5.34/2.08 YES 6.45/2.38 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 6.45/2.38 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 6.45/2.38 6.45/2.38 6.45/2.38 Termination of the given RelTRS could be proven: 6.45/2.38 6.45/2.38 (0) RelTRS 6.45/2.38 (1) RelTRSRRRProof [EQUIVALENT, 56 ms] 6.45/2.38 (2) RelTRS 6.45/2.38 (3) RIsEmptyProof [EQUIVALENT, 2 ms] 6.45/2.38 (4) YES 6.45/2.38 6.45/2.38 6.45/2.38 ---------------------------------------- 6.45/2.38 6.45/2.38 (0) 6.45/2.38 Obligation: 6.45/2.38 Relative term rewrite system: 6.45/2.38 The relative TRS consists of the following R rules: 6.45/2.38 6.45/2.38 f(el(x), y) -> f(x, el(y)) 6.45/2.38 6.45/2.38 The relative TRS consists of the following S rules: 6.45/2.38 6.45/2.38 f(x, y) -> f(l(x), y) 6.45/2.38 f(x, y) -> f(x, r(y)) 6.45/2.38 l(el(x)) -> el(l(x)) 6.45/2.38 el(r(x)) -> r(el(x)) 6.45/2.38 6.45/2.38 6.45/2.38 ---------------------------------------- 6.45/2.38 6.45/2.38 (1) RelTRSRRRProof (EQUIVALENT) 6.45/2.38 We used the following monotonic ordering for rule removal: 6.45/2.38 Matrix interpretation [MATRO] to (N^2, +, *, >=, >) : 6.45/2.38 6.45/2.38 <<< 6.45/2.38 POL(f(x_1, x_2)) = [[1], [1]] + [[1, 1], [1, 1]] * x_1 + [[1, 0], [1, 0]] * x_2 6.45/2.38 >>> 6.45/2.38 6.45/2.38 <<< 6.45/2.38 POL(el(x_1)) = [[1], [1]] + [[1, 0], [1, 1]] * x_1 6.45/2.38 >>> 6.45/2.38 6.45/2.38 <<< 6.45/2.38 POL(l(x_1)) = [[0], [0]] + [[1, 0], [0, 1]] * x_1 6.45/2.38 >>> 6.45/2.38 6.45/2.38 <<< 6.45/2.38 POL(r(x_1)) = [[0], [1]] + [[1, 0], [0, 1]] * x_1 6.45/2.38 >>> 6.45/2.38 6.45/2.38 With this ordering the following rules can be removed [MATRO] because they are oriented strictly: 6.45/2.38 Rules from R: 6.45/2.38 6.45/2.38 f(el(x), y) -> f(x, el(y)) 6.45/2.38 Rules from S: 6.45/2.38 none 6.45/2.38 6.45/2.38 6.45/2.38 6.45/2.38 6.45/2.38 ---------------------------------------- 6.45/2.38 6.45/2.38 (2) 6.45/2.38 Obligation: 6.45/2.38 Relative term rewrite system: 6.45/2.38 R is empty. 6.45/2.38 The relative TRS consists of the following S rules: 6.45/2.38 6.45/2.38 f(x, y) -> f(l(x), y) 6.45/2.38 f(x, y) -> f(x, r(y)) 6.45/2.38 l(el(x)) -> el(l(x)) 6.45/2.38 el(r(x)) -> r(el(x)) 6.45/2.38 6.45/2.38 6.45/2.38 ---------------------------------------- 6.45/2.38 6.45/2.38 (3) RIsEmptyProof (EQUIVALENT) 6.45/2.38 The TRS R is empty. Hence, termination is trivially proven. 6.45/2.38 ---------------------------------------- 6.45/2.38 6.45/2.38 (4) 6.45/2.38 YES 6.62/2.45 EOF