/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.pl /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.pl # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Left Termination of the query pattern app3_a(g,g,g,a) w.r.t. the given Prolog program could successfully be proven: (0) Prolog (1) PrologToPiTRSProof [SOUND, 0 ms] (2) PiTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) PiDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) PiDP (7) UsableRulesProof [EQUIVALENT, 0 ms] (8) PiDP (9) PiDPToQDPProof [SOUND, 0 ms] (10) QDP (11) QDPSizeChangeProof [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Clauses: app3_a(Xs, Ys, Zs, Us) :- ','(app(Xs, Ys, Vs), app(Vs, Zs, Us)). app3_b(Xs, Ys, Zs, Us) :- ','(app(Ys, Zs, Vs), app(Xs, Vs, Us)). app([], Ys, Ys). app(.(X, Xs), Ys, .(X, Zs)) :- app(Xs, Ys, Zs). Query: app3_a(g,g,g,a) ---------------------------------------- (1) PrologToPiTRSProof (SOUND) We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes: app3_a_in_4: (b,b,b,f) app_in_3: (b,b,f) Transforming Prolog into the following Term Rewriting System: Pi-finite rewrite system: The TRS R consists of the following rules: app3_a_in_ggga(Xs, Ys, Zs, Us) -> U1_ggga(Xs, Ys, Zs, Us, app_in_gga(Xs, Ys, Vs)) app_in_gga([], Ys, Ys) -> app_out_gga([], Ys, Ys) app_in_gga(.(X, Xs), Ys, .(X, Zs)) -> U5_gga(X, Xs, Ys, Zs, app_in_gga(Xs, Ys, Zs)) U5_gga(X, Xs, Ys, Zs, app_out_gga(Xs, Ys, Zs)) -> app_out_gga(.(X, Xs), Ys, .(X, Zs)) U1_ggga(Xs, Ys, Zs, Us, app_out_gga(Xs, Ys, Vs)) -> U2_ggga(Xs, Ys, Zs, Us, app_in_gga(Vs, Zs, Us)) U2_ggga(Xs, Ys, Zs, Us, app_out_gga(Vs, Zs, Us)) -> app3_a_out_ggga(Xs, Ys, Zs, Us) The argument filtering Pi contains the following mapping: app3_a_in_ggga(x1, x2, x3, x4) = app3_a_in_ggga(x1, x2, x3) U1_ggga(x1, x2, x3, x4, x5) = U1_ggga(x1, x2, x3, x5) app_in_gga(x1, x2, x3) = app_in_gga(x1, x2) [] = [] app_out_gga(x1, x2, x3) = app_out_gga(x1, x2, x3) .(x1, x2) = .(x1, x2) U5_gga(x1, x2, x3, x4, x5) = U5_gga(x1, x2, x3, x5) U2_ggga(x1, x2, x3, x4, x5) = U2_ggga(x1, x2, x3, x5) app3_a_out_ggga(x1, x2, x3, x4) = app3_a_out_ggga(x1, x2, x3, x4) Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog ---------------------------------------- (2) Obligation: Pi-finite rewrite system: The TRS R consists of the following rules: app3_a_in_ggga(Xs, Ys, Zs, Us) -> U1_ggga(Xs, Ys, Zs, Us, app_in_gga(Xs, Ys, Vs)) app_in_gga([], Ys, Ys) -> app_out_gga([], Ys, Ys) app_in_gga(.