2.36/1.67	WORST_CASE(?, O(1))
2.36/1.68	proof of /export/starexec/sandbox/output/output_files/bench.koat
2.36/1.68	# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty
2.36/1.68	
2.36/1.68	
2.36/1.68	The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, 1).
2.36/1.68	
2.36/1.68	(0) CpxIntTrs
2.36/1.68	(1) Koat Proof [FINISHED, 481 ms]
2.36/1.68	(2) BOUNDS(1, 1)
2.36/1.68	
2.36/1.68	
2.36/1.68	----------------------------------------
2.36/1.68	
2.36/1.68	(0)
2.36/1.68	Obligation:
2.36/1.68	Complexity Int TRS consisting of the following rules:
2.36/1.68	eval_foo_start(v_.0, v_x) -> Com_1(eval_foo_bb0_in(v_.0, v_x)) :|: TRUE
2.36/1.68	eval_foo_bb0_in(v_.0, v_x) -> Com_1(eval_foo_bb1_in(v_x, v_x)) :|: TRUE
2.36/1.68	eval_foo_bb1_in(v_.0, v_x) -> Com_1(eval_foo_bb2_in(v_.0, v_x)) :|: v_.0 >= 0
2.36/1.68	eval_foo_bb1_in(v_.0, v_x) -> Com_1(eval_foo_bb3_in(v_.0, v_x)) :|: v_.0 < 0
2.36/1.68	eval_foo_bb2_in(v_.0, v_x) -> Com_1(eval_foo_bb1_in(-(2) * v_.0 + 10, v_x)) :|: TRUE
2.36/1.68	eval_foo_bb3_in(v_.0, v_x) -> Com_1(eval_foo_stop(v_.0, v_x)) :|: TRUE
2.36/1.68	
2.36/1.68	The start-symbols are:[eval_foo_start_2]
2.36/1.68	
2.36/1.68	
2.36/1.68	----------------------------------------
2.36/1.68	
2.36/1.68	(1) Koat Proof (FINISHED)
2.36/1.68	YES(?, 42)
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Initial complexity problem:
2.36/1.68	
2.36/1.68	1:	T:
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1))
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1))
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 0)    koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Repeatedly propagating knowledge in problem 1 produces the following problem:
2.36/1.68	
2.36/1.68	2:	T:
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1))
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 0)    koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	A polynomial rank function with
2.36/1.68	
2.36/1.68		Pol(evalfoostart) = 2
2.36/1.68	
2.36/1.68		Pol(evalfoobb0in) = 2
2.36/1.68	
2.36/1.68		Pol(evalfoobb1in) = 2
2.36/1.68	
2.36/1.68		Pol(evalfoobb2in) = 2
2.36/1.68	
2.36/1.68		Pol(evalfoobb3in) = 1
2.36/1.68	
2.36/1.68		Pol(evalfoostop) = 0
2.36/1.68	
2.36/1.68		Pol(koat_start) = 2
2.36/1.68	
2.36/1.68	orients all transitions weakly and the transitions
2.36/1.68	
2.36/1.68		evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1))
2.36/1.68	
2.36/1.68		evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ]
2.36/1.68	
2.36/1.68	strictly and produces the following problem:
2.36/1.68	
2.36/1.68	3:	T:
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 0)    koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Applied AI with 'oct' on problem 3 to obtain the following invariants:
2.36/1.68	
2.36/1.68	  For symbol evalfoobb2in: X_1 >= 0
2.36/1.68	
2.36/1.68	  For symbol evalfoobb3in: -X_1 - 1 >= 0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	This yielded the following problem:
2.36/1.68	
2.36/1.68	4:	T:
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 0)    koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1))
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ] with all transitions in problem 4, the following new transition is obtained:
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	5:	T:
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1))
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Testing for reachability in the complexity graph removes the following transition from problem 5:
2.36/1.68	
2.36/1.68		evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1))
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	6:	T:
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	By chaining the transition evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 0 ] with all transitions in problem 6, the following new transition is obtained:
2.36/1.68	
2.36/1.68		evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	7:	T:
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 1)    evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Testing for reachability in the complexity graph removes the following transition from problem 7:
2.36/1.68	
2.36/1.68		evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	8:	T:
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	By chaining the transition evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 + 1 ] with all transitions in problem 8, the following new transition is obtained:
2.36/1.68	
2.36/1.68		evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	9:	T:
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 1)    evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Testing for reachability in the complexity graph removes the following transition from problem 9:
2.36/1.68	
2.36/1.68		evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	10:	T:
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ] with all transitions in problem 10, the following new transition is obtained:
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	11:	T:
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 2)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 1)    evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Testing for reachability in the complexity graph removes the following transition from problem 11:
2.36/1.68	
2.36/1.68		evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1))
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	12:	T:
