4.10/2.07	WORST_CASE(Omega(n^2), O(n^2))
4.10/2.08	proof of /export/starexec/sandbox/benchmark/theBenchmark.koat
4.10/2.08	# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty
4.10/2.08	
4.10/2.08	
4.10/2.08	The runtime complexity of the given CpxIntTrs could be proven to be BOUNDS(n^2, max(1, 3 + 2 * Arg_0) + nat(3 * Arg_0) + nat(Arg_0 * max(3 * Arg_0, -3) + max(3 * Arg_0, -3))).
4.10/2.08	
4.10/2.08	(0) CpxIntTrs
4.10/2.08	(1) Koat2 Proof [FINISHED, 255 ms]
4.10/2.08	(2) BOUNDS(1, max(1, 3 + 2 * Arg_0) + nat(3 * Arg_0) + nat(Arg_0 * max(3 * Arg_0, -3) + max(3 * Arg_0, -3)))
4.10/2.08	(3) Loat Proof [FINISHED, 426 ms]
4.10/2.08	(4) BOUNDS(n^2, INF)
4.10/2.08	
4.10/2.08	
4.10/2.08	----------------------------------------
4.10/2.08	
4.10/2.08	(0)
4.10/2.08	Obligation:
4.10/2.08	Complexity Int TRS consisting of the following rules:
4.10/2.08	eval1(A, B) -> Com_1(eval2(A, 0)) :|: A >= 0
4.10/2.08	eval2(A, B) -> Com_1(eval2(A, B + 1)) :|: A >= 1 + B
4.10/2.08	eval2(A, B) -> Com_1(eval1(A - 1, B)) :|: B >= A
4.10/2.08	start(A, B) -> Com_1(eval1(A, B)) :|: TRUE
4.10/2.08	
4.10/2.08	The start-symbols are:[start_2]
4.10/2.08	
4.10/2.08	
4.10/2.08	----------------------------------------
4.10/2.08	
4.10/2.08	(1) Koat2 Proof (FINISHED)
4.10/2.08	YES( ?, 1+2*max([0, 1+Arg_0])+max([0, 3*Arg_0])+max([0, (1+Arg_0)*max([-3, 3*Arg_0])]) {O(n^2)})
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Initial Complexity Problem:
4.10/2.08	
4.10/2.08	  Start:  start  
4.10/2.08	
4.10/2.08	  Program_Vars:  Arg_0, Arg_1  
4.10/2.08	
4.10/2.08	  Temp_Vars:    
4.10/2.08	
4.10/2.08	  Locations:  eval1, eval2, start  
4.10/2.08	
4.10/2.08	  Transitions:
4.10/2.08	
4.10/2.08	  eval1(Arg_0,Arg_1) -> eval2(Arg_0,0):|:0 <= Arg_0
4.10/2.08	
4.10/2.08	  eval2(Arg_0,Arg_1) -> eval1(Arg_0-1,Arg_1):|:Arg_1 <= Arg_0 && 0 <= Arg_1 && 0 <= Arg_0+Arg_1 && 0 <= Arg_0 && Arg_0 <= Arg_1
4.10/2.08	
4.10/2.08	  eval2(Arg_0,Arg_1) -> eval2(Arg_0,Arg_1+1):|:Arg_1 <= Arg_0 && 0 <= Arg_1 && 0 <= Arg_0+Arg_1 && 0 <= Arg_0 && 1+Arg_1 <= Arg_0
4.10/2.08	
4.10/2.08	  start(Arg_0,Arg_1) -> eval1(Arg_0,Arg_1):|:  
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Timebounds: 
4.10/2.08	
4.10/2.08	  Overall timebound: 1+2*max([0, 1+Arg_0])+max([0, 3*Arg_0])+max([0, (1+Arg_0)*max([-3, 3*Arg_0])]) {O(n^2)}
4.10/2.08	
4.10/2.08	  0: eval1->eval2: max([0, 1+Arg_0]) {O(n)}
4.10/2.08	
4.10/2.08	  1: eval2->eval2: max([0, 3*Arg_0])+max([0, (1+Arg_0)*max([-3, 3*Arg_0])]) {O(n^2)}
4.10/2.08	
4.10/2.08	  2: eval2->eval1: max([0, 1+Arg_0]) {O(n)}
4.10/2.08	
4.10/2.08	  3: start->eval1: 1 {O(1)}
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Costbounds:
4.10/2.08	
4.10/2.08	  Overall costbound: 1+2*max([0, 1+Arg_0])+max([0, 3*Arg_0])+max([0, (1+Arg_0)*max([-3, 3*Arg_0])]) {O(n^2)}
4.10/2.08	
4.10/2.08	  0: eval1->eval2: max([0, 1+Arg_0]) {O(n)}
4.10/2.08	
4.10/2.08	  1: eval2->eval2: max([0, 3*Arg_0])+max([0, (1+Arg_0)*max([-3, 3*Arg_0])]) {O(n^2)}
4.10/2.08	
4.10/2.08	  2: eval2->eval1: max([0, 1+Arg_0]) {O(n)}
4.10/2.08	
4.10/2.08	  3: start->eval1: 1 {O(1)}
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Sizebounds:
4.10/2.08	
4.10/2.08	`Lower:
4.10/2.08	
4.10/2.08	  0: eval1->eval2, Arg_0: 0 {O(1)}
4.10/2.08	
4.10/2.08	  0: eval1->eval2, Arg_1: 0 {O(1)}
4.10/2.08	
4.10/2.08	  1: eval2->eval2, Arg_0: 1 {O(1)}
4.10/2.08	
4.10/2.08	  1: eval2->eval2, Arg_1: 1 {O(1)}
4.10/2.08	
4.10/2.08	  2: eval2->eval1, Arg_0: -1 {O(1)}
4.10/2.08	
