, x18, x19) balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaaaaaaaaa(x1) balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaaaaaaaaa U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaaaaaaaaa(x3, x19) U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaaaaaaaaa(x19) U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaagagaaag(x19) [] = [] balance_out_ga(x1, x2) = balance_out_ga ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem: Pi DP problem: The TRS P consists of the following rules: BALANCE_IN_GA(T, TB) -> U1_GA(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) BALANCE_IN_GA(T, TB) -> BALANCE55_IN_GAAGAGAAAG(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []) BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)) U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAAAAAAAA(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT) U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAGAGAAAG(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT) The TRS R consists of the following rules: balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB) The argument filtering Pi contains the following mapping: balance_in_ga(x1, x2) = balance_in_ga(x1) U1_ga(x1, x2, x3) = U1_ga(x3) balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaagagaaag(x1, x4, x6, x10) nil = nil balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaagagaaag tree(x1, x2, x3) = tree(x1, x2, x3) U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaagagaaag(x3, x6, x8, x18, x19) balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaaaaaaaaa(x1) balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaaaaaaaaa U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaaaaaaaaa(x3, x19) U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaaaaaaaaa(x19) U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaagagaaag(x19) [] = [] balance_out_ga(x1, x2) = balance_out_ga BALANCE_IN_GA(x1, x2) = BALANCE_IN_GA(x1) U1_GA(x1, x2, x3) = U1_GA(x3) BALANCE55_IN_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = BALANCE55_IN_GAAGAGAAAG(x1, x4, x6, x10) U2_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_GAAGAGAAAG(x3, x6, x8, x18, x19) BALANCE55_IN_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = BALANCE55_IN_GAAAAAAAAA(x1) U2_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_GAAAAAAAAA(x3, x19) U3_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_GAAAAAAAAA(x19) U3_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_GAAGAGAAAG(x19) We have to consider all (P,R,Pi)-chains ---------------------------------------- (4) Obligation: Pi DP problem: The TRS P consists of the following rules: BALANCE_IN_GA(T, TB) -> U1_GA(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) BALANCE_IN_GA(T, TB) -> BALANCE55_IN_GAAGAGAAAG(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, []) BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)) U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAAAAAAAA(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT) U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAGAGAAAG(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT) The TRS R consists of the following rules: balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB) The argument filtering Pi contains the following mapping: balance_in_ga(x1, x2) = balance_in_ga(x1) U1_ga(x1, x2, x3) = U1_ga(x3) balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaagagaaag(x1, x4, x6, x10) nil = nil balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaagagaaag tree(x1, x2, x3) = tree(x1, x2, x3) U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaagagaaag(x3, x6, x8, x18, x19) balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaaaaaaaaa(x1) balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaaaaaaaaa U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaaaaaaaaa(x3, x19) U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaaaaaaaaa(x19) U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaagagaaag(x19) [] = [] balance_out_ga(x1, x2) = balance_out_ga BALANCE_IN_GA(x1, x2) = BALANCE_IN_GA(x1) U1_GA(x1, x2, x3) = U1_GA(x3) BALANCE55_IN_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = BALANCE55_IN_GAAGAGAAAG(x1, x4, x6, x10) U2_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_GAAGAGAAAG(x3, x6, x8, x18, x19) BALANCE55_IN_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = BALANCE55_IN_GAAAAAAAAA(x1) U2_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_GAAAAAAAAA(x3, x19) U3_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_GAAAAAAAAA(x19) U3_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_GAAGAGAAAG(x19) We have to consider all (P,R,Pi)-chains ---------------------------------------- (5) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LOPSTR] contains 2 SCCs with 5 less nodes. ---------------------------------------- (6) Complex Obligation (AND) ---------------------------------------- (7) Obligation: Pi DP problem: The TRS P consists of the following rules: U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAAAAAAAA(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)) The TRS R consists of the following rules: balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB) The argument filtering Pi contains the following mapping: balance_in_ga(x1, x2) = balance_in_ga(x1) U1_ga(x1, x2, x3) = U1_ga(x3) balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaagagaaag(x1, x4, x6, x10) nil = nil balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaagagaaag tree(x1, x2, x3) = tree(x1, x2, x3) U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaagagaaag(x3, x6, x8, x18, x19) balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaaaaaaaaa(x1) balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaaaaaaaaa U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaaaaaaaaa(x3, x19) U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaaaaaaaaa(x19) U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaagagaaag(x19) [] = [] balance_out_ga(x1, x2) = balance_out_ga BALANCE55_IN_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = BALANCE55_IN_GAAAAAAAAA(x1) U2_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_GAAAAAAAAA(x3, x19) We have to consider all (P,R,Pi)-chains ---------------------------------------- (8) UsableRulesProof (EQUIVALENT) For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R. ---------------------------------------- (9) Obligation: Pi DP problem: The TRS P consists of the following rules: U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAAAAAAAA(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAAAAAAAA(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> BALANCE55_IN_GAAAAAAAAA(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1)) The TRS R consists of the following rules: balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) The argument filtering Pi contains the following mapping: nil = nil tree(x1, x2, x3) = tree(x1, x2, x3) balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaaaaaaaaa(x1) balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaaaaaaaaa U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaaaaaaaaa(x3, x19) U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaaaaaaaaa(x19) BALANCE55_IN_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = BALANCE55_IN_GAAAAAAAAA(x1) U2_GAAAAAAAAA(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_GAAAAAAAAA(x3, x19) We have to consider all (P,R,Pi)-chains ---------------------------------------- (10) PiDPToQDPProof (SOUND) Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi. ---------------------------------------- (11) Obligation: Q DP problem: The TRS P consists of the following rules: U2_GAAAAAAAAA(R, balance55_out_gaaaaaaaaa) -> BALANCE55_IN_GAAAAAAAAA(R) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R)) -> U2_GAAAAAAAAA(R, balance55_in_gaaaaaaaaa(L)) BALANCE55_IN_GAAAAAAAAA(tree(L, V, R)) -> BALANCE55_IN_GAAAAAAAAA(L) The TRS R consists of the following rules: balance55_in_gaaaaaaaaa(nil) -> balance55_out_gaaaaaaaaa balance55_in_gaaaaaaaaa(tree(L, V, R)) -> U2_gaaaaaaaaa(R, balance55_in_gaaaaaaaaa(L)) U2_gaaaaaaaaa(R, balance55_out_gaaaaaaaaa) -> U3_gaaaaaaaaa(balance55_in_gaaaaaaaaa(R)) U3_gaaaaaaaaa(balance55_out_gaaaaaaaaa) -> balance55_out_gaaaaaaaaa The set Q consists of the following terms: balance55_in_gaaaaaaaaa(x0) U2_gaaaaaaaaa(x0, x1) U3_gaaaaaaaaa(x0) We have to consider all (P,Q,R)-chains. ---------------------------------------- (12) QDPSizeChangeProof (EQUIVALENT) By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. From the DPs we obtained the following set of size-change graphs: *BALANCE55_IN_GAAAAAAAAA(tree(L, V, R)) -> U2_GAAAAAAAAA(R, balance55_in_gaaaaaaaaa(L)) The graph contains the following edges 1 > 1 *BALANCE55_IN_GAAAAAAAAA(tree(L, V, R)) -> BALANCE55_IN_GAAAAAAAAA(L) The graph contains the following edges 1 > 1 *U2_GAAAAAAAAA(R, balance55_out_gaaaaaaaaa) -> BALANCE55_IN_GAAAAAAAAA(R) The graph contains the following edges 1 >= 1 ---------------------------------------- (13) YES ---------------------------------------- (14) Obligation: Pi DP problem: The TRS P consists of the following rules: U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAGAGAAAG(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT) BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) The TRS R consists of the following rules: balance_in_ga(T, TB) -> U1_ga(T, TB, balance55_in_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) balance55_in_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaagagaaag(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U2_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaagagaaag(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaagagaaag(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaagagaaag(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) U1_ga(T, TB, balance55_out_gaagagaaag(T, XX0, XX1, [], .