3.25/1.58 WORST_CASE(?, O(1)) 3.25/1.59 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 3.25/1.59 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.25/1.59 3.25/1.59 3.25/1.59 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, 1). 3.25/1.59 3.25/1.59 (0) CpxIntTrs 3.25/1.59 (1) Koat Proof [FINISHED, 7 ms] 3.25/1.59 (2) BOUNDS(1, 1) 3.25/1.59 3.25/1.59 3.25/1.59 ---------------------------------------- 3.25/1.59 3.25/1.59 (0) 3.25/1.59 Obligation: 3.25/1.59 Complexity Int TRS consisting of the following rules: 3.25/1.59 start(A, B, C, D) -> Com_1(lbl41(E, B, C, D)) :|: A >= B && A <= B && C >= D && C <= D 3.25/1.59 lbl41(A, B, C, D) -> Com_1(stop(A, B, A, D)) :|: C >= D && C <= D 3.25/1.59 start0(A, B, C, D) -> Com_1(start(B, B, D, D)) :|: TRUE 3.25/1.59 3.25/1.59 The start-symbols are:[start0_4] 3.25/1.59 3.25/1.59 3.25/1.59 ---------------------------------------- 3.25/1.59 3.25/1.59 (1) Koat Proof (FINISHED) 3.25/1.59 YES(?, 3) 3.25/1.59 3.25/1.59 3.25/1.59 3.25/1.59 Initial complexity problem: 3.25/1.59 3.25/1.59 1: T: 3.25/1.59 3.25/1.59 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl41(e, ar_1, ar_2, ar_3)) [ ar_0 = ar_1 /\ ar_2 = ar_3 ] 3.25/1.59 3.25/1.59 (Comp: ?, Cost: 1) lbl41(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_0, ar_3)) [ ar_2 = ar_3 ] 3.25/1.59 3.25/1.59 (Comp: ?, Cost: 1) start0(ar_0, ar_1, ar_2, ar_3) -> Com_1(start(ar_1, ar_1, ar_3, ar_3)) 3.25/1.59 3.25/1.59 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3) -> Com_1(start0(ar_0, ar_1, ar_2, ar_3)) [ 0 <= 0 ] 3.25/1.59 3.25/1.59 start location: koat_start 3.25/1.59 3.25/1.59 leaf cost: 0 3.25/1.59 3.25/1.59 3.25/1.59 3.25/1.59 Repeatedly propagating knowledge in problem 1 produces the following problem: 3.25/1.59 3.25/1.59 2: T: 3.25/1.59 3.25/1.59 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl41(e, ar_1, ar_2, ar_3)) [ ar_0 = ar_1 /\ ar_2 = ar_3 ] 3.25/1.59 3.25/1.59 (Comp: 1, Cost: 1) lbl41(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_0, ar_3)) [ ar_2 = ar_3 ] 3.25/1.59 3.25/1.59 (Comp: 1, Cost: 1) start0(ar_0, ar_1, ar_2, ar_3) -> Com_1(start(ar_1, ar_1, ar_3, ar_3)) 3.25/1.59 3.25/1.59 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3) -> Com_1(start0(ar_0, ar_1, ar_2, ar_3)) [ 0 <= 0 ] 3.25/1.59 3.25/1.59 start location: koat_start 3.25/1.59 3.25/1.59 leaf cost: 0 3.25/1.59 3.25/1.59 3.25/1.59 3.25/1.59 Complexity upper bound 3 3.25/1.59 3.25/1.59 3.25/1.59 3.25/1.59 Time: 0.021 sec (SMT: 0.020 sec) 3.25/1.59 3.25/1.59 3.25/1.59 ---------------------------------------- 3.25/1.59 3.25/1.59 (2) 3.25/1.59 BOUNDS(1, 1) 3.25/1.62 EOF