/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.hs /export/starexec/sandbox/output/output_files


--------------------------------------------------------------------------------


MAYBE
proof of /export/starexec/sandbox/benchmark/theBenchmark.hs
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


H-Termination with start terms of the given HASKELL could not be shown:

(0) HASKELL
(1) BR [EQUIVALENT, 0 ms]
(2) HASKELL
(3) COR [EQUIVALENT, 0 ms]
(4) HASKELL
(5) NumRed [SOUND, 0 ms]
(6) HASKELL
(7) Narrow [COMPLETE, 0 ms]
(8) QDP
(9) NonTerminationLoopProof [COMPLETE, 0 ms]
(10) NO


----------------------------------------

(0)
Obligation:
mainModule Main 
module Main where {
import qualified Prelude;
}

----------------------------------------

(1) BR (EQUIVALENT)
Replaced joker patterns by fresh variables and removed binding patterns.
----------------------------------------

(2)
Obligation:
mainModule Main 
module Main where {
import qualified Prelude;
}

----------------------------------------

(3) COR (EQUIVALENT)
Cond Reductions:
The following Function with conditions
"undefined |Falseundefined;
"
is transformed to
"undefined  = undefined1;
"
"undefined0 True = undefined;
"
"undefined1  = undefined0 False;
"

----------------------------------------

(4)
Obligation:
mainModule Main 
module Main where {
import qualified Prelude;
}

----------------------------------------

(5) NumRed (SOUND)
Num Reduction:All numbers are transformed to their corresponding representation with Succ, Pred and Zero.
----------------------------------------

(6)
Obligation:
mainModule Main 
module Main where {
import qualified Prelude;
}

----------------------------------------

(7) Narrow (COMPLETE)
Haskell To QDPs

digraph dp_graph {
node [outthreshold=100, inthreshold=100];1[label="minBound",fontsize=16,color="blue",shape="box"];14[label="minBound :: Char",fontsize=10,color="white",style="solid",shape="box"];1 -> 14[label="",style="solid", color="blue", weight=9];
14 -> 3[label="",style="solid", color="blue", weight=3];
15[label="minBound :: Bool",fontsize=10,color="white",style="solid",shape="box"];1 -> 15[label="",style="solid", color="blue", weight=9];
15 -> 4[label="",style="solid", color="blue", weight=3];
16[label="minBound :: Int",fontsize=10,color="white",style="solid",shape="box"];1 -> 16[label="",style="solid", color="blue", weight=9];
16 -> 5[label="",style="solid", color="blue", weight=3];
17[label="minBound :: Ordering",fontsize=10,color="white",style="solid",shape="box"];1 -> 17[label="",style="solid", color="blue", weight=9];
17 -> 6[label="",style="solid", color="blue", weight=3];
18[label="minBound :: ()",fontsize=10,color="white",style="solid",shape="box"];1 -> 18[label="",style="solid", color="blue", weight=9];
18 -> 7[label="",style="solid", color="blue", weight=3];
3[label="minBound",fontsize=16,color="black",shape="box"];3 -> 8[label="",style="solid", color="black", weight=3];
4[label="minBound",fontsize=16,color="black",shape="box"];4 -> 9[label="",style="solid", color="black", weight=3];
5[label="minBound",fontsize=16,color="black",shape="box"];5 -> 10[label="",style="solid", color="black", weight=3];
6[label="minBound",fontsize=16,color="black",shape="box"];6 -> 11[label="",style="solid", color="black", weight=3];
7[label="minBound",fontsize=16,color="black",shape="box"];7 -> 12[label="",style="solid", color="black", weight=3];
8[label="Char Zero",fontsize=16,color="green",shape="box"];9[label="False",fontsize=16,color="green",shape="box"];10[label="primMinInt",fontsize=16,color="black",shape="triangle"];10 -> 13[label="",style="solid", color="black", weight=3];
11[label="LT",fontsize=16,color="green",shape="box"];12[label="()",fontsize=16,color="green",shape="box"];13 -> 10[label="",style="dashed", color="red", weight=0];
13[label="primMinInt",fontsize=16,color="magenta"];}

----------------------------------------

(8)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   new_primMinInt([]) -> new_primMinInt([])

R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
----------------------------------------

(9) NonTerminationLoopProof (COMPLETE)
We used the non-termination processor [FROCOS05] to show that the DP problem is infinite.
Found a loop by semiunifying a rule from P directly.

s = new_primMinInt([]) evaluates to  t =new_primMinInt([])

Thus s starts an infinite chain as s semiunifies with t with the following substitutions:
* Matcher: [ ]
* Semiunifier: [ ]

--------------------------------------------------------------------------------
Rewriting sequence

The DP semiunifies directly so there is only one rewrite step from new_primMinInt([]) to new_primMinInt([]).




----------------------------------------

(10)
NO