2.09/1.71 WORST_CASE(?, O(1)) 2.62/1.72 proof of /export/starexec/sandbox/output/output_files/bench.koat 2.62/1.72 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 2.62/1.72 2.62/1.72 2.62/1.72 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, 1). 2.62/1.72 2.62/1.72 (0) CpxIntTrs 2.62/1.72 (1) Koat Proof [FINISHED, 481 ms] 2.62/1.72 (2) BOUNDS(1, 1) 2.62/1.72 2.62/1.72 2.62/1.72 ---------------------------------------- 2.62/1.72 2.62/1.72 (0) 2.62/1.72 Obligation: 2.62/1.72 Complexity Int TRS consisting of the following rules: 2.62/1.72 eval_foo_start(v_.0, v_x) -> Com_1(eval_foo_bb0_in(v_.0, v_x)) :|: TRUE 2.62/1.72 eval_foo_bb0_in(v_.0, v_x) -> Com_1(eval_foo_bb1_in(v_x, v_x)) :|: TRUE 2.62/1.72 eval_foo_bb1_in(v_.0, v_x) -> Com_1(eval_foo_bb2_in(v_.0, v_x)) :|: v_.0 > 0 2.62/1.72 eval_foo_bb1_in(v_.0, v_x) -> Com_1(eval_foo_bb3_in(v_.0, v_x)) :|: v_.0 <= 0 2.62/1.72 eval_foo_bb2_in(v_.0, v_x) -> Com_1(eval_foo_bb1_in(-(2) * v_.0 + 10, v_x)) :|: TRUE 2.62/1.72 eval_foo_bb3_in(v_.0, v_x) -> Com_1(eval_foo_stop(v_.0, v_x)) :|: TRUE 2.62/1.72 2.62/1.72 The start-symbols are:[eval_foo_start_2] 2.62/1.72 2.62/1.72 2.62/1.72 ---------------------------------------- 2.62/1.72 2.62/1.72 (1) Koat Proof (FINISHED) 2.62/1.72 YES(?, 42) 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Initial complexity problem: 2.62/1.72 2.62/1.72 1: T: 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 1 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Repeatedly propagating knowledge in problem 1 produces the following problem: 2.62/1.72 2.62/1.72 2: T: 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 1 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 A polynomial rank function with 2.62/1.72 2.62/1.72 Pol(evalfoostart) = 2 2.62/1.72 2.62/1.72 Pol(evalfoobb0in) = 2 2.62/1.72 2.62/1.72 Pol(evalfoobb1in) = 2 2.62/1.72 2.62/1.72 Pol(evalfoobb2in) = 2 2.62/1.72 2.62/1.72 Pol(evalfoobb3in) = 1 2.62/1.72 2.62/1.72 Pol(evalfoostop) = 0 2.62/1.72 2.62/1.72 Pol(koat_start) = 2 2.62/1.72 2.62/1.72 orients all transitions weakly and the transitions 2.62/1.72 2.62/1.72 evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) 2.62/1.72 2.62/1.72 evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] 2.62/1.72 2.62/1.72 strictly and produces the following problem: 2.62/1.72 2.62/1.72 3: T: 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 1 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Applied AI with 'oct' on problem 3 to obtain the following invariants: 2.62/1.72 2.62/1.72 For symbol evalfoobb2in: X_1 - 1 >= 0 2.62/1.72 2.62/1.72 For symbol evalfoobb3in: -X_1 >= 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 This yielded the following problem: 2.62/1.72 2.62/1.72 4: T: 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 1 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoostart(ar_0, ar_1)) [ 0 <= 0 ] with all transitions in problem 4, the following new transition is obtained: 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 5: T: 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 1 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Testing for reachability in the complexity graph removes the following transition from problem 5: 2.62/1.72 2.62/1.72 evalfoostart(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 6: T: 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 1 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 By chaining the transition evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb2in(ar_0, ar_1)) [ ar_0 >= 1 ] with all transitions in problem 6, the following new transition is obtained: 2.62/1.72 2.62/1.72 evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 7: T: 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 1) evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Testing for reachability in the complexity graph removes the following transition from problem 7: 2.62/1.72 2.62/1.72 evalfoobb2in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 8: T: 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 By chaining the transition evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb3in(ar_0, ar_1)) [ 0 >= ar_0 ] with all transitions in problem 8, the following new transition is obtained: 2.62/1.72 2.62/1.72 evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 9: T: 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 1) evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Testing for reachability in the complexity graph removes the following transition from problem 9: 2.62/1.72 2.62/1.72 evalfoobb3in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 10: T: 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb0in(ar_0, ar_1)) [ 0 <= 0 ] with all transitions in problem 10, the following new transition is obtained: 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 11: T: 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 2) koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 1) evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Testing for reachability in the complexity graph removes the following transition from problem 11: 2.62/1.72 2.62/1.72 evalfoobb0in(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 12: T: 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 2) koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) [ 0 <= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(ar_1, ar_1)) [ 0 <= 0 ] with all transitions in problem 12, the