4.60/2.12 WORST_CASE(Omega(n^1), O(n^1)) 4.60/2.14 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 4.60/2.14 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.60/2.14 4.60/2.14 4.60/2.14 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^1, n^1). 4.60/2.14 4.60/2.14 (0) CpxIntTrs 4.60/2.14 (1) Koat Proof [FINISHED, 211 ms] 4.60/2.14 (2) BOUNDS(1, n^1) 4.60/2.14 (3) Loat Proof [FINISHED, 411 ms] 4.60/2.14 (4) BOUNDS(n^1, INF) 4.60/2.14 4.60/2.14 4.60/2.14 ---------------------------------------- 4.60/2.14 4.60/2.14 (0) 4.60/2.14 Obligation: 4.60/2.14 Complexity Int TRS consisting of the following rules: 4.60/2.14 start(A, B, C, D) -> Com_1(stop(A, B, C, D)) :|: 0 >= A + 1 && B >= C && B <= C && D >= A && D <= A 4.60/2.14 start(A, B, C, D) -> Com_1(stop(A, B, C, D)) :|: 0 >= C + 1 && B >= C && B <= C && D >= A && D <= A 4.60/2.14 start(A, B, C, D) -> Com_1(stop(A, B, C, D)) :|: A >= 0 && A + 2 >= C && C >= 0 && C + 2 >= A && B >= C && B <= C && D >= A && D <= A 4.60/2.14 start(A, B, C, D) -> Com_1(lbl81(A, B, C, 1 + D)) :|: A >= 0 && C >= A + 3 && B >= C && B <= C && D >= A && D <= A 4.60/2.14 start(A, B, C, D) -> Com_1(lbl91(A, 1 + B, C, D)) :|: A >= C + 3 && C >= 0 && B >= C && B <= C && D >= A && D <= A 4.60/2.15 lbl81(A, B, C, D) -> Com_1(stop(A, B, C, D)) :|: C >= 3 + A && A >= 0 && D + 2 >= C && D + 2 <= C && B >= C && B <= C 4.60/2.15 lbl81(A, B, C, D) -> Com_1(lbl81(A, B, C, 1 + D)) :|: C >= D + 3 && D >= A + 1 && A >= 0 && C >= D + 2 && B >= C && B <= C 4.60/2.15 lbl81(A, B, C, D) -> Com_1(lbl91(A, 1 + B, C, D)) :|: D >= C + 3 && D >= A + 1 && A >= 0 && C >= D + 2 && B >= C && B <= C 4.60/2.15 lbl91(A, B, C, D) -> Com_1(stop(A, B, C, D)) :|: A >= 3 + C && C >= 0 && B + 2 >= A && B + 2 <= A && D >= A && D <= A 4.60/2.15 lbl91(A, B, C, D) -> Com_1(lbl81(A, B, C, 1 + D)) :|: B >= A + 3 && A >= B + 2 && B >= C + 1 && C >= 0 && D >= A && D <= A 4.60/2.15 lbl91(A, B, C, D) -> Com_1(lbl91(A, 1 + B, C, D)) :|: A >= B + 3 && A >= B + 2 && B >= C + 1 && C >= 0 && D >= A && D <= A 4.60/2.15 start0(A, B, C, D) -> Com_1(start(A, C, C, A)) :|: TRUE 4.60/2.15 4.60/2.15 The start-symbols are:[start0_4] 4.60/2.15 4.60/2.15 4.60/2.15 ---------------------------------------- 4.60/2.15 4.60/2.15 (1) Koat Proof (FINISHED) 4.60/2.15 YES(?, 2*ar_0 + 2*ar_2 + 8) 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Initial complexity problem: 4.60/2.15 4.60/2.15 1: T: 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_0 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_2 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= 0 /\ ar_0 + 2 >= ar_2 /\ ar_2 >= 0 /\ ar_2 + 2 >= ar_0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_0 >= 0 /\ ar_2 >= ar_0 + 3 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_2 >= ar_0 + 3 /\ ar_0 >= 0 /\ ar_3 + 2 = ar_2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_2 >= ar_3 + 3 /\ ar_3 >= ar_0 + 1 /\ ar_0 >= 0 /\ ar_2 >= ar_3 + 2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_3 >= ar_2 + 3 /\ ar_3 >= ar_0 + 1 /\ ar_0 >= 0 /\ ar_2 >= ar_3 + 2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 + 2 = ar_0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_1 >= ar_0 + 3 /\ ar_0 >= ar_1 + 2 /\ ar_1 >= ar_2 + 1 /\ ar_2 >= 0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_1 + 3 /\ ar_0 >= ar_1 + 2 /\ ar_1 >= ar_2 + 1 /\ ar_2 >= 0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start0(ar_0, ar_1, ar_2, ar_3) -> Com_1(start(ar_0, ar_2, ar_2, ar_0)) 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3) -> Com_1(start0(ar_0, ar_1, ar_2, ar_3)) [ 0 <= 0 ] 4.60/2.15 4.60/2.15 start location: koat_start 4.60/2.15 4.60/2.15 leaf cost: 0 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Testing for reachability in the complexity graph removes the following transitions from problem 1: 4.60/2.15 4.60/2.15 lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_3 >= ar_2 + 3 /\ ar_3 >= ar_0 + 1 /\ ar_0 >= 0 /\ ar_2 >= ar_3 + 2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_1 >= ar_0 + 3 /\ ar_0 >= ar_1 + 2 /\ ar_1 >= ar_2 + 1 /\ ar_2 >= 0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 We thus obtain the following problem: 4.60/2.15 4.60/2.15 2: T: 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_1 + 3 /\ ar_0 >= ar_1 + 2 /\ ar_1 >= ar_2 + 1 /\ ar_2 >= 0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 + 2 = ar_0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_2 >= ar_3 + 3 /\ ar_3 >= ar_0 + 1 /\ ar_0 >= 0 /\ ar_2 >= ar_3 + 2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_2 >= ar_0 + 3 /\ ar_0 >= 0 /\ ar_3 + 2 = ar_2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_0 >= 0 /\ ar_2 >= ar_0 + 3 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= 0 /\ ar_0 + 2 >= ar_2 /\ ar_2 >= 0 /\ ar_2 + 2 >= ar_0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_2 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_0 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) start0(ar_0, ar_1, ar_2, ar_3) -> Com_1(start(ar_0, ar_2, ar_2, ar_0)) 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3) -> Com_1(start0(ar_0, ar_1, ar_2, ar_3)) [ 0 <= 0 ] 4.60/2.15 4.60/2.15 start location: koat_start 4.60/2.15 4.60/2.15 leaf cost: 0 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Repeatedly propagating knowledge in problem 2 produces the following problem: 4.60/2.15 4.60/2.15 3: T: 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_1 + 3 /\ ar_0 >= ar_1 + 2 /\ ar_1 >= ar_2 + 1 /\ ar_2 >= 0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 + 2 = ar_0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_2 >= ar_3 + 3 /\ ar_3 >= ar_0 + 1 /\ ar_0 >= 0 /\ ar_2 >= ar_3 + 2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_2 >= ar_0 + 3 /\ ar_0 >= 0 /\ ar_3 + 2 = ar_2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_0 >= 0 /\ ar_2 >= ar_0 + 3 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= 0 /\ ar_0 + 2 >= ar_2 /\ ar_2 >= 0 /\ ar_2 + 2 >= ar_0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_2 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_0 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start0(ar_0, ar_1, ar_2, ar_3) -> Com_1(start(ar_0, ar_2, ar_2, ar_0)) 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3) -> Com_1(start0(ar_0, ar_1, ar_2, ar_3)) [ 0 <= 0 ] 4.60/2.15 4.60/2.15 start location: koat_start 4.60/2.15 4.60/2.15 leaf cost: 0 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 A polynomial rank function with 4.60/2.15 4.60/2.15 Pol(lbl91) = 1 4.60/2.15 4.60/2.15 Pol(stop) = 0 4.60/2.15 4.60/2.15 Pol(lbl81) = 1 4.60/2.15 4.60/2.15 Pol(start) = 1 4.60/2.15 