(X, Xs), Ys, .(X, Zs)) -> U5_gga(X, Xs, Ys, Zs, app_in_gga(Xs, Ys, Zs)) U5_gga(X, Xs, Ys, Zs, app_out_gga(Xs, Ys, Zs)) -> app_out_gga(.(X, Xs), Ys, .(X, Zs)) U1_ggga(Xs, Ys, Zs, Us, app_out_gga(Xs, Ys, Vs)) -> U2_ggga(Xs, Ys, Zs, Us, app_in_gga(Vs, Zs, Us)) U2_ggga(Xs, Ys, Zs, Us, app_out_gga(Vs, Zs, Us)) -> app3_a_out_ggga(Xs, Ys, Zs, Us) The argument filtering Pi contains the following mapping: app3_a_in_ggga(x1, x2, x3, x4) = app3_a_in_ggga(x1, x2, x3) U1_ggga(x1, x2, x3, x4, x5) = U1_ggga(x1, x2, x3, x5) app_in_gga(x1, x2, x3) = app_in_gga(x1, x2) [] = [] app_out_gga(x1, x2, x3) = app_out_gga(x1, x2, x3) .(x1, x2) = .(x1, x2) U5_gga(x1, x2, x3, x4, x5) = U5_gga(x1, x2, x3, x5) U2_ggga(x1, x2, x3, x4, x5) = U2_ggga(x1, x2, x3, x5) app3_a_out_ggga(x1, x2, x3, x4) = app3_a_out_ggga(x1, x2, x3, x4) ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem: Pi DP problem: The TRS P consists of the following rules: APP3_A_IN_GGGA(Xs, Ys, Zs, Us) -> U1_GGGA(Xs, Ys, Zs, Us, app_in_gga(Xs, Ys, Vs)) APP3_A_IN_GGGA(Xs, Ys, Zs, Us) -> APP_IN_GGA(Xs, Ys, Vs) APP_IN_GGA(.(X, Xs), Ys, .(X, Zs)) -> U5_GGA(X, Xs, Ys, Zs, app_in_gga(Xs, Ys, Zs)) APP_IN_GGA(.(X, Xs), Ys, .(X, Zs)) -> APP_IN_GGA(Xs, Ys, Zs) U1_GGGA(Xs, Ys, Zs, Us, app_out_gga(Xs, Ys, Vs)) -> U2_GGGA(Xs, Ys, Zs, Us, app_in_gga(Vs, Zs, Us)) U1_GGGA(Xs, Ys, Zs, Us, app_out_gga(Xs, Ys, Vs)) -> APP_IN_GGA(Vs, Zs, Us) The TRS R consists of the following rules: app3_a_in_ggga(Xs, Ys, Zs, Us) -> U1_ggga(Xs, Ys, Zs, Us, app_in_gga(Xs, Ys, Vs)) app_in_gga([], Ys, Ys) -> app_out_gga([], Ys, Ys) app_in_gga(.(X, Xs), Ys, .(X, Zs)) -> U5_gga(X, Xs, Ys, Zs, app_in_gga(Xs, Ys, Zs)) U5_gga(X, Xs, Ys, Zs, app_out_gga(Xs, Ys, Zs)) -> app_out_gga(.(X, Xs), Ys, .(X, Zs)) U1_ggga(Xs, Ys, Zs, Us, app_out_gga(Xs, Ys, Vs)) -> U2_ggga(Xs, Ys, Zs, Us, app_in_gga(Vs, Zs, Us)) U2_ggga(Xs, Ys, Zs, Us, app_out_gga(Vs, Zs, Us)) -> app3_a_out_ggga(Xs, Ys, Zs, Us) The argument filtering Pi contains the following mapping: app3_a_in_ggga(x1, x2, x3, x4) = app3_a_in_ggga(x1, x2, x3) U1_ggga(x1, x2, x3, x4, x5) = U1_ggga(x1, x2, x3, x5) app_in_gga(x1, x2, x3) = app_in_gga(x1, x2) [] = [] app_out_gga(x1, x2, x3) = app_out_gga(x1, x2, x3) .(x1, x2) = .