/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.hs /export/starexec/sandbox/output/output_files


--------------------------------------------------------------------------------


YES
proof of /export/starexec/sandbox/benchmark/theBenchmark.hs
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


H-Termination with start terms of the given HASKELL could be proven:

(0) HASKELL
(1) BR [EQUIVALENT, 0 ms]
(2) HASKELL
(3) COR [EQUIVALENT, 0 ms]
(4) HASKELL
(5) Narrow [SOUND, 0 ms]
(6) QDP
(7) QDPSizeChangeProof [EQUIVALENT, 0 ms]
(8) YES


----------------------------------------

(0)
Obligation:
mainModule Main 
module Main where {
import qualified Prelude;
data List a = Cons a (List a)  | Nil ;

init :: List a  ->  List a;
init (Cons x Nil) = Nil;
init (Cons x xs) = Cons x (init xs);

}

----------------------------------------

(1) BR (EQUIVALENT)
Replaced joker patterns by fresh variables and removed binding patterns.
----------------------------------------

(2)
Obligation:
mainModule Main 
module Main where {
import qualified Prelude;
data List a = Cons a (List a)  | Nil ;

init :: List a  ->  List a;
init (Cons x Nil) = Nil;
init (Cons x xs) = Cons x (init xs);

}

----------------------------------------

(3) COR (EQUIVALENT)
Cond Reductions:
The following Function with conditions
"undefined |Falseundefined;
"
is transformed to
"undefined  = undefined1;
"
"undefined0 True = undefined;
"
"undefined1  = undefined0 False;
"

----------------------------------------

(4)
Obligation:
mainModule Main 
module Main where {
import qualified Prelude;
data List a = Cons a (List a)  | Nil ;

init :: List a  ->  List a;
init (Cons x Nil) = Nil;
init (Cons x xs) = Cons x (init xs);

}

----------------------------------------

(5) Narrow (SOUND)
Haskell To QDPs

digraph dp_graph {
node [outthreshold=100, inthreshold=100];1[label="init",fontsize=16,color="grey",shape="box"];1 -> 3[label="",style="dashed", color="grey", weight=3];
3[label="init vx3",fontsize=16,color="burlywood",shape="triangle"];13[label="vx3/Cons vx30 vx31",fontsize=10,color="white",style="solid",shape="box"];3 -> 13[label="",style="solid", color="burlywood", weight=9];
13 -> 4[label="",style="solid", color="burlywood", weight=3];
14[label="vx3/Nil",fontsize=10,color="white",style="solid",shape="box"];3 -> 14[label="",style="solid", color="burlywood", weight=9];
14 -> 5[label="",style="solid", color="burlywood", weight=3];
4[label="init (Cons vx30 vx31)",fontsize=16,color="burlywood",shape="box"];15[label="vx31/Cons vx310 vx311",fontsize=10,color="white",style="solid",shape="box"];4 -> 15[label="",style="solid", color="burlywood", weight=9];
15 -> 6[label="",style="solid", color="burlywood", weight=3];
16[label="vx31/Nil",fontsize=10,color="white",style="solid",shape="box"];4 -> 16[label="",style="solid", color="burlywood", weight=9];
16 -> 7[label="",style="solid", color="burlywood", weight=3];
5[label="init Nil",fontsize=16,color="black",shape="box"];5 -> 8[label="",style="solid", color="black", weight=3];
6[label="init (Cons vx30 (Cons vx310 vx311))",fontsize=16,color="black",shape="box"];6 -> 9[label="",style="solid", color="black", weight=3];
7[label="init (Cons vx30 Nil)",fontsize=16,color="black",shape="box"];7 -> 10[label="",style="solid", color="black", weight=3];
8[label="error []",fontsize=16,color="red",shape="box"];9[label="Cons vx30 (init (Cons vx310 vx311))",fontsize=16,color="green",shape="box"];9 -> 11[label="",style="dashed", color="green", weight=3];
10[label="Nil",fontsize=16,color="green",shape="box"];11 -> 3[label="",style="dashed", color="red", weight=0];
11[label="init (Cons vx310 vx311)",fontsize=16,color="magenta"];11 -> 12[label="",style="dashed", color="magenta", weight=3];
12[label="Cons vx310 vx311",fontsize=16,color="green",shape="box"];}

----------------------------------------

(6)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   new_init(Cons(vx30, Cons(vx310, vx311)), h) -> new_init(Cons(vx310, vx311), h)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
----------------------------------------

(7) QDPSizeChangeProof (EQUIVALENT)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 

From the DPs we obtained the following set of size-change graphs:
*new_init(Cons(vx30, Cons(vx310, vx311)), h) -> new_init(Cons(vx310, vx311), h)
The graph contains the following edges 1 > 1, 2 >= 2


----------------------------------------

(8)
YES