following new transitions are obtained: 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 /\ -ar_1 >= 0 ] 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 13: T: 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 4) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 /\ -ar_1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 4) koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 ] with all transitions in problem 13, the following new transitions are obtained: 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ 0 >= -2*ar_1 + 10 /\ 2*ar_1 - 10 >= 0 ] 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 14: T: 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 6) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ 0 >= -2*ar_1 + 10 /\ 2*ar_1 - 10 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 6) koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 4) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 /\ -ar_1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 ] with all transitions in problem 14, the following new transitions are obtained: 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoostop(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 0 >= 4*ar_1 - 10 /\ -4*ar_1 + 10 >= 0 ] 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 4*ar_1 - 10 >= 1 /\ 4*ar_1 - 11 >= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 15: T: 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 8) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 0 >= 4*ar_1 - 10 /\ -4*ar_1 + 10 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 8) koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 4*ar_1 - 10 >= 1 /\ 4*ar_1 - 11 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 6) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ 0 >= -2*ar_1 + 10 /\ 2*ar_1 - 10 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 4) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 /\ -ar_1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 By chaining the transition koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 4*ar_1 - 10 >= 1 /\ 4*ar_1 - 11 >= 0 ] with all transitions in problem 15, the following new transitions are obtained: 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 4*ar_1 - 10 >= 1 /\ 4*ar_1 - 11 >= 0 /\ 0 >= -8*ar_1 + 30 /\ 8*ar_1 - 30 >= 0 ] 2.62/1.72 2.62/1.72 koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(16*ar_1 - 50, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 4*ar_1 - 10 >= 1 /\ 4*ar_1 - 11 >= 0 /\ -8*ar_1 + 30 >= 1 /\ -8*ar_1 + 29 >= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 16: T: 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 10) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 4*ar_1 - 10 >= 1 /\ 4*ar_1 - 11 >= 0 /\ 0 >= -8*ar_1 + 30 /\ 8*ar_1 - 30 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 10) koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(16*ar_1 - 50, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 4*ar_1 - 10 >= 1 /\ 4*ar_1 - 11 >= 0 /\ -8*ar_1 + 30 >= 1 /\ -8*ar_1 + 29 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 8) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 0 >= 4*ar_1 - 10 /\ -4*ar_1 + 10 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 6) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ 0 >= -2*ar_1 + 10 /\ 2*ar_1 - 10 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 4) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 /\ -ar_1 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: ?, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Testing for reachability in the complexity graph removes the following transition from problem 16: 2.62/1.72 2.62/1.72 evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoobb1in(-2*ar_0 + 10, ar_1)) [ ar_0 >= 1 /\ ar_0 - 1 >= 0 ] 2.62/1.72 2.62/1.72 We thus obtain the following problem: 2.62/1.72 2.62/1.72 17: T: 2.62/1.72 2.62/1.72 (Comp: 2, Cost: 2) evalfoobb1in(ar_0, ar_1) -> Com_1(evalfoostop(ar_0, ar_1)) [ 0 >= ar_0 /\ -ar_0 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 10) koat_start(ar_0, ar_1) -> Com_1(evalfoobb1in(16*ar_1 - 50, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 4*ar_1 - 10 >= 1 /\ 4*ar_1 - 11 >= 0 /\ -8*ar_1 + 30 >= 1 /\ -8*ar_1 + 29 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 10) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-8*ar_1 + 30, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 4*ar_1 - 10 >= 1 /\ 4*ar_1 - 11 >= 0 /\ 0 >= -8*ar_1 + 30 /\ 8*ar_1 - 30 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 8) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(4*ar_1 - 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ -2*ar_1 + 10 >= 1 /\ -2*ar_1 + 9 >= 0 /\ 0 >= 4*ar_1 - 10 /\ -4*ar_1 + 10 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 6) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(-2*ar_1 + 10, ar_1)) [ 0 <= 0 /\ ar_1 >= 1 /\ ar_1 - 1 >= 0 /\ 0 >= -2*ar_1 + 10 /\ 2*ar_1 - 10 >= 0 ] 2.62/1.72 2.62/1.72 (Comp: 1, Cost: 4) koat_start(ar_0, ar_1) -> Com_1(evalfoostop(ar_1, ar_1)) [ 0 <= 0 /\ 0 >= ar_1 /\ -ar_1 >= 0 ] 2.62/1.72 2.62/1.72 start location: koat_start 2.62/1.72 2.62/1.72 leaf cost: 0 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Complexity upper bound 42 2.62/1.72 2.62/1.72 2.62/1.72 2.62/1.72 Time: 0.471 sec (SMT: 0.440 sec) 2.62/1.72 2.62/1.72 2.62/1.72 ---------------------------------------- 2.62/1.72 2.62/1.72 (2) 2.62/1.72 BOUNDS(1, 1) 2.62/1.74 EOF