(x1, x2) U5_gga(x1, x2, x3, x4, x5) = U5_gga(x1, x2, x3, x5) U2_ggga(x1, x2, x3, x4, x5) = U2_ggga(x1, x2, x3, x5) app3_a_out_ggga(x1, x2, x3, x4) = app3_a_out_ggga(x1, x2, x3, x4) APP3_A_IN_GGGA(x1, x2, x3, x4) = APP3_A_IN_GGGA(x1, x2, x3) U1_GGGA(x1, x2, x3, x4, x5) = U1_GGGA(x1, x2, x3, x5) APP_IN_GGA(x1, x2, x3) = APP_IN_GGA(x1, x2) U5_GGA(x1, x2, x3, x4, x5) = U5_GGA(x1, x2, x3, x5) U2_GGGA(x1, x2, x3, x4, x5) = U2_GGGA(x1, x2, x3, x5) We have to consider all (P,R,Pi)-chains ---------------------------------------- (4) Obligation: Pi DP problem: The TRS P consists of the following rules: APP3_A_IN_GGGA(Xs, Ys, Zs, Us) -> U1_GGGA(Xs, Ys, Zs, Us, app_in_gga(Xs, Ys, Vs)) APP3_A_IN_GGGA(Xs, Ys, Zs, Us) -> APP_IN_GGA(Xs, Ys, Vs) APP_IN_GGA(.(X, Xs), Ys, .(X, Zs)) -> U5_GGA(X, Xs, Ys, Zs, app_in_gga(Xs, Ys, Zs)) APP_IN_GGA(.(X, Xs), Ys, .(X, Zs)) -> APP_IN_GGA(Xs, Ys, Zs) U1_GGGA(Xs, Ys, Zs, Us, app_out_gga(Xs, Ys, Vs)) -> U2_GGGA(Xs, Ys, Zs, Us, app_in_gga(Vs, Zs, Us)) U1_GGGA(Xs, Ys, Zs, Us, app_out_gga(Xs, Ys, Vs)) -> APP_IN_GGA(Vs, Zs, Us) The TRS R consists of the following rules: app3_a_in_ggga(Xs, Ys, Zs, Us) -> U1_ggga(Xs, Ys, Zs, Us, app_in_gga(Xs, Ys, Vs)) app_in_gga([], Ys, Ys) -> app_out_gga([], Ys, Ys) app_in_gga(.(X, Xs), Ys, .(X, Zs)) -> U5_gga(X, Xs, Ys, Zs, app_in_gga(Xs, Ys, Zs)) U5_gga(X, Xs, Ys, Zs, app_out_gga(Xs, Ys, Zs)) -> app_out_gga(.(X, Xs), Ys, .(X, Zs)) U1_ggga(Xs, Ys, Zs, Us, app_out_gga(Xs, Ys, Vs)) -> U2_ggga(Xs, Ys, Zs, Us, app_in_gga(Vs, Zs, Us)) U2_ggga(Xs, Ys, Zs, Us, app_out_gga(Vs, Zs, Us)) -> app3_a_out_ggga(Xs, Ys, Zs, Us) The argument filtering Pi contains the following mapping: app3_a_in_ggga(x1, x2, x3, x4) = app3_a_in_ggga(x1, x2, x3) U1_ggga(x1, x2, x3, x4, x5) = U1_ggga(x1, x2, x3, x5) app_in_gga(x1, x2, x3) = app_in_gga(x1, x2) [] = [] app_out_gga(x1, x2, x3) = app_out_gga(x1, x2, x3) .(x1, x2) = .(x1, x2) U5_gga(x1, x2, x3, x4, x5) = U5_gga(x1, x2, x3, x5) U2_ggga(x1, x2, x3, x4, x5) = U2_ggga(x1, x2, x3, x5) app3_a_out_ggga(x1, x2, x3, x4) = app3_a_out_ggga(x1, x2, x3, x4) APP3_A_IN_GGGA(x1, x2, x3, x4) = APP3_A_IN_GGGA(x1, x2, x3) U1_GGGA(x1, x2, x3, x4, x5) = U1_GGGA(x1, x2, x3, x5) APP_IN_GGA(x1, x2, x3) = APP_IN_GGA(x1, x2) U5_GGA(x1, x2, x3, x4, x5) = U5_GGA(x1, x2, x3, x5) U2_GGGA(x1, x2, x3, x4, x5) = U2_GGGA(x1, x2, x3, x5) We have to consider all (P,R,Pi)-chains ---------------------------------------- (5) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 5 less nodes. ---------------------------------------- (6) Obligation: Pi DP problem: The TRS P consists of the following rules: APP_IN_GGA(.