4.10/2.08	  2: eval2->eval1, Arg_1: 0 {O(1)}
4.10/2.08	
4.10/2.08	  3: start->eval1, Arg_0: Arg_0 {O(n)}
4.10/2.08	
4.10/2.08	  3: start->eval1, Arg_1: Arg_1 {O(n)}
4.10/2.08	
4.10/2.08	`Upper:
4.10/2.08	
4.10/2.08	  0: eval1->eval2, Arg_0: Arg_0 {O(n)}
4.10/2.08	
4.10/2.08	  0: eval1->eval2, Arg_1: 0 {O(1)}
4.10/2.08	
4.10/2.08	  1: eval2->eval2, Arg_0: Arg_0 {O(n)}
4.10/2.08	
4.10/2.08	  1: eval2->eval2, Arg_1: max([0, 3*Arg_0])+max([0, (1+Arg_0)*max([-3, 3*Arg_0])]) {O(n^2)}
4.10/2.08	
4.10/2.08	  2: eval2->eval1, Arg_0: Arg_0 {O(n)}
4.10/2.08	
4.10/2.08	  2: eval2->eval1, Arg_1: max([0, max([0, 3*Arg_0])+max([0, (1+Arg_0)*max([-3, 3*Arg_0])])]) {O(n^2)}
4.10/2.08	
4.10/2.08	  3: start->eval1, Arg_0: Arg_0 {O(n)}
4.10/2.08	
4.10/2.08	  3: start->eval1, Arg_1: Arg_1 {O(n)}
4.10/2.08	
4.10/2.08	
4.10/2.08	----------------------------------------
4.10/2.08	
4.10/2.08	(2)
4.10/2.08	BOUNDS(1, max(1, 3 + 2 * Arg_0) + nat(3 * Arg_0) + nat(Arg_0 * max(3 * Arg_0, -3) + max(3 * Arg_0, -3)))
4.10/2.08	
4.10/2.08	----------------------------------------
4.10/2.08	
4.10/2.08	(3) Loat Proof (FINISHED)
4.10/2.08	
4.10/2.08	
4.10/2.08	### Pre-processing the ITS problem ###
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Initial linear ITS problem
4.10/2.08	
4.10/2.08	   Start location: start
4.10/2.08	
4.10/2.08	      0: eval1 -> eval2 : B'=0, [ A>=0 ], cost: 1
4.10/2.08	
4.10/2.08	      1: eval2 -> eval2 : B'=1+B, [ A>=1+B ], cost: 1
4.10/2.08	
4.10/2.08	      2: eval2 -> eval1 : A'=-1+A, [ B>=A ], cost: 1
4.10/2.08	
4.10/2.08	      3: start -> eval1 : [], cost: 1
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	### Simplification by acceleration and chaining ###
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Accelerating simple loops of location 1.
4.10/2.08	
4.10/2.08	   Accelerating the following rules:
4.10/2.08	
4.10/2.08	      1: eval2 -> eval2 : B'=1+B, [ A>=1+B ], cost: 1
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	   Accelerated rule 1 with metering function A-B, yielding the new rule 4.
4.10/2.08	
4.10/2.08	   Removing the simple loops: 1.
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Accelerated all simple loops using metering functions (where possible):
4.10/2.08	
4.10/2.08	   Start location: start
4.10/2.08	
4.10/2.08	      0: eval1 -> eval2 : B'=0, [ A>=0 ], cost: 1
4.10/2.08	
4.10/2.08	      2: eval2 -> eval1 : A'=-1+A, [ B>=A ], cost: 1
4.10/2.08	
4.10/2.08	      4: eval2 -> eval2 : B'=A, [ A>=1+B ], cost: A-B
4.10/2.08	
4.10/2.08	      3: start -> eval1 : [], cost: 1
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Chained accelerated rules (with incoming rules):
4.10/2.08	
4.10/2.08	   Start location: start
4.10/2.08	
4.10/2.08	      0: eval1 -> eval2 : B'=0, [ A>=0 ], cost: 1
4.10/2.08	
4.10/2.08	      5: eval1 -> eval2 : B'=A, [ A>=1 ], cost: 1+A
4.10/2.08	
4.10/2.08	      2: eval2 -> eval1 : A'=-1+A, [ B>=A ], cost: 1
4.10/2.08	
4.10/2.08	      3: start -> eval1 : [], cost: 1
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Eliminated locations (on tree-shaped paths):
4.10/2.08	
4.10/2.08	   Start location: start
4.10/2.08	
4.10/2.08	      6: eval1 -> eval1 : A'=-1+A, B'=0, [ A>=0 && 0>=A ], cost: 2
4.10/2.08	
4.10/2.08	      7: eval1 -> eval1 : A'=-1+A, B'=A, [ A>=1 ], cost: 2+A
4.10/2.08	
4.10/2.08	      3: start -> eval1 : [], cost: 1
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Accelerating simple loops of location 0.