(','(nil, -(XX0, XX0)), XX1), [], .(','(TB, -(I, [])), X), X, I, [])) -> balance_out_ga(T, TB) The argument filtering Pi contains the following mapping: balance_in_ga(x1, x2) = balance_in_ga(x1) U1_ga(x1, x2, x3) = U1_ga(x3) balance55_in_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaagagaaag(x1, x4, x6, x10) nil = nil balance55_out_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaagagaaag tree(x1, x2, x3) = tree(x1, x2, x3) U2_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaagagaaag(x3, x6, x8, x18, x19) balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaaaaaaaaa(x1) balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaaaaaaaaa U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaaaaaaaaa(x3, x19) U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaaaaaaaaa(x19) U3_gaagagaaag(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaagagaaag(x19) [] = [] balance_out_ga(x1, x2) = balance_out_ga BALANCE55_IN_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = BALANCE55_IN_GAAGAGAAAG(x1, x4, x6, x10) U2_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_GAAGAGAAAG(x3, x6, x8, x18, x19) We have to consider all (P,R,Pi)-chains ---------------------------------------- (15) UsableRulesProof (EQUIVALENT) For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R. ---------------------------------------- (16) Obligation: Pi DP problem: The TRS P consists of the following rules: U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> BALANCE55_IN_GAAGAGAAAG(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT) BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_GAAGAGAAAG(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) The TRS R consists of the following rules: balance55_in_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) -> balance55_out_gaaaaaaaaa(nil, C, T, T, A, B, A, B, X, X) balance55_in_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) -> U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) U2_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(L, XX0, XX1, .(','(nil, -(XX2, XX2)), XX3), HR1, TR1, H, T, IH, .(V, IT1))) -> U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_in_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) U3_gaaaaaaaaa(L, V, R, XX0, XX1, NT, HR, TR, LB, VB, RB, A, D, H, X, T, IH, IT, balance55_out_gaaaaaaaaa(R, XX2, XX3, NT, HR, TR, HR1, TR1, IT1, IT)) -> balance55_out_gaaaaaaaaa(tree(L, V, R), XX0, XX1, NT, HR, TR, .(','(tree(LB, VB, RB), -(A, D)), H), .(','(LB, -(A, .(VB, X))), .(','(RB, -(X, D)), T)), IH, IT) The argument filtering Pi contains the following mapping: nil = nil tree(x1, x2, x3) = tree(x1, x2, x3) balance55_in_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_in_gaaaaaaaaa(x1) balance55_out_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = balance55_out_gaaaaaaaaa U2_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_gaaaaaaaaa(x3, x19) U3_gaaaaaaaaa(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U3_gaaaaaaaaa(x19) BALANCE55_IN_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10) = BALANCE55_IN_GAAGAGAAAG(x1, x4, x6, x10) U2_GAAGAGAAAG(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19) = U2_GAAGAGAAAG(x3, x6, x8, x18, x19) We have to consider all (P,R,Pi)-chains ---------------------------------------- (17) PiDPToQDPProof (SOUND) Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi. ---------------------------------------- (18) Obligation: Q DP problem: The TRS P consists of the following rules: U2_GAAGAGAAAG(R, NT, TR, IT, balance55_out_gaaaaaaaaa) -> BALANCE55_IN_GAAGAGAAAG(R, NT, TR, IT) BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), NT, TR, IT) -> U2_GAAGAGAAAG(R, NT, TR, IT, balance55_in_gaaaaaaaaa(L)) The TRS R consists of the following rules: balance55_in_gaaaaaaaaa(nil) -> balance55_out_gaaaaaaaaa balance55_in_gaaaaaaaaa(tree(L, V, R)) -> U2_gaaaaaaaaa(R, balance55_in_gaaaaaaaaa(L)) U2_gaaaaaaaaa(R, balance55_out_gaaaaaaaaa) -> U3_gaaaaaaaaa(balance55_in_gaaaaaaaaa(R)) U3_gaaaaaaaaa(balance55_out_gaaaaaaaaa) -> balance55_out_gaaaaaaaaa The set Q consists of the following terms: balance55_in_gaaaaaaaaa(x0) U2_gaaaaaaaaa(x0, x1) U3_gaaaaaaaaa(x0) We have to consider all (P,Q,R)-chains. ---------------------------------------- (19) QDPSizeChangeProof (EQUIVALENT) By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. From the DPs we obtained the following set of size-change graphs: *BALANCE55_IN_GAAGAGAAAG(tree(L, V, R), NT, TR, IT) -> U2_GAAGAGAAAG(R, NT, TR, IT, balance55_in_gaaaaaaaaa(L)) The graph contains the following edges 1 > 1, 2 >= 2, 3 >= 3, 4 >= 4 *U2_GAAGAGAAAG(R, NT, TR, IT, balance55_out_gaaaaaaaaa) -> BALANCE55_IN_GAAGAGAAAG(R, NT, TR, IT) The graph contains the following edges 1 >= 1, 2 >= 2, 3 >= 3, 4 >= 4 ---------------------------------------- (20) YES