2.06/1.35 WORST_CASE(?, O(n^1)) 2.06/1.36 proof of /export/starexec/sandbox2/output/output_files/bench.koat 2.06/1.36 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 2.06/1.36 2.06/1.36 2.06/1.36 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, n^1). 2.06/1.36 2.06/1.36 (0) CpxIntTrs 2.06/1.36 (1) Koat Proof [FINISHED, 183 ms] 2.06/1.36 (2) BOUNDS(1, n^1) 2.06/1.36 2.06/1.36 2.06/1.36 ---------------------------------------- 2.06/1.36 2.06/1.36 (0) 2.06/1.36 Obligation: 2.06/1.36 Complexity Int TRS consisting of the following rules: 2.06/1.36 eval_speed_popl10_simple_single_start(v_n, v_x.0) -> Com_1(eval_speed_popl10_simple_single_bb0_in(v_n, v_x.0)) :|: TRUE 2.06/1.36 eval_speed_popl10_simple_single_bb0_in(v_n, v_x.0) -> Com_1(eval_speed_popl10_simple_single_bb1_in(v_n, 0)) :|: TRUE 2.06/1.36 eval_speed_popl10_simple_single_bb1_in(v_n, v_x.0) -> Com_1(eval_speed_popl10_simple_single_bb2_in(v_n, v_x.0)) :|: v_x.0 < v_n 2.06/1.36 eval_speed_popl10_simple_single_bb1_in(v_n, v_x.0) -> Com_1(eval_speed_popl10_simple_single_bb3_in(v_n, v_x.0)) :|: v_x.0 >= v_n 2.06/1.36 eval_speed_popl10_simple_single_bb2_in(v_n, v_x.0) -> Com_1(eval_speed_popl10_simple_single_0(v_n, v_x.0)) :|: TRUE 2.06/1.37 eval_speed_popl10_simple_single_0(v_n, v_x.0) -> Com_2(eval_nondet_start(v_n, v_x.0), eval_speed_popl10_simple_single_1(v_n, v_x.0)) :|: TRUE 2.06/1.37 eval_speed_popl10_simple_single_1(v_n, v_x.0) -> Com_1(eval_speed_popl10_simple_single_bb1_in(v_n, v_x.0 + 1)) :|: TRUE 2.06/1.37 eval_speed_popl10_simple_single_bb3_in(v_n, v_x.0) -> Com_1(eval_speed_popl10_simple_single_stop(v_n, v_x.0)) :|: TRUE 2.06/1.37 2.06/1.37 The start-symbols are:[eval_speed_popl10_simple_single_start_2] 2.06/1.37 2.06/1.37 2.06/1.37 ---------------------------------------- 2.06/1.37 2.06/1.37 (1) Koat Proof (FINISHED) 2.06/1.37 YES(?, 16*ar_1 + 6) 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 Initial complexity problem: 2.06/1.37 2.06/1.37 1: T: 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglestart(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb0in(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb0in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb2in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb3in(ar_0, ar_1)) [ ar_0 >= ar_1 ] 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb2in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesingle0(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesingle0(ar_0, ar_1) -> Com_2(evalnondetstart(ar_0, ar_1), evalspeedpopl10simplesingle1(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesingle1(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(ar_0 + 1, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb3in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestop(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestart(ar_0, ar_1)) [ 0 <= 0 ] 2.06/1.37 2.06/1.37 start location: koat_start 2.06/1.37 2.06/1.37 leaf cost: 0 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 Repeatedly propagating knowledge in problem 1 produces the following problem: 2.06/1.37 2.06/1.37 2: T: 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 1) evalspeedpopl10simplesinglestart(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb0in(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 1) evalspeedpopl10simplesinglebb0in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb2in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb3in(ar_0, ar_1)) [ ar_0 >= ar_1 ] 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb2in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesingle0(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesingle0(ar_0, ar_1) -> Com_2(evalnondetstart(ar_0, ar_1), evalspeedpopl10simplesingle1(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesingle1(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(ar_0 + 1, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb3in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestop(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestart(ar_0, ar_1)) [ 0 <= 0 ] 2.06/1.37 2.06/1.37 start location: koat_start 