(X, Xs), Ys, .(X, Zs)) -> APP_IN_GGA(Xs, Ys, Zs) The TRS R consists of the following rules: app3_a_in_ggga(Xs, Ys, Zs, Us) -> U1_ggga(Xs, Ys, Zs, Us, app_in_gga(Xs, Ys, Vs)) app_in_gga([], Ys, Ys) -> app_out_gga([], Ys, Ys) app_in_gga(.(X, Xs), Ys, .(X, Zs)) -> U5_gga(X, Xs, Ys, Zs, app_in_gga(Xs, Ys, Zs)) U5_gga(X, Xs, Ys, Zs, app_out_gga(Xs, Ys, Zs)) -> app_out_gga(.(X, Xs), Ys, .(X, Zs)) U1_ggga(Xs, Ys, Zs, Us, app_out_gga(Xs, Ys, Vs)) -> U2_ggga(Xs, Ys, Zs, Us, app_in_gga(Vs, Zs, Us)) U2_ggga(Xs, Ys, Zs, Us, app_out_gga(Vs, Zs, Us)) -> app3_a_out_ggga(Xs, Ys, Zs, Us) The argument filtering Pi contains the following mapping: app3_a_in_ggga(x1, x2, x3, x4) = app3_a_in_ggga(x1, x2, x3) U1_ggga(x1, x2, x3, x4, x5) = U1_ggga(x1, x2, x3, x5) app_in_gga(x1, x2, x3) = app_in_gga(x1, x2) [] = [] app_out_gga(x1, x2, x3) = app_out_gga(x1, x2, x3) .(x1, x2) = .(x1, x2) U5_gga(x1, x2, x3, x4, x5) = U5_gga(x1, x2, x3, x5) U2_ggga(x1, x2, x3, x4, x5) = U2_ggga(x1, x2, x3, x5) app3_a_out_ggga(x1, x2, x3, x4) = app3_a_out_ggga(x1, x2, x3, x4) APP_IN_GGA(x1, x2, x3) = APP_IN_GGA(x1, x2) We have to consider all (P,R,Pi)-chains ---------------------------------------- (7) UsableRulesProof (EQUIVALENT) For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R. ---------------------------------------- (8) Obligation: Pi DP problem: The TRS P consists of the following rules: APP_IN_GGA(.(X, Xs), Ys, .(X, Zs)) -> APP_IN_GGA(Xs, Ys, Zs) R is empty. The argument filtering Pi contains the following mapping: .(x1, x2) = .(x1, x2) APP_IN_GGA(x1, x2, x3) = APP_IN_GGA(x1, x2) We have to consider all (P,R,Pi)-chains ---------------------------------------- (9) PiDPToQDPProof (SOUND) Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi. ---------------------------------------- (10) Obligation: Q DP problem: The TRS P consists of the following rules: APP_IN_GGA(.(X, Xs), Ys) -> APP_IN_GGA(Xs, Ys) R is empty. Q is empty. We have to consider all (P,Q,R)-chains. ---------------------------------------- (11) QDPSizeChangeProof (EQUIVALENT) By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. From the DPs we obtained the following set of size-change graphs: *APP_IN_GGA(.(X, Xs), Ys) -> APP_IN_GGA(Xs, Ys) The graph contains the following edges 1 > 1, 2 >= 2 ---------------------------------------- (12) YES