3.26/1.64 WORST_CASE(?, O(1)) 3.26/1.65 proof of /export/starexec/sandbox/benchmark/theBenchmark.koat 3.26/1.65 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.26/1.65 3.26/1.65 3.26/1.65 The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(1, 1). 3.26/1.65 3.26/1.65 (0) CpxIntTrs 3.26/1.65 (1) Koat Proof [FINISHED, 11 ms] 3.26/1.65 (2) BOUNDS(1, 1) 3.26/1.65 3.26/1.65 3.26/1.65 ---------------------------------------- 3.26/1.65 3.26/1.65 (0) 3.26/1.65 Obligation: 3.26/1.65 Complexity Int TRS consisting of the following rules: 3.26/1.65 evalndloopstart(A) -> Com_1(evalndloopentryin(A)) :|: TRUE 3.26/1.65 evalndloopentryin(A) -> Com_1(evalndloopbbin(0)) :|: TRUE 3.26/1.65 evalndloopbbin(A) -> Com_1(evalndloopbbin(B)) :|: 2 + A >= B && B >= A + 1 && 9 >= B 3.26/1.65 evalndloopbbin(A) -> Com_1(evalndloopreturnin(A)) :|: B >= A + 3 3.26/1.65 evalndloopbbin(A) -> Com_1(evalndloopreturnin(A)) :|: A >= B 3.26/1.65 evalndloopbbin(A) -> Com_1(evalndloopreturnin(A)) :|: B >= 10 3.26/1.65 evalndloopreturnin(A) -> Com_1(evalndloopstop(A)) :|: TRUE 3.26/1.65 3.26/1.65 The start-symbols are:[evalndloopstart_1] 3.26/1.65 3.26/1.65 3.26/1.65 ---------------------------------------- 3.26/1.65 3.26/1.65 (1) Koat Proof (FINISHED) 3.26/1.65 YES(?, 19) 3.26/1.65 3.26/1.65 3.26/1.65 3.26/1.65 Initial complexity problem: 3.26/1.65 3.26/1.65 1: T: 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopstart(ar_0) -> Com_1(evalndloopentryin(ar_0)) 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopentryin(ar_0) -> Com_1(evalndloopbbin(0)) 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopbbin(b)) [ ar_0 + 2 >= b /\ b >= ar_0 + 1 /\ 9 >= b ] 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= ar_0 + 3 ] 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ ar_0 >= b ] 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= 10 ] 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopreturnin(ar_0) -> Com_1(evalndloopstop(ar_0)) 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 0) koat_start(ar_0) -> Com_1(evalndloopstart(ar_0)) [ 0 <= 0 ] 3.26/1.65 3.26/1.65 start location: koat_start 3.26/1.65 3.26/1.65 leaf cost: 0 3.26/1.65 3.26/1.65 3.26/1.65 3.26/1.65 Repeatedly propagating knowledge in problem 1 produces the following problem: 3.26/1.65 3.26/1.65 2: T: 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 1) evalndloopstart(ar_0) -> Com_1(evalndloopentryin(ar_0)) 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 1) evalndloopentryin(ar_0) -> Com_1(evalndloopbbin(0)) 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopbbin(b)) [ ar_0 + 2 >= b /\ b >= ar_0 + 1 /\ 9 >= b ] 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= ar_0 + 3 ] 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ ar_0 >= b ] 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= 10 ] 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopreturnin(ar_0) -> Com_1(evalndloopstop(ar_0)) 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 0) koat_start(ar_0) -> Com_1(evalndloopstart(ar_0)) [ 0 <= 0 ] 3.26/1.65 3.26/1.65 start location: koat_start 3.26/1.65 3.26/1.65 leaf cost: 0 3.26/1.65 3.26/1.65 3.26/1.65 3.26/1.65 A polynomial rank function with 3.26/1.65 3.26/1.65 Pol(evalndloopstart) = 2 3.26/1.65 3.26/1.65 Pol(evalndloopentryin) = 2 3.26/1.65 3.26/1.65 Pol(evalndloopbbin) = 2 3.26/1.65 3.26/1.65 