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 2)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) [ 0 <= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) [ 0 <= 0 ] with all transitions in problem 12, the following new transitions are obtained:
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 + 1 /\ -ar_1 - 1 >= 0 ]
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	13:	T:
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 4)    koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 + 1 /\ -ar_1 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 4)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 ] with all transitions in problem 13, the following new transitions are obtained:
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ 0 >= -2*ar_1 + 11 /\ 2*ar_1 - 11 >= 0 ]
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	14:	T:
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 6)    koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ 0 >= -2*ar_1 + 11 /\ 2*ar_1 - 11 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 6)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 4)    koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 + 1 /\ -ar_1 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 ] with all transitions in problem 14, the following new transitions are obtained:
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoostop(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 0 >= 4*ar_1 - 9 /\ -4*ar_1 + 9 >= 0 ]
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 4*ar_1 - 10 >= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	15:	T:
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 8)    koat_start(ar_0, ar_1) -> Com_1(evalfoostop(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 0 >= 4*ar_1 - 9 /\ -4*ar_1 + 9 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 8)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 4*ar_1 - 10 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 6)    koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ 0 >= -2*ar_1 + 11 /\ 2*ar_1 - 11 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 4)    koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 + 1 /\ -ar_1 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)    evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 4*ar_1 - 10 >= 0 ] with all transitions in problem 15, the following new transitions are obtained:
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 4*ar_1 - 10 >= 0 /\ 0 >= -8*ar_1 + 31 /\ 8*ar_1 - 31 >= 0 ]
2.36/1.68	
2.36/1.68		koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(16*ar_1 - 50, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 4*ar_1 - 10 >= 0 /\ -8*ar_1 + 30 >= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	16:	T:
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 10)    koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 4*ar_1 - 10 >= 0 /\ 0 >= -8*ar_1 + 31 /\ 8*ar_1 - 31 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 10)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(16*ar_1 - 50, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 4*ar_1 - 10 >= 0 /\ -8*ar_1 + 30 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 8)     koat_start(ar_0, ar_1) -> Com_1(evalfoostop(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 0 >= 4*ar_1 - 9 /\ -4*ar_1 + 9 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 6)     koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ 0 >= -2*ar_1 + 11 /\ 2*ar_1 - 11 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 4)     koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 + 1 /\ -ar_1 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 2)     evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: ?, Cost: 2)     evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Testing for reachability in the complexity graph removes the following transition from problem 16:
2.36/1.68	
2.36/1.68		evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 0 ]
2.36/1.68	
2.36/1.68	We thus obtain the following problem:
2.36/1.68	
2.36/1.68	17:	T:
2.36/1.68	
2.36/1.68			(Comp: 2, Cost: 2)     evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 + 1 /\ -ar_0 - 1 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 10)    koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(16*ar_1 - 50, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 4*ar_1 - 10 >= 0 /\ -8*ar_1 + 30 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 10)    koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 4*ar_1 - 10 >= 0 /\ 0 >= -8*ar_1 + 31 /\ 8*ar_1 - 31 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 8)     koat_start(ar_0, ar_1) -> Com_1(evalfoostop(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ -2*ar_1 + 10 >= 0 /\ 0 >= 4*ar_1 - 9 /\ -4*ar_1 + 9 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 6)     koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 0 /\ 0 >= -2*ar_1 + 11 /\ 2*ar_1 - 11 >= 0 ]
2.36/1.68	
2.36/1.68			(Comp: 1, Cost: 4)     koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 + 1 /\ -ar_1 - 1 >= 0 ]
2.36/1.68	
2.36/1.68		start location:	koat_start
2.36/1.68	
2.36/1.68		leaf cost:	0
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Complexity upper bound 42
2.36/1.68	
2.36/1.68	
2.36/1.68	
2.36/1.68	Time: 0.462 sec (SMT: 0.425 sec)
2.36/1.68	
2.36/1.68	
2.36/1.68	----------------------------------------
2.36/1.68	
2.36/1.68	(2)
2.36/1.68	BOUNDS(1, 1)
2.47/1.70	EOF