4.60/2.15 Pol(start0) = 1 4.60/2.15 4.60/2.15 Pol(koat_start) = 1 4.60/2.15 4.60/2.15 orients all transitions weakly and the transitions 4.60/2.15 4.60/2.15 lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 + 2 = ar_0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_2 >= ar_0 + 3 /\ ar_0 >= 0 /\ ar_3 + 2 = ar_2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 strictly and produces the following problem: 4.60/2.15 4.60/2.15 4: T: 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_1 + 3 /\ ar_0 >= ar_1 + 2 /\ ar_1 >= ar_2 + 1 /\ ar_2 >= 0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 + 2 = ar_0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ?, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_2 >= ar_3 + 3 /\ ar_3 >= ar_0 + 1 /\ ar_0 >= 0 /\ ar_2 >= ar_3 + 2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_2 >= ar_0 + 3 /\ ar_0 >= 0 /\ ar_3 + 2 = ar_2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_0 >= 0 /\ ar_2 >= ar_0 + 3 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= 0 /\ ar_0 + 2 >= ar_2 /\ ar_2 >= 0 /\ ar_2 + 2 >= ar_0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_2 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_0 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start0(ar_0, ar_1, ar_2, ar_3) -> Com_1(start(ar_0, ar_2, ar_2, ar_0)) 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3) -> Com_1(start0(ar_0, ar_1, ar_2, ar_3)) [ 0 <= 0 ] 4.60/2.15 4.60/2.15 start location: koat_start 4.60/2.15 4.60/2.15 leaf cost: 0 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 A polynomial rank function with 4.60/2.15 4.60/2.15 Pol(lbl91) = 2*V_1 - V_2 + 2*V_3 - V_4 4.60/2.15 4.60/2.15 Pol(stop) = 2*V_1 - V_2 + 2*V_3 - V_4 4.60/2.15 4.60/2.15 Pol(lbl81) = 2*V_1 + V_2 - V_4 4.60/2.15 4.60/2.15 Pol(start) = V_1 + V_3 4.60/2.15 4.60/2.15 Pol(start0) = V_1 + V_3 4.60/2.15 4.60/2.15 Pol(koat_start) = V_1 + V_3 4.60/2.15 4.60/2.15 orients all transitions weakly and the transitions 4.60/2.15 4.60/2.15 lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_1 + 3 /\ ar_0 >= ar_1 + 2 /\ ar_1 >= ar_2 + 1 /\ ar_2 >= 0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_2 >= ar_3 + 3 /\ ar_3 >= ar_0 + 1 /\ ar_0 >= 0 /\ ar_2 >= ar_3 + 2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 strictly and produces the following problem: 4.60/2.15 4.60/2.15 5: T: 4.60/2.15 4.60/2.15 (Comp: ar_0 + ar_2, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_1 + 3 /\ ar_0 >= ar_1 + 2 /\ ar_1 >= ar_2 + 1 /\ ar_2 >= 0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) lbl91(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 + 2 = ar_0 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: ar_0 + ar_2, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_2 >= ar_3 + 3 /\ ar_3 >= ar_0 + 1 /\ ar_0 >= 0 /\ ar_2 >= ar_3 + 2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) lbl81(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_2 >= ar_0 + 3 /\ ar_0 >= 0 /\ ar_3 + 2 = ar_2 /\ ar_1 = ar_2 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl91(ar_0, ar_1 + 1, ar_2, ar_3)) [ ar_0 >= ar_2 + 3 /\ ar_2 >= 0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(lbl81(ar_0, ar_1, ar_2, ar_3 + 1)) [ ar_0 >= 0 /\ ar_2 >= ar_0 + 3 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ ar_0 >= 0 /\ ar_0 + 2 >= ar_2 /\ ar_2 >= 0 /\ ar_2 + 2 >= ar_0 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_2 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start(ar_0, ar_1, ar_2, ar_3) -> Com_1(stop(ar_0, ar_1, ar_2, ar_3)) [ 0 >= ar_0 + 1 /\ ar_1 = ar_2 /\ ar_3 = ar_0 ] 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 1) start0(ar_0, ar_1, ar_2, ar_3) -> Com_1(start(ar_0, ar_2, ar_2, ar_0)) 4.60/2.15 4.60/2.15 (Comp: 1, Cost: 0) koat_start(ar_0, ar_1, ar_2, ar_3) -> Com_1(start0(ar_0, ar_1, ar_2, ar_3)) [ 0 <= 0 ] 4.60/2.15 4.60/2.15 start location: koat_start 4.60/2.15 4.60/2.15 leaf cost: 0 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Complexity upper bound 2*ar_0 + 2*ar_2 + 8 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Time: 0.199 sec (SMT: 0.179 sec) 4.60/2.15 4.60/2.15 4.60/2.15 ---------------------------------------- 4.60/2.15 4.60/2.15 (2) 4.60/2.15 BOUNDS(1, n^1) 4.60/2.15 4.60/2.15 ---------------------------------------- 4.60/2.15 4.60/2.15 (3) Loat Proof (FINISHED) 4.60/2.15 4.60/2.15 4.60/2.15 ### Pre-processing the ITS problem ### 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Initial linear ITS problem 4.60/2.15 4.60/2.15 Start location: start0 4.60/2.15 4.60/2.15 0: start -> stop : [ 0>=1+A && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 1: start -> stop : [ 0>=1+C && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 2: start -> stop : [ A>=0 && 2+A>=C && C>=0 && 2+C>=A && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 3: start -> lbl81 : D'=1+D, [ A>=0 && C>=3+A && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 4: start -> lbl91 : B'=1+B, [ A>=3+C && C>=0 && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 5: lbl81 -> stop : [ C>=3+A && A>=0 && 2+D==C && B==C ], cost: 1 4.60/2.15 4.60/2.15 6: lbl81 -> lbl81 : D'=1+D, [ C>=3+D && D>=1+A && A>=0 && C>=2+D && B==C ], cost: 1 4.60/2.15 4.60/2.15 7: lbl81 -> lbl91 : B'=1+B, [ D>=3+C && D>=1+A && A>=0 && C>=2+D && B==C ], cost: 1 4.60/2.15 4.60/2.15 8: lbl91 -> stop : [ A>=3+C && C>=0 && 2+B==A && D==A ], cost: 1 4.60/2.15 4.60/2.15 9: lbl91 -> lbl81 : D'=1+D, [ B>=3+A && A>=2+B && B>=1+C && C>=0 && D==A ], cost: 1 4.60/2.15 4.60/2.15 10: lbl91 -> lbl91 : B'=1+B, [ A>=3+B && A>=2+B && B>=1+C && C>=0 && D==A ], cost: 1 4.60/2.15 4.60/2.15 11: start0 -> start : B'=C, D'=A, [], cost: 1 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Removed unreachable and leaf rules: 4.60/2.15 4.60/2.15 Start location: start0 4.60/2.15 4.60/2.15 3: start -> lbl81 : D'=1+D, [ A>=0 && C>=3+A && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 4: start -> lbl91 : B'=1+B, [ A>=3+C && C>=0 && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 6: lbl81 -> lbl81 : D'=1+D, [ C>=3+D && D>=1+A && A>=0 && C>=2+D && B==C ], cost: 1 4.60/2.15 4.60/2.15 7: lbl81 -> lbl91 : B'=1+B, [ D>=3+C && D>=1+A && A>=0 && C>=2+D && B==C ], cost: 1 4.60/2.15 4.60/2.15 9: lbl91 -> lbl81 : D'=1+D, [ B>=3+A && A>=2+B && B>=1+C && C>=0 && D==A ], cost: 1 4.60/2.15 4.60/2.15 10: lbl91 -> lbl91 : B'=1+B, [ A>=3+B && A>=2+B && B>=1+C && C>=0 && D==A ], cost: 1 4.60/2.15 4.60/2.15 11: start0 -> start : B'=C, D'=A, [], cost: 1 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Removed rules with unsatisfiable guard: 4.60/2.15 4.60/2.15 Start location: start0 4.60/2.15 