Pol(evalndloopreturnin) = 1 3.26/1.65 3.26/1.65 Pol(evalndloopstop) = 0 3.26/1.65 3.26/1.65 Pol(koat_start) = 2 3.26/1.65 3.26/1.65 orients all transitions weakly and the transitions 3.26/1.65 3.26/1.65 evalndloopreturnin(ar_0) -> Com_1(evalndloopstop(ar_0)) 3.26/1.65 3.26/1.65 evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= 10 ] 3.26/1.65 3.26/1.65 evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= ar_0 + 3 ] 3.26/1.65 3.26/1.65 evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ ar_0 >= b ] 3.26/1.65 3.26/1.65 strictly and produces the following problem: 3.26/1.65 3.26/1.65 3: T: 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 1) evalndloopstart(ar_0) -> Com_1(evalndloopentryin(ar_0)) 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 1) evalndloopentryin(ar_0) -> Com_1(evalndloopbbin(0)) 3.26/1.65 3.26/1.65 (Comp: ?, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopbbin(b)) [ ar_0 + 2 >= b /\ b >= ar_0 + 1 /\ 9 >= b ] 3.26/1.65 3.26/1.65 (Comp: 2, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= ar_0 + 3 ] 3.26/1.65 3.26/1.65 (Comp: 2, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ ar_0 >= b ] 3.26/1.65 3.26/1.65 (Comp: 2, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= 10 ] 3.26/1.65 3.26/1.65 (Comp: 2, Cost: 1) evalndloopreturnin(ar_0) -> Com_1(evalndloopstop(ar_0)) 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 0) koat_start(ar_0) -> Com_1(evalndloopstart(ar_0)) [ 0 <= 0 ] 3.26/1.65 3.26/1.65 start location: koat_start 3.26/1.65 3.26/1.65 leaf cost: 0 3.26/1.65 3.26/1.65 3.26/1.65 3.26/1.65 A polynomial rank function with 3.26/1.65 3.26/1.65 Pol(evalndloopstart) = 9 3.26/1.65 3.26/1.65 Pol(evalndloopentryin) = 9 3.26/1.65 3.26/1.65 Pol(evalndloopbbin) = -V_1 + 9 3.26/1.65 3.26/1.65 Pol(evalndloopreturnin) = -V_1 3.26/1.65 3.26/1.65 Pol(evalndloopstop) = -V_1 3.26/1.65 3.26/1.65 Pol(koat_start) = 9 3.26/1.65 3.26/1.65 orients all transitions weakly and the transition 3.26/1.65 3.26/1.65 evalndloopbbin(ar_0) -> Com_1(evalndloopbbin(b)) [ ar_0 + 2 >= b /\ b >= ar_0 + 1 /\ 9 >= b ] 3.26/1.65 3.26/1.65 strictly and produces the following problem: 3.26/1.65 3.26/1.65 4: T: 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 1) evalndloopstart(ar_0) -> Com_1(evalndloopentryin(ar_0)) 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 1) evalndloopentryin(ar_0) -> Com_1(evalndloopbbin(0)) 3.26/1.65 3.26/1.65 (Comp: 9, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopbbin(b)) [ ar_0 + 2 >= b /\ b >= ar_0 + 1 /\ 9 >= b ] 3.26/1.65 3.26/1.65 (Comp: 2, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= ar_0 + 3 ] 3.26/1.65 3.26/1.65 (Comp: 2, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ ar_0 >= b ] 3.26/1.65 3.26/1.65 (Comp: 2, Cost: 1) evalndloopbbin(ar_0) -> Com_1(evalndloopreturnin(ar_0)) [ b >= 10 ] 3.26/1.65 3.26/1.65 (Comp: 2, Cost: 1) evalndloopreturnin(ar_0) -> Com_1(evalndloopstop(ar_0)) 3.26/1.65 3.26/1.65 (Comp: 1, Cost: 0) koat_start(ar_0) -> Com_1(evalndloopstart(ar_0)) [ 0 <= 0 ] 3.26/1.65 3.26/1.65 start location: koat_start 3.26/1.65 3.26/1.65 leaf cost: 0 3.26/1.65 3.26/1.65 3.26/1.65 3.26/1.65 Complexity upper bound 19 3.26/1.65 3.26/1.65 3.26/1.65 3.26/1.65 Time: 0.060 sec (SMT: 0.056 sec) 3.26/1.65 3.26/1.65 3.26/1.65 ---------------------------------------- 3.26/1.65 3.26/1.65 (2) 3.26/1.65 BOUNDS(1, 1) 3.26/1.66 EOF