4.10/2.08	
4.10/2.08	   Simplified some of the simple loops (and removed duplicate rules).
4.10/2.08	
4.10/2.08	   Accelerating the following rules:
4.10/2.08	
4.10/2.08	      6: eval1 -> eval1 : A'=-1+A, B'=0, [ -A==0 ], cost: 2
4.10/2.08	
4.10/2.08	      7: eval1 -> eval1 : A'=-1+A, B'=A, [ A>=1 ], cost: 2+A
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	   Accelerated rule 6 with metering function 1+A, yielding the new rule 8.
4.10/2.08	
4.10/2.08	   Accelerated rule 7 with metering function A, yielding the new rule 9.
4.10/2.08	
4.10/2.08	   Removing the simple loops: 6 7.
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Accelerated all simple loops using metering functions (where possible):
4.10/2.08	
4.10/2.08	   Start location: start
4.10/2.08	
4.10/2.08	      8: eval1 -> eval1 : A'=-1, B'=0, [ -A==0 ], cost: 2+2*A
4.10/2.08	
4.10/2.08	      9: eval1 -> eval1 : A'=0, B'=1, [ A>=1 ], cost: 5/2*A+1/2*A^2
4.10/2.08	
4.10/2.08	      3: start -> eval1 : [], cost: 1
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Chained accelerated rules (with incoming rules):
4.10/2.08	
4.10/2.08	   Start location: start
4.10/2.08	
4.10/2.08	      3: start -> eval1 : [], cost: 1
4.10/2.08	
4.10/2.08	     10: start -> eval1 : A'=-1, B'=0, [ -A==0 ], cost: 3+2*A
4.10/2.08	
4.10/2.08	     11: start -> eval1 : A'=0, B'=1, [ A>=1 ], cost: 1+5/2*A+1/2*A^2
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Removed unreachable locations (and leaf rules with constant cost):
4.10/2.08	
4.10/2.08	   Start location: start
4.10/2.08	
4.10/2.08	     10: start -> eval1 : A'=-1, B'=0, [ -A==0 ], cost: 3+2*A
4.10/2.08	
4.10/2.08	     11: start -> eval1 : A'=0, B'=1, [ A>=1 ], cost: 1+5/2*A+1/2*A^2
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	### Computing asymptotic complexity ###
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Fully simplified ITS problem
4.10/2.08	
4.10/2.08	   Start location: start
4.10/2.08	
4.10/2.08	     10: start -> eval1 : A'=-1, B'=0, [ -A==0 ], cost: 3+2*A
4.10/2.08	
4.10/2.08	     11: start -> eval1 : A'=0, B'=1, [ A>=1 ], cost: 1+5/2*A+1/2*A^2
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Computing asymptotic complexity for rule 10
4.10/2.08	
4.10/2.08	   Could not solve the limit problem.
4.10/2.08	
4.10/2.08	   Resulting cost 0 has complexity: Unknown
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Computing asymptotic complexity for rule 11
4.10/2.08	
4.10/2.08	   Solved the limit problem by the following transformations:
4.10/2.08	
4.10/2.08	      Created initial limit problem:
4.10/2.08	
4.10/2.08	      1+5/2*A+1/2*A^2 (+), A (+/+!) [not solved]
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	      removing all constraints (solved by SMT)
4.10/2.08	
4.10/2.08	      resulting limit problem: [solved]
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	      applying transformation rule (C) using substitution {A==n}
4.10/2.08	
4.10/2.08	      resulting limit problem:
4.10/2.08	
4.10/2.08	      [solved]
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	   Solution:
4.10/2.08	
4.10/2.08	      A / n
4.10/2.08	
4.10/2.08	   Resulting cost 1+1/2*n^2+5/2*n has complexity: Poly(n^2)
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Found new complexity Poly(n^2).
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	Obtained the following overall complexity (w.r.t. the length of the input n):
4.10/2.08	
4.10/2.08	   Complexity:  Poly(n^2)
4.10/2.08	
4.10/2.08	   Cpx degree:  2
4.10/2.08	
4.10/2.08	   Solved cost: 1+1/2*n^2+5/2*n
4.10/2.08	
4.10/2.08	   Rule cost:   1+5/2*A+1/2*A^2
4.10/2.08	
4.10/2.08	   Rule guard:  [ A>=1 ]
4.10/2.08	
4.10/2.08	
4.10/2.08	
4.10/2.08	WORST_CASE(Omega(n^2),?)
4.10/2.08	
4.10/2.08	
4.10/2.08	----------------------------------------
4.10/2.08	
4.10/2.08	(4)
4.10/2.08	BOUNDS(n^2, INF)
4.16/2.11	EOF