4.60/2.15 3: start -> lbl81 : D'=1+D, [ A>=0 && C>=3+A && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 4: start -> lbl91 : B'=1+B, [ A>=3+C && C>=0 && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 6: lbl81 -> lbl81 : D'=1+D, [ C>=3+D && D>=1+A && A>=0 && C>=2+D && B==C ], cost: 1 4.60/2.15 4.60/2.15 10: lbl91 -> lbl91 : B'=1+B, [ A>=3+B && A>=2+B && B>=1+C && C>=0 && D==A ], cost: 1 4.60/2.15 4.60/2.15 11: start0 -> start : B'=C, D'=A, [], cost: 1 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Simplified all rules, resulting in: 4.60/2.15 4.60/2.15 Start location: start0 4.60/2.15 4.60/2.15 3: start -> lbl81 : D'=1+D, [ A>=0 && C>=3+A && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 4: start -> lbl91 : B'=1+B, [ A>=3+C && C>=0 && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 6: lbl81 -> lbl81 : D'=1+D, [ C>=3+D && D>=1+A && A>=0 && B==C ], cost: 1 4.60/2.15 4.60/2.15 10: lbl91 -> lbl91 : B'=1+B, [ A>=3+B && B>=1+C && C>=0 && D==A ], cost: 1 4.60/2.15 4.60/2.15 11: start0 -> start : B'=C, D'=A, [], cost: 1 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 ### Simplification by acceleration and chaining ### 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Accelerating simple loops of location 1. 4.60/2.15 4.60/2.15 Accelerating the following rules: 4.60/2.15 4.60/2.15 6: lbl81 -> lbl81 : D'=1+D, [ C>=3+D && D>=1+A && A>=0 && B==C ], cost: 1 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Accelerated rule 6 with metering function -2+C-D, yielding the new rule 12. 4.60/2.15 4.60/2.15 Removing the simple loops: 6. 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Accelerating simple loops of location 2. 4.60/2.15 4.60/2.15 Accelerating the following rules: 4.60/2.15 4.60/2.15 10: lbl91 -> lbl91 : B'=1+B, [ A>=3+B && B>=1+C && C>=0 && D==A ], cost: 1 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Accelerated rule 10 with metering function -2+A-B, yielding the new rule 13. 4.60/2.15 4.60/2.15 Removing the simple loops: 10. 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Accelerated all simple loops using metering functions (where possible): 4.60/2.15 4.60/2.15 Start location: start0 4.60/2.15 4.60/2.15 3: start -> lbl81 : D'=1+D, [ A>=0 && C>=3+A && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 4: start -> lbl91 : B'=1+B, [ A>=3+C && C>=0 && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 12: lbl81 -> lbl81 : D'=-2+C, [ C>=3+D && D>=1+A && A>=0 && B==C ], cost: -2+C-D 4.60/2.15 4.60/2.15 13: lbl91 -> lbl91 : B'=-2+A, [ A>=3+B && B>=1+C && C>=0 && D==A ], cost: -2+A-B 4.60/2.15 4.60/2.15 11: start0 -> start : B'=C, D'=A, [], cost: 1 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Chained accelerated rules (with incoming rules): 4.60/2.15 4.60/2.15 Start location: start0 4.60/2.15 4.60/2.15 3: start -> lbl81 : D'=1+D, [ A>=0 && C>=3+A && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 4: start -> lbl91 : B'=1+B, [ A>=3+C && C>=0 && B==C && D==A ], cost: 1 4.60/2.15 4.60/2.15 14: start -> lbl81 : D'=-2+C, [ A>=0 && C>=3+A && B==C && D==A && C>=4+D ], cost: -2+C-D 4.60/2.15 4.60/2.15 15: start -> lbl91 : B'=-2+A, [ A>=3+C && C>=0 && B==C && D==A && A>=4+B ], cost: -2+A-B 4.60/2.15 4.60/2.15 11: start0 -> start : B'=C, D'=A, [], cost: 1 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Removed unreachable locations (and leaf rules with constant cost): 4.60/2.15 4.60/2.15 Start location: start0 4.60/2.15 4.60/2.15 14: start -> lbl81 : D'=-2+C, [ A>=0 && C>=3+A && B==C && D==A && C>=4+D ], cost: -2+C-D 4.60/2.15 4.60/2.15 15: start -> lbl91 : B'=-2+A, [ A>=3+C && C>=0 && B==C && D==A && A>=4+B ], cost: -2+A-B 4.60/2.15 4.60/2.15 11: start0 -> start : B'=C, D'=A, [], cost: 1 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Eliminated locations (on tree-shaped paths): 4.60/2.15 4.60/2.15 Start location: start0 4.60/2.15 4.60/2.15 16: start0 -> lbl81 : B'=C, D'=-2+C, [ A>=0 && C>=4+A ], cost: -1+C-A 4.60/2.15 4.60/2.15 17: start0 -> lbl91 : B'=-2+A, D'=A, [ C>=0 && A>=4+C ], cost: -1-C+A 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 ### Computing asymptotic complexity ### 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Fully simplified ITS problem 4.60/2.15 4.60/2.15 Start location: start0 4.60/2.15 4.60/2.15 16: start0 -> lbl81 : B'=C, D'=-2+C, [ A>=0 && C>=4+A ], cost: -1+C-A 4.60/2.15 4.60/2.15 17: start0 -> lbl91 : B'=-2+A, D'=A, [ C>=0 && A>=4+C ], cost: -1-C+A 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Computing asymptotic complexity for rule 16 4.60/2.15 4.60/2.15 Solved the limit problem by the following transformations: 4.60/2.15 4.60/2.15 Created initial limit problem: 4.60/2.15 4.60/2.15 -1+C-A (+), -3+C-A (+/+!), 1+A (+/+!) [not solved] 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 applying transformation rule (C) using substitution {A==0} 4.60/2.15 4.60/2.15 resulting limit problem: 4.60/2.15 4.60/2.15 1 (+/+!), -3+C (+/+!), -1+C (+) [not solved] 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 applying transformation rule (C) using substitution {C==4+A} 4.60/2.15 4.60/2.15 resulting limit problem: 4.60/2.15 4.60/2.15 1 (+/+!), 3+A (+), 1+A (+/+!) [not solved] 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 applying transformation rule (B), deleting 1 (+/+!) 4.60/2.15 4.60/2.15 resulting limit problem: 4.60/2.15 4.60/2.15 3+A (+), 1+A (+/+!) [not solved] 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 applying transformation rule (D), replacing 3+A (+) by A (+) 4.60/2.15 4.60/2.15 resulting limit problem: 4.60/2.15 4.60/2.15 A (+), 1+A (+/+!) [not solved] 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 applying transformation rule (D), replacing 1+A (+/+!) by A (+) 4.60/2.15 4.60/2.15 resulting limit problem: 4.60/2.15 4.60/2.15 A (+) [solved] 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Solution: 4.60/2.15 4.60/2.15 C / 4+n 4.60/2.15 4.60/2.15 A / 0 4.60/2.15 4.60/2.15 Resulting cost 3+n has complexity: Poly(n^1) 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Found new complexity Poly(n^1). 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 Obtained the following overall complexity (w.r.t. the length of the input n): 4.60/2.15 4.60/2.15 Complexity: Poly(n^1) 4.60/2.15 4.60/2.15 Cpx degree: 1 4.60/2.15 4.60/2.15 Solved cost: 3+n 4.60/2.15 4.60/2.15 Rule cost: -1+C-A 4.60/2.15 4.60/2.15 Rule guard: [ A>=0 && C>=4+A ] 4.60/2.15 4.60/2.15 4.60/2.15 4.60/2.15 WORST_CASE(Omega(n^1),?) 4.60/2.15 4.60/2.15 4.60/2.15 ---------------------------------------- 4.60/2.15 4.60/2.15 (4) 4.60/2.15 BOUNDS(n^1, INF) 4.76/2.17 EOF