2.06/1.37 2.06/1.37 leaf cost: 0 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 A polynomial rank function with 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglestart) = 2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglebb0in) = 2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglebb1in) = 2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglebb2in) = 2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglebb3in) = 1 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesingle0) = 2 2.06/1.37 2.06/1.37 Pol(evalnondetstart) = 0 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesingle1) = 2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglestop) = 0 2.06/1.37 2.06/1.37 Pol(koat_start) = 2 2.06/1.37 2.06/1.37 orients all transitions weakly and the transitions 2.06/1.37 2.06/1.37 evalspeedpopl10simplesinglebb3in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestop(ar_0, ar_1)) 2.06/1.37 2.06/1.37 evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb3in(ar_0, ar_1)) [ ar_0 >= ar_1 ] 2.06/1.37 2.06/1.37 strictly and produces the following problem: 2.06/1.37 2.06/1.37 3: T: 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 1) evalspeedpopl10simplesinglestart(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb0in(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 1) evalspeedpopl10simplesinglebb0in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb2in(ar_0, ar_1)) [ ar_1 >= ar_0 + 1 ] 2.06/1.37 2.06/1.37 (Comp: 2, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb3in(ar_0, ar_1)) [ ar_0 >= ar_1 ] 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb2in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesingle0(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesingle0(ar_0, ar_1) -> Com_2(evalnondetstart(ar_0, ar_1), evalspeedpopl10simplesingle1(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesingle1(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(ar_0 + 1, ar_1)) 2.06/1.37 2.06/1.37 (Comp: 2, Cost: 1) evalspeedpopl10simplesinglebb3in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestop(ar_0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestart(ar_0, ar_1)) [ 0 <= 0 ] 2.06/1.37 2.06/1.37 start location: koat_start 2.06/1.37 2.06/1.37 leaf cost: 0 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 Applied AI with 'oct' on problem 3 to obtain the following invariants: 2.06/1.37 2.06/1.37 For symbol evalspeedpopl10simplesingle0: X_2 - 1 >= 0 /\ X_1 + X_2 - 1 >= 0 /\ -X_1 + X_2 - 1 >= 0 /\ X_1 >= 0 2.06/1.37 2.06/1.37 For symbol evalspeedpopl10simplesingle1: X_2 - 1 >= 0 /\ X_1 + X_2 - 1 >= 0 /\ -X_1 + X_2 - 1 >= 0 /\ X_1 >= 0 2.06/1.37 2.06/1.37 For symbol evalspeedpopl10simplesinglebb1in: X_1 >= 0 2.06/1.37 2.06/1.37 For symbol evalspeedpopl10simplesinglebb2in: X_2 - 1 >= 0 /\ X_1 + X_2 - 1 >= 0 /\ -X_1 + X_2 - 1 >= 0 /\ X_1 >= 0 2.06/1.37 2.06/1.37 For symbol evalspeedpopl10simplesinglebb3in: X_1 - X_2 >= 0 /\ X_1 >= 0 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 This yielded the following problem: 2.06/1.37 2.06/1.37 4: T: 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestart(ar_0, ar_1)) [ 0 <= 0 ] 2.06/1.37 2.06/1.37 (Comp: 2, Cost: 1) evalspeedpopl10simplesinglebb3in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestop(ar_0, ar_1)) [ ar_0 - ar_1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesingle1(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(ar_0 + 1, ar_1)) [ ar_1 - 1 >= 0 /\ ar_0 + ar_1 - 1 >= 0 /\ -ar_0 + ar_1 - 1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesingle0(ar_0, ar_1) -> Com_2(evalnondetstart(ar_0, ar_1), evalspeedpopl10simplesingle1(ar_0, ar_1)) [ ar_1 - 1 >= 0 /\ ar_0 + ar_1 - 1 >= 0 /\ -ar_0 + ar_1 - 1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb2in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesingle0(ar_0, ar_1)) [ ar_1 - 1 >= 0 /\ ar_0 + ar_1 - 1 >= 0 /\ -ar_0 + ar_1 - 1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 (Comp: 2, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb3in(ar_0, ar_1)) [ ar_0 >= 0 /\ ar_0 >= ar_1 ] 2.06/1.37 2.06/1.37 (Comp: ?, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb2in(ar_0, ar_1)) [ ar_0 >= 0 /\ ar_1 >= ar_0 + 1 ] 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 1) evalspeedpopl10simplesinglebb0in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 1) evalspeedpopl10simplesinglestart(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb0in(ar_0, ar_1)) 2.06/1.37 2.06/1.37 start location: koat_start 2.06/1.37 2.06/1.37 leaf cost: 0 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 A polynomial rank function with 2.06/1.37 2.06/1.37 Pol(koat_start) = 4*V_2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglestart) = 4*V_2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglebb3in) = -4*V_1 + 4*V_2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglestop) = -4*V_1 + 4*V_2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesingle1) = -4*V_1 + 4*V_2 - 3 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglebb1in) = -4*V_1 + 4*V_2 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesingle0) = -4*V_1 + 4*V_2 - 2 2.06/1.37 2.06/1.37 Pol(evalnondetstart) = -4*V_1 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglebb2in) = -4*V_1 + 4*V_2 - 1 2.06/1.37 2.06/1.37 Pol(evalspeedpopl10simplesinglebb0in) = 4*V_2 2.06/1.37 2.06/1.37 orients all transitions weakly and the transitions 2.06/1.37 2.06/1.37 evalspeedpopl10simplesinglebb2in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesingle0(ar_0, ar_1)) [ ar_1 - 1 >= 0 /\ ar_0 + ar_1 - 1 >= 0 /\ -ar_0 + ar_1 - 1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb2in(ar_0, ar_1)) [ ar_0 >= 0 /\ ar_1 >= ar_0 + 1 ] 2.06/1.37 2.06/1.37 evalspeedpopl10simplesingle1(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(ar_0 + 1, ar_1)) [ ar_1 - 1 >= 0 /\ ar_0 + ar_1 - 1 >= 0 /\ -ar_0 + ar_1 - 1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 evalspeedpopl10simplesingle0(ar_0, ar_1) -> Com_2(evalnondetstart(ar_0, ar_1), evalspeedpopl10simplesingle1(ar_0, ar_1)) [ ar_1 - 1 >= 0 /\ ar_0 + ar_1 - 1 >= 0 /\ -ar_0 + ar_1 - 1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 strictly and produces the following problem: 2.06/1.37 2.06/1.37 5: T: 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestart(ar_0, ar_1)) [ 0 <= 0 ] 2.06/1.37 2.06/1.37 (Comp: 2, Cost: 1) evalspeedpopl10simplesinglebb3in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglestop(ar_0, ar_1)) [ ar_0 - ar_1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 (Comp: 4*ar_1, Cost: 1) evalspeedpopl10simplesingle1(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(ar_0 + 1, ar_1)) [ ar_1 - 1 >= 0 /\ ar_0 + ar_1 - 1 >= 0 /\ -ar_0 + ar_1 - 1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 (Comp: 4*ar_1, Cost: 1) evalspeedpopl10simplesingle0(ar_0, ar_1) -> Com_2(evalnondetstart(ar_0, ar_1), evalspeedpopl10simplesingle1(ar_0, ar_1)) [ ar_1 - 1 >= 0 /\ ar_0 + ar_1 - 1 >= 0 /\ -ar_0 + ar_1 - 1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 (Comp: 4*ar_1, Cost: 1) evalspeedpopl10simplesinglebb2in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesingle0(ar_0, ar_1)) [ ar_1 - 1 >= 0 /\ ar_0 + ar_1 - 1 >= 0 /\ -ar_0 + ar_1 - 1 >= 0 /\ ar_0 >= 0 ] 2.06/1.37 2.06/1.37 (Comp: 2, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb3in(ar_0, ar_1)) [ ar_0 >= 0 /\ ar_0 >= ar_1 ] 2.06/1.37 2.06/1.37 (Comp: 4*ar_1, Cost: 1) evalspeedpopl10simplesinglebb1in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb2in(ar_0, ar_1)) [ ar_0 >= 0 /\ ar_1 >= ar_0 + 1 ] 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 1) evalspeedpopl10simplesinglebb0in(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb1in(0, ar_1)) 2.06/1.37 2.06/1.37 (Comp: 1, Cost: 1) evalspeedpopl10simplesinglestart(ar_0, ar_1) -> Com_1(evalspeedpopl10simplesinglebb0in(ar_0, ar_1)) 2.06/1.37 2.06/1.37 start location: koat_start 2.06/1.37 2.06/1.37 leaf cost: 0 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 Complexity upper bound 16*ar_1 + 6 2.06/1.37 2.06/1.37 2.06/1.37 2.06/1.37 Time: 0.140 sec (SMT: 0.124 sec) 2.06/1.37 2.06/1.37 2.06/1.37 ---------------------------------------- 2.06/1.37 2.06/1.37 (2) 2.06/1.37 BOUNDS(1, n^1) 